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When Gloria wears her hearing aid, the sound intensity level increases by \(30.0 \mathrm{dB}\). By what factor does the sound intensity increase?

Short Answer

Expert verified
The sound intensity increases by a factor of 1000.

Step by step solution

01

Understanding the Decibel Increase

Decibels measure sound intensity level on a logarithmic scale. An increase of 30 dB signifies a significant change in intensity.
02

Relating Decibels to Intensity

The formula to relate decibel increase to intensity is given by: \[ \Delta \beta = 10 \log_{10}\left(\frac{I}{I_0}\right) \] where \( \Delta \beta = 30 \mathrm{dB} \), and \( \frac{I}{I_0} \) is the factor of intensity increase.
03

Solving for Intensity Increase

We rearrange the formula to solve for the intensity factor:\[ 30 = 10 \log_{10}\left(\frac{I}{I_0}\right) \] \[ 3 = \log_{10}\left(\frac{I}{I_0}\right) \] Exponentiate both sides: \[ 10^3 = \frac{I}{I_0} \] \[ \frac{I}{I_0} = 1000 \]
04

Conclusion

The sound intensity increases by a factor of 1000.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Scale
The decibel (dB) scale is a handy way to measure sound intensity levels, especially because human hearing perceives a vast range of intensities. Instead of using a linear scale where small changes might be undetectable, the decibel scale is logarithmic. This means each step on this scale represents a tenfold change in intensity. In Gloria's case, an increase of 30 dB significantly boosts the sound she hears.
This scale is not absolute but relative, usually comparing the intensity to a reference level. For sound, this reference is typically the quietest sound the average human can hear, known as the threshold of hearing.
  • A 10 dB increase means the sound is ten times more intense.
  • A 20 dB increase means the sound is a hundred times more intense.
  • A 30 dB increase, like Gloria's, means the sound is a thousand times more intense.
Understanding decibels helps in grasping how different sounds relate to each other in terms of intensity.
Logarithmic Scale
A logarithmic scale is crucial for handling quantities that span several orders of magnitude, like sound intensities. Instead of adding to move up the scale, you multiply. This makes it a perfect fit for the decibel system.
On this scale, every 10 dB represents a tenfold increase in intensity. That's why the decibel scale is logarithmic - it can compress big numbers into manageable figures. Logarithmic scales are common in many scientific fields, like geology for measuring earthquakes or chemistry for pH levels.
  • Logarithms convert multiplicative relationships into additive ones.
  • This simplification helps in calculations and comparisons.
  • For instance, knowing that 3 in the logarithmic scale means 1000 times more intensity simplifies understanding the change.
Grasping the idea of logarithmic scale transforms how we perceive and calculate shifts in sound intensity.
Intensity Increase Factor
The intensity increase factor is a way to express how much more intense a sound becomes. This concept directly ties into the decibel scale since it quantifies the change in power from the reference level.
To find the intensity increase factor, you use the relationship of decibel changes and power: \[ \Delta \beta = 10 \log_{10}\left(\frac{I}{I_0}\right) \]For Gloria, a 30 dB increase means: 1. Rearrange the formula to isolate the intensity factor.2. Solve as follows: \[ 30 = 10 \log_{10}\left(\frac{I}{I_0}\right) \]\[ 3 = \log_{10}\left(\frac{I}{I_0}\right) \]Exponentiate: \[ 10^3 = \frac{I}{I_0} \]The result, \( \frac{I}{I_0} = 1000 \), means the sound intensity is a thousand times higher.
  • This calculation captures a big change in sound perception.
  • Each rise in decibels implies a large increase in power.
  • The factor helps explain the vast range of sounds we can hear, from whispers to jet engines.
Recognizing the intensity increase factor helps reason out the substantial effect of small dB changes on perceived loudness.

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Most popular questions from this chapter

A bat emits a sound whose frequency is \(91 \mathrm{kHz}\). The speed of sound in air at \(20.0^{\circ} \mathrm{C}\) is \(343 \mathrm{m} / \mathrm{s} .\) However, the air temperature is \(35^{\circ} \mathrm{C},\) so the speed of sound is not \(343 \mathrm{m} / \mathrm{s} .\) Assume that air behaves like an ideal gas, and find the wavelength of the sound.

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The siren on an ambulance is emitting a sound whose frequency is \(2450 \mathrm{Hz} .\) The speed of sound is \(343 \mathrm{m} / \mathrm{s} .\) (a) If the ambulance is stationary and you (the "observer") are sitting in a parked car, what are the wavelength and the frequency of the sound you hear? (b) Suppose that the ambulance is moving toward you at a speed of \(26.8 \mathrm{m} / \mathrm{s} .\) Determine the wavelength and the frequency of the sound you hear. (c) If the ambulance is moving toward you at a speed of \(26.8 \mathrm{m} / \mathrm{s}\) and you are moving toward it at a speed of \(14.0 \mathrm{m} / \mathrm{s}\) find the wavelength and frequency of the sound you hear.

A steel cable has a cross-sectional area \(2.83 \times 10^{-3} \mathrm{m}^{2}\) and is kept under a tension of \(1.00 \times 10^{4} \mathrm{N}\). The density of steel is \(7860 \mathrm{kg} / \mathrm{m}^{3}\). Note that this value is not the linear density of the cable. At what speed does a transverse wave move along the cable?

Using an intensity of \(1 \times 10^{-12} \mathrm{W} / \mathrm{m}^{2}\) as a reference, the threshold of hearing for an average young person is 0 dB. Person 1 and person \(2,\) who are not average, have thresholds of hearing that are \(\beta_{1}=-8.00 \mathrm{dB}\) and \(\beta_{2}=\) \(+12.0 \mathrm{dB} .\) What is the ratio \(I_{1} / I_{2}\) of the sound intensity \(I_{1}\) when person 1 hears the sound at his own threshold of hearing compared to the sound intensity \(I_{2}\) when person 2 hears the sound at his own threshold of hearing?

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