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One method for measuring the speed of sound uses standing waves. A cylindrical tube is open at both ends, and one end admits sound from a tuning fork. A movable plunger is inserted into the other end at a distance \(L\) from the end of the tube where the tuning fork is. For a fixed frequency, the plunger is moved until the smallest value of \(L\) is measured that allows a standing wave to be formed. Suppose that the tuning fork produces a \(485-\mathrm{Hz}\) tone, and that the smallest value observed for \(L\) is \(0.264 \mathrm{m} .\) What is the speed of sound in the gas in the tube?

Short Answer

Expert verified
The speed of sound in the gas is approximately 256.08 m/s.

Step by step solution

01

Understanding the Standing Wave Condition

For a tube open at both ends, a standing wave is formed when the length of the tube is an integer multiple of half the wavelength, i.e., \( L = \frac{n\lambda}{2} \), where \( n \) is an integer (1, 2, 3,...). Since the smallest value is given, \( n = 1 \) and \( L = \frac{\lambda}{2} \).
02

Calculating the Wavelength

Convert the relationship \( L = \frac{\lambda}{2} \) into \( \lambda = 2L \) to find the wavelength. Given \( L = 0.264 \text{ m} \), the wavelength \( \lambda = 2 \times 0.264 \text{ m} = 0.528 \text{ m} \).
03

Applying the Speed of Sound Formula

The speed of sound \( v \) in the medium can be calculated using the formula \( v = f \lambda \), where \( f \) is the frequency. Here, \( f = 485 \text{ Hz} \) and \( \lambda = 0.528 \text{ m} \). Thus, \( v = 485 \times 0.528 \text{ m/s} \).
04

Calculating the Speed of Sound

Perform the multiplication to find \( v = 485 \times 0.528 = 256.08 \text{ m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standing Waves
Standing waves are a fascinating phenomenon that occur when two waves of the same frequency and amplitude travel in opposite directions and interfere with each other. This creates a wave where certain points, called nodes, remain stationary, while others, known as antinodes, oscillate with maximum amplitude.
In the context of sound, standing waves are formed in a medium, such as air within a tube, when sound waves reflect back and forth.
For a tube open at both ends, where both ends serve as the locations for antinodes, standing waves are formed when the length of the tube is an integer multiple of half the wavelength.
  • This is because each half-wavelength fits between two consecutive nodes.
  • In calculations, understanding standing waves is crucial because it helps determine the conditions necessary for forming waves that produce resonant frequencies.
Recognizing these resonances allows us to perform experiments, like measuring the speed of sound in a medium.
Cylindrical Tube
A cylindrical tube plays an important role in many acoustic experiments due to its simplicity and efficiency. It essentially acts like a resonant cavity where sound waves can form standing waves.
This type of tube is often used in teaching environments to illustrate principles of wave physics.
The tube is open at both ends, which is significant because it means that both ends will have antinodes when standing waves are formed.
  • The open ends naturally enforce the condition that the air molecules at these points have the greatest freedom to move, creating maximum displacement.
  • This configuration inherently affects the wave patterns that can be sustained within the tube, hence impacting the measurements and calculations of sound properties like frequency and speed.
Conducting sound experiments in a cylindrical tube is a practical way to observe the phenomenon of resonance and standing waves in action.
Tuning Fork Frequency
A tuning fork is a simple yet precise instrument that emits a constant pitch when it vibrates, and is perfect for sound experiments.
In the exercise, the tuning fork produces a frequency of 485 Hz. This frequency, denoted as \( f \), represents the number of vibrations or cycles the wave completes per second.
The consistency of the tuning fork's frequency is essential for accurate experimental results.
  • By using a known frequency, we can easily calculate the speed of sound or other related wave properties.
  • Frequency is a primary component in the formula to find the speed of sound: \( v = f \lambda \), where \( \lambda \) is the wavelength.
Using the tuning fork's steady frequency ensures the validity and reliability of our measurements and calculations.
Wavelength Calculation
Wavelength is the distance between consecutive points of a wave, such as from crest to crest or trough to trough. In sound waves, it represents the physical distance over which the wave's shape repeats.
In the given exercise, we start by using the relationship between the tube length \( L \) and the wavelength \( \lambda \).
For a tube open at both ends, the length \( L \) is half the wavelength, so \( L = \frac{\lambda}{2} \).
Once we find the smallest \( L \) that supports a standing wave, we can determine the wavelength using \( \lambda = 2L \).
  • With \( L = 0.264 \text{ m} \), the wavelength \( \lambda \) is computed as \( 0.528 \text{ m} \).
  • Knowing the wavelength allows us to further calculate other crucial parameters, like the speed of sound, using the accompanying frequency.
Understanding how to accurately determine wavelength is a key step in analyzing sound wave properties within a medium.

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Most popular questions from this chapter

A person hums into the top of a well and finds that standing waves are established at frequencies of \(42,70.0,\) and 98 Hz. The frequency of \(42\) \(\mathrm{Hz}\) is not necessarily the fundamental frequency. The speed of sound is \(343\) \(\mathrm{m} / \mathrm{s} .\) How deep is the well?

Two tubes of gas are identical and are open only at one end. One tube contains neon (Ne) and the other krypton (Kr). Both are monatomic gases, have the same temperature, and may be assumed to be ideal gases. The fundamental frequency of the tube containing neon is 481 Hz. Concepts: (i) For a gas-filled tube open only at one end, the fundamental frequency \((n=1)\) is \(f_{1}=v /(4 L),\) where \(v\) is the speed of sound and \(L\) is the length of the tube. How is the speed related to the properties of the gas? (ii) All of the factors that affect the speed of sound in this problem are the same except for the atomic masses, which are given by 20.180 u for neon, and 83.80 u for krypton. Is the speed of sound in krypton greater than, smaller than, or equal to the speed of sound in neon? Why? (iii) Is the fundamental frequency of the tube containing krypton greater than, less than, or equal to the fundamental frequency of the tube containing neon? Explain. Calculations: What is the fundamental frequency of the tube containing krypton?

A string has a linear density of \(8.5 \times 10^{-3}\) \(\mathrm{kg} / \mathrm{m}\) and is under a tension of \(280\) \(\mathrm{N}\). The string is \(1.8\) \(\mathrm{m}\) long, is fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the (a) speed, (b) wavelength, and (c) frequency of the traveling waves that make up the standing wave.

Two wires, each of length \(1.2\) \(\mathrm{m},\) are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 660 Hz. However, the same frequency of \(660\) \(\mathrm{Hz}\) is the third harmonic on wire \(\mathrm{B}\). Find the speed at which the individual waves travel on each wire.

Review Conceptual Example 5 before attempting this problem. As the drawing shows, the length of a guitar string is \(0.628\) \(\mathrm{m} .\) The frets are numbered for convenience. A performer can play a musical scale on a single string because the spacing between the frets is designed according to the following rule: When the string is pushed against any fret \(j,\) the fundamental frequency of the shortened string is larger by a factor of the twelfth root of two \((\sqrt[12]{2})\) than it is when the string is pushed against the fret \(j-1 .\) Assuming that the tension in the string is the same for any note, find the spacing (a) between fret 1 and fret 0 and (b) between fret 7 and fret \(6 .\)

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