/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Two motorcycles are traveling du... [FREE SOLUTION] | 91Ó°ÊÓ

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Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this foursecond interval, cycle A has an average acceleration of \(2.0 \mathrm{m} / \mathrm{s}^{2}\) due east, while cycle B has an average acceleration of \(4.0 \mathrm{m} / \mathrm{s}^{2}\) due east. By how much did the speeds differ at the beginning of the four-second interval, and which motorcycle was moving faster?.

Short Answer

Expert verified
Motorcycle B was initially faster by 8 m/s.

Step by step solution

01

Understand the Problem

We are given two motorcycles, A and B, each accelerating at different rates over a time period of 4 seconds until they reach the same velocity. We need to find the initial velocity difference and which motorcycle was initially faster.
02

Define the Variables

Let the initial velocity of motorcycle A be \(v_{A0}\), and that of motorcycle B be \(v_{B0}\). The final velocity for both motorcycles after 4 seconds is the same, say \(v_f\). The accelerations are given as \(a_A = 2.0 \, \mathrm{m/s^2}\) and \(a_B = 4.0 \, \mathrm{m/s^2}\), and the time interval is \(t = 4 \, \mathrm{s}\).
03

Use the Kinematic Equation

Use the equation for final velocity: \(v_f = v_0 + a \cdot t\). For motorcycle A, the equation is \(v_f = v_{A0} + 2.0 \times 4\). For motorcycle B, the equation is \(v_f = v_{B0} + 4.0 \times 4\).
04

Set the Equations Equal

Since both motorcycles have the same final velocity \(v_f\), equate the final velocities from Step 3:\(v_{A0} + 8 = v_{B0} + 16\).
05

Solve for the Initial Velocity Difference

Rearrange the equation from Step 4 to solve for the difference in initial velocities:\(v_{B0} - v_{A0} = 8\). This shows that Motorcycle B was initially faster by 8 m/s.
06

Analyze Initial Velocities

Since \(v_{B0} - v_{A0} = 8\) means that \(v_{B0}\) is greater than \(v_{A0}\), it indicates Motorcycle B was initially moving faster than Motorcycle A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Acceleration
In kinematics, average acceleration is an important concept that helps us understand how quickly an object speeds up or slows down over a period of time. It is defined as the change in velocity divided by the time over which the change occurs. Mathematically, it can be expressed as:\[\text{Average Acceleration} = \frac{\Delta v}{\Delta t}\]Where \(\Delta v\) is the change in velocity and \(\Delta t\) is the time interval. Average acceleration gives us a good idea about the rate of change of velocity irrespective of the specific path taken by the object. In our exercise, motorcycle A experiences an average acceleration of 2.0 m/s², and motorcycle B experiences a higher acceleration of 4.0 m/s². Knowing their accelerations helps us calculate how their velocities change over the given time period, leading to conclusions about their initial speeds.
Initial Velocity
The concept of initial velocity refers to the speed and direction that an object has before any forces or accelerations act upon it. It's the starting point for calculating how an object's motion will change due to acceleration. In calculations, we often use \(v_0\) to represent initial velocity.In our specific problem, we need to determine the initial velocities of both motorcycles A and B. These initial velocities, denoted as \(v_{A0}\) and \(v_{B0}\), respectively, are crucial for solving kinematic problems as they set up the initial conditions for any motion equations we use thereafter. In the exercise, these velocities are not directly given, but they are part of the variables we need to solve for in order to find the velocity difference.
Final Velocity
Final velocity is the speed and direction of an object at the end of a period of acceleration. In kinematics, it's calculated using the initial velocity, acceleration, and time using the formula:\[ v_f = v_0 + a \cdot t \]In the exercise with the motorcycles, both have the same final velocity after 4 seconds, even though they had different rates of acceleration. Knowing that both motorcycles reach the same final velocity is key to setting up our equations and understanding the changes in their speeds over time.This equality in final velocities, despite different initial speeds and accelerations, helps us locate and solve for the unknowns in the system of equations based on the given data.
Velocity Difference
Understanding the difference in velocities, particularly initial velocities, is crucial for solving many kinematics problems. The velocity difference indicates how much faster or slower one object is compared to another. It is calculated as the difference between two velocities, often represented as:\[ \Delta v = v_{B0} - v_{A0} \]In our exercise, determining \(\Delta v\) was essential to identifying which motorcycle started off faster. From the problem's solution steps, we see that initially, motorcycle B was faster than motorcycle A by 8 m/s as \(v_{B0} - v_{A0} = 8\). This comparison of initial velocities plays a pivotal role in many real-world applications, such as in traffic analysis and sports science, where predicting outcomes based on initial conditions is crucial.

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Most popular questions from this chapter

An 18 -year-old runner can complete a \(10.0-\mathrm{km}\) course with an average speed of \(4.39 \mathrm{m} / \mathrm{s} .\) A 50 -year-old runner can cover the same distance with an average speed of \(4.27 \mathrm{m} / \mathrm{s} .\) How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?

A ball is thrown straight upward. At \(4.00 \mathrm{m}\) above its launch point, the ball's speed is one-half its launch speed. What maximum height above its launch point does the ball attain?

For each of the three pairs of positions listed in the following table, determine the magnitude and direction (positive or negative) of the displacement. $$\begin{array}{lcc} & \text { Initial position } x_{0} & \text { Final position } x \\\\\hline \text { (a) } & +2.0 \mathrm{m} & +6.0 \mathrm{m} \\\\\hline \text { (b) } & +6.0 \mathrm{m} & +2.0 \mathrm{m} \\\\\hline \text { (c) } & -3.0 \mathrm{m} & +7.0 \mathrm{m} \\\\\hline\end{array}$$

A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is \(6.0 \mathrm{m} / \mathrm{s}^{2}\), after \(4.0 \mathrm{s}\) he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of \(70.0 \mathrm{m} / \mathrm{s}\) overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch the other car?

The three-toed sloth is the slowest-moving land mammal. On the ground, the sloth moves at an average speed of \(0.037 \mathrm{m} / \mathrm{s},\) considerably slower than the giant tortoise, which walks at \(0.076 \mathrm{m} / \mathrm{s}\). After 12 minutes of walking, how much further would the tortoise have gone relative to the sloth?

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