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Hearing damage may occur when a person is exposed to intensity level at the center of the field is \(60.0 \mathrm{dB}\). When all the people shout togcther, the intensity level increases to 109 dB. Assuming that each person generates the same sound intensity at the center of the field, how many people are at the game?

Short Answer

Expert verified
There are approximately 7943 people at the game.

Step by step solution

01

Understand the Formula for Intensity Levels

The formula to relate intensity levels in decibels (dB) to sound intensity is \( L = 10 \, \log_{10} \left(\frac{I}{I_0}\right) \), where \( L \) is the intensity level in dB, \( I \) is the intensity in watts per square meter, and \( I_0 = 10^{-12} \) W/m² is the reference intensity.
02

Calculate Intensity for a Single Person

Using the formula from Step 1, the intensity level of a single person's sound is given as 60 dB. Substitute \( L = 60 \) to find \( I_1 \): \[ 60 = 10 \, \log_{10} \left(\frac{I_1}{I_0}\right) \]. Solving, we have: \[ I_1 = I_0 \times 10^{6} \].
03

Calculate Total Intensity for All People

The total intensity level when everyone is shouting is 109 dB. Using the same formula, substitute \( L = 109 \) to find the total intensity \( I_t \): \[109 = 10 \, \log_{10} \left(\frac{I_t}{I_0}\right) \]. Solving, we have: \[ I_t = I_0 \times 10^{10.9} \].
04

Set up the Equation to Find Number of People

Assuming each person contributes equally to the total intensity, let \( N \) be the number of people. Then, the total intensity \( I_t \) is \( N \times I_1 \). Substitute the values from Steps 2 and 3: \[ I_0 \times 10^{10.9} = N \times I_0 \times 10^{6} \].
05

Solve for the Number of People

Cancel \( I_0 \) from both sides of the equation: \[ 10^{10.9} = N \times 10^{6} \]. Solve for \( N \) by dividing both sides by \( 10^6 \): \[ N = 10^{10.9 - 6} = 10^{4.9} \]. Calculating, \( N \approx 7943 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibels
Decibels (dB) are used to measure sound intensity levels. This is a logarithmic unit, meaning each increase of 10 dB represents a tenfold increase in intensity. For example, a sound at 60 dB is ten times more intense than a sound at 50 dB. This scale is particularly useful for dealing with the wide range of human hearing.

The decibel scale starts at 0 dB, which is the faintest sound a human ear can detect. Everyday sounds, like conversation, are around 60 dB. When using the formula for sound intensity in decibels:
  • Use the equation: \( L = 10 \times \log_{10} \left( \frac{I}{I_0} \right) \), where \(L\) is the level in dB, \(I\) is the sound intensity, and \(I_0 = 10^{-12} \) W/m².
We use this specific formula because 10 dB is perceived as a doubling of loudness to the human ear.
Intensity Level
Sound intensity level is a measure of the power of sound waves passing through a particular area. It's calculated using the decibel formula, and it's important to understand how this works in practice.

To calculate the intensity level of a sound:
  • Determine the sound intensity (in watts per square meter), and the reference intensity (\(I_0 = 10^{-12}\) W/m²).
  • Use the formula \( L = 10 \times \log_{10} \left( \frac{I}{I_0} \right) \).
For example, at a sports event, one person's voice might have a sound intensity level of 60 dB. If all spectators cheer simultaneously, the intensity level can jump significantly, such as to 109 dB. This increase indicates a massive collective power of sound energy.
Hearing Damage
Prolonged exposure to high intensity levels can cause hearing damage. Human ears can be incredibly sensitive, and sounds above certain thresholds are not only uncomfortable but potentially harmful.

Hearing damage can begin at sounds above 85 dB, and the risk increases rapidly with the rise in dB levels. For example:
  • Normal conversation is around 60 dB and is safe.
  • Lawnmowers and heavy traffic range from 85 dB upwards, risking damage over prolonged exposure.
  • Any sound over 120 dB can be painful and cause immediate harm.
It's vital to limit exposure time or use protective measures like earplugs when in contact with high decibel environments, such as concerts or loud sports events.
Wave Amplitude
Wave amplitude is related to the loudness or intensity of sound. A higher amplitude means a louder sound. It is crucial for understanding why sounds of the same intensity level but different distances can vary in loudness.

The amplitude of a sound wave is the height of the wave and it determines the energy carried by the wave:
  • Greater amplitude results in a louder sound.
  • Smaller amplitude produces a softer sound.
Think of it like throwing a ball – the more energy you use, the higher the ball goes. Similarly, more sound energy means higher amplitude, more intensity, and thus, a louder sound.

While decibels measure the perceived loudness, wave amplitude gives the raw power behind that sound. Understanding both can help you appreciate how sound travels and affects environments, especially in crowded areas like stadiums.

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Most popular questions from this chapter

A car is parked \(20.0 \mathrm{m}\) directly south of a railroad crossing. A train is approaching the crossing from the west, headed directly east at a speed of \(55.0 \mathrm{m} / \mathrm{s}\). The train sounds a short blast of its \(289-\mathrm{Hz}\). horn when it reaches a point \(20.0 \mathrm{m}\) west of the crossing. What frequency does the car's driver hear when the horn blast reaches the car? The speed of sound in air is \(343 \mathrm{m} / \mathrm{s} .\)

From a vantage point very close to the track at a stock car race, you hear the sound emitted by a moving car. You detect a frequency that is 0.86 times as small as the frequency emitted by the car when it is stationary. The speed of sound is \(343 \mathrm{m} / \mathrm{s} .\) What is the speed of the car?

The security alarm on a parked car goes off and produces a frequency of \(960 \mathrm{Hz}\). The speed of sound is \(343 \mathrm{m} / \mathrm{s}\). As you drive toward this parked car, pass it, and drive away, you observe the frequency to change by \(95 \mathrm{Hz}\) Al what speed are you driving?

The tension in a string is \(15 \mathrm{N}\), and its linear density is \(0.85 \mathrm{kg} / \mathrm{m}\). A wave on the string travels toward the \(-x\) direction; it has an amplitude of \(3.6 \mathrm{cm}\) and a frequency of \(12 \mathrm{Hz} .\) What are the (a) speed and (b) wavelength of the wave? (c) Write down a mathematical expression (like Equation 16.3 or 16.4 ) for the wave, substituting numbers for the variables \(A, f,\) and \(\lambda\).

Deep ultrasonic heating is used to promote healing of torn tendons. It is produced by applying ultrasonic sound over the affected area of the body. The sound transducer (generator) is circular with a radius of \(1.8 \mathrm{cm},\) and it produces a sound intensity of \(5.9 \times 10^{3} \mathrm{W} / \mathrm{m}^{2} .\) How much time is required for the transducer to emit 4800 J of sound energy?

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