/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Two point charges are fixed on t... [FREE SOLUTION] | 91Ó°ÊÓ

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Two point charges are fixed on the \(y\) axis: a negative point charge \(q_{1}=-25 \mu \mathrm{C}\) at \(y_{1}=+0.22 \mathrm{m}\) and a positive point charge \(q_{2}\) at \(y_{2}=+0.34 \mathrm{m}\) A third point charge \(q=+8.4 \mu \mathrm{C}\) is fixed at the origin. The net electrostatic force exerted on the charge \(q\) by the other two charges has a magnitude of \(27 \mathrm{N}\) and points in the \(+y\) direction. Determine the magnitude of \(q_{2}\)

Short Answer

Expert verified
The magnitude of \( q_2 \) is approximately 19.5 \( \mu \mathrm{C} \).

Step by step solution

01

Understanding the Forces

The electrostatic force between two point charges is given by Coulomb's law: \[ F = k \frac{|q_1 q_2|}{r^2} \]where \( F \) is the magnitude of the force between them, \( k \) is Coulomb's constant \( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \), \( q_1 \) and \( q_2 \) are the amounts of charge, and \( r \) is the distance between the charges. We have two forces to consider: \( F_{1} \) from \( q_1 \) and \( F_{2} \) from \( q_2 \). Our goal is to find the value of \( q_2 \).
02

Calculate Distance Between Charges

Since \( q \) is at the origin \((0, 0)\), the distances to \( q_1 \) and \( q_2 \) are simply their respective \( y \)-coordinates. So, \[ r_1 = 0.22 \, \text{m} \] and \[ r_2 = 0.34 \, \text{m} \].
03

Calculate Force from Charge q1

Using Coulomb's law for \( q_1 \):\[ F_1 = k \frac{|q q_1|}{r_1^2} \]Substituting the values, \ q = 8.4 \, \mu\text{C}, \, q_1 = -25 \, \mu\text{C}, \, r_1 = 0.22 \, \text{m}\\[ F_1 = 8.99 \times 10^9 \frac{8.4 \times 10^{-6} \times 25 \times 10^{-6}}{(0.22)^2} \approx -39.5 \, \text{N} \] The negative sign indicates that the force is in the \(-y\) direction.
04

Set Up Equation for Net Force

Since the net force on \( q \) is given as \( 27 \, \text{N} \) in the \(+y\) direction, the equation combining the forces is:\[ F_2 - F_1 = 27 \, \text{N} \] where \( F_2 \) needs to counteract and exceed \( F_1 \), as \( F_1 \) is in the \(-y\) direction.
05

Solve for Force from Charge q2

Rearrange to find \( F_2 \):\[ F_2 = 27 \, \text{N} + F_1 \approx 27 \, \text{N} + 39.5 \, \text{N} \approx 66.5 \, \text{N} \].
06

Calculate Charge q2

Now use Coulomb's law for \( q_2 \) to find its magnitude:\[ F_2 = k \frac{|q q_2|}{r_2^2} \]Substitute the values and solve for \( q_2 \):\[ 66.5 = 8.99 \times 10^9 \frac{8.4 \times 10^{-6} \times q_2}{(0.34)^2} \]\[ q_2 = \frac{66.5 \times 0.34^2}{8.99 \times 10^9 \times 8.4 \times 10^{-6}} \approx 19.5 \, \mu\text{C} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point Charges
In the context of electrostatics, a point charge refers to an idealized model of a particle that has an electric charge and negligible size. This simplification allows us to focus on the effects of the charge itself without worrying about the complexities that come with a more spread-out distribution. Point charges are crucial in calculations since they help establish an understanding of how charges interact with one another based on their positions.

