Chapter 2: Problem 29
A jetliner, traveling northward, is landing with a speed of \(69 \mathrm{m} / \mathrm{s}\). Once the jet touches down, it has \(750 \mathrm{m}\) of runway in which to reduce its speed to \(6.1 \mathrm{m} / \mathrm{s} .\) Compute the average acceleration (magnitude and direction) of the plane during landing.
Short Answer
Step by step solution
Identify Given Values
Use the Kinematic Equation
Solve for Acceleration
Calculate the Acceleration
Determine Direction and Magnitude
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
kinematic equation
The particular kinematic equation applied here is: \[ v_f^2 = v_i^2 + 2ad \] This formula is instrumental in calculating one of these variables when the others are known. It allows us to solve for the plane's average acceleration as it lands by rearranging the equation to isolate acceleration \(a\): \[ a = \frac{v_f^2 - v_i^2}{2d} \] Understanding how these equations work lays the foundation for solving many problems related to motion, including those involving varying speeds and forces.
initial and final velocities
These velocities give us insights into how fast the plane travels initially and how much it must decrease its speed to safely and smoothly land within the given runway distance. The change between these velocities helps us calculate the acceleration needed during landing using the kinematic equations.
In physics, such values are crucial for determining how external forces, such as thrust or drag, affect an object's motion.
distance traveled
The distance component in the kinematic equation \( v_f^2 = v_i^2 + 2ad \) highlights how these 750 meters are crucial in solving for acceleration. It’s the runway’s physical length that allows engineers to determine how quickly the speed must change.
Problems involving distance emphasize the importance of understanding environmental constraints and how they impact a moving object's kinematics.
jetliner landing
When a jetliner lands, reducing speed efficiently within the available space is vital to avoid overshooting the runway. By calculating the average acceleration, in this case \( -3.15 \, \text{m/s}^2 \), we gain insight into the necessary braking force. The negative acceleration indicates deceleration, changing the velocity's direction from northward to effectively slowing the plane southward.
It's these calculated manipulations of accelerative forces that enable safe landings, proving the practical application of motion equations.