In the exercise provided, we deal with three point charges: a negative charge, a positive charge, and another positive charge at the origin. Each of these can be treated as a distinct point charge because their sizes are not factors in our computations. By considering each as a point, we can easily apply formulas such as Coulomb's Law to determine the forces between them.
  • Point charges are theoretical but useful in simplifying real-world systems.
  • They allow the application of mathematical models like Coulomb's Law.
  • For practical exercises, we assume that charges interact only through their center points.
Electrostatic Force
Electrostatic force is the push or pull that arises from the interaction of charged particles due to their electric charges. This is a fundamental force in nature and is described by Coulomb's Law, which quantifies the magnitude of the electric force between two point charges. According to Coulomb's Law, the force between two charges depends on the product of the charges and inversely on the square of the distance between them:

\[ F = k \frac{|q_1 q_2|}{r^2} \]where:
  • \(F\) is the electrostatic force between the charges.
  • \(k\) is Coulomb's constant, approximately \(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\).
  • \(q_1\) and \(q_2\) are the magnitudes of the two charges.
  • \(r\) is the distance between the charges.
In the given problem, forces between point charges are calculated to determine how they influence each other. The negative sign of force, like in Step 3, indicates direction — opposite charges attract, and like charges repel. Understanding electrostatic force helps predict the outcomes of such interactions, forming the basis for computations like those required in this exercise.
Net Force
When multiple forces act on a charge, the net force is the vector sum of these forces. It determines the overall motion of a charged particle. This concept is significant when several electrostatic forces are acting in various directions and must be considered together to find the resultant force.

For our exercise, the net force acting on the charge located at the origin can be determined through the combination of forces from the point charges situated along the y-axis:
  • Net force accounts for both magnitude and direction.
  • In this exercise, a net force, \(27 \, \text{N}\), is specified in the \(+y\) direction, necessitating computation to find balancing forces.
  • We need to consider the contribution of each charge to the net force, using their calculations through Coulomb's Law to solve for unknowns, like the charge \(q_2\).
The electrostatic forces from \(q_1\) and \(q_2\) are summed, considering their directions, to equate to the known net force, allowing us to find the missing charge value efficiently.

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Most popular questions from this chapter

Four identical metal spheres have charges of \(q_{\Lambda}=-8.0 \mu \mathrm{C}, q_{\mathrm{B}}=\) \(-2.0 \mu \mathrm{C}, q_{\mathrm{c}}=+5.0 \mu \mathrm{C},\) and \(q_{\mathrm{D}}=+12.0 \mu \mathrm{C}\) (a) Two of the spheres are brought together so they touch, and then they are separated. Which spheres are they, if the final charge on each one is \(+5.0 \mu \mathrm{C} ?\) (b) In a similar manner, which three spheres are brought together and then separated, if the final charge on each of the three is \(+3.0 \mu \mathrm{C} ?\) (c) The final charge on each of the three separated spheres in part (b) is \(+3.0 \mu \mathrm{C} .\) How many electrons would have to be added to one of these spheres to make it electrically neutral?

You and your team are designing a device that can be used to position a small, plastic object in the region between the plates of a parallel-plate capacitor. A small plastic sphere of mass \(m=1.20 \times 10^{-2} \mathrm{kg}\) carries a charge \(q=+0.200 \mu \mathrm{C}\) and hangs vertically (along the \(y\) direction) from a massless, insulating thread (length \(l=10.0 \mathrm{cm})\) between two vertical capacitor plates. When there is no electric field, the object resides at the midpoint between the plates (at \(x=0\) ). However, when there is a field between plates (in the \(\pm x\) direction) the object moves to a new equilibrium position. (a) To what value should you set the field if you want the object to be located at \(x=2.10 \mathrm{cm} ?\) (b) To what value should you set the field if you want the object to be located at \(x=-3.30 \mathrm{cm} ?\)

The drawing shows an equilateral triangle, each side of which has a length of \(2.00 \mathrm{cm}\). Point charges are fixed to each corner, as shown. The \(4.00 \mu \mathrm{C}\) charge experiences a net force due to the charges \(q_{A}\) and \(q_{\mathrm{B}} .\) This net force points vertically downward and has a magnitude of 405 N. Determine the magnitudes and algebraic signs of the charges \(q_{A}\) and \(q_{\mathrm{B}}\)

Four identical metallic objects carry the following charges: +1.6 \(+6.2,-4.8,\) and \(-9.4 \mu \mathrm{C} .\) The objects are brought simultaneously into \(\mathrm{con}-\) tact, so that each touches the others. Then they are separated. (a) What is the final charge on each object? (b) How many electrons (or protons) make up the final charge on each object?

A plate carries a charge of \(-3.0 \mu \mathrm{C}\), while a rod carries a charge of \(+2.0 \mu \mathrm{C} .\) How many electrons must be transferred from the plate to the rod, so that both objects have the same charge?

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