/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 At a fabrication plant, a hot me... [FREE SOLUTION] | 91Ó°ÊÓ

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At a fabrication plant, a hot metal forging has a mass of \(75 \mathrm{kg}\) and a specific heat capacity of \(430 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right) .\) To harden it, the forging is immersed in \(710 \mathrm{kg}\) of oil that has a temperature of \(32^{\circ} \mathrm{C}\) and a specific heat capacity of \(2700 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right) .\) The final temperature of the oil and forging at thermal equilibrium is \(47^{\circ} \mathrm{C}\). Assuming that heat flows only between the forging and the oil, determine the initial temperature of the forging.

Short Answer

Expert verified
The initial temperature of the forging is approximately 642°C.

Step by step solution

01

Understand the Problem

The problem requires us to find the initial temperature of the forging using the concept of thermal equilibrium. We know the masses, specific heat capacities, and final temperature of both the metal forging and the oil.
02

Apply the Principle of Conservation of Energy

At thermal equilibrium, the heat lost by the forging equals the heat gained by the oil. Thus, we set up the equation for heat transfer: \[ m_{f}c_{f}(T_{i} - T_{f}) = m_{o}c_{o}(T_{f} - T_{o}) \]where:- \( m_{f} = 75 \, \text{kg} \) is the mass of the forging,- \( c_{f} = 430 \, \text{J/(kg°C)} \) is the specific heat capacity of the forging,- \( T_{i} \) is the initial temperature of the forging,- \( T_{f} = 47 \, \text{°C} \) is the final temperature, - \( m_{o} = 710 \, \text{kg} \) is the mass of the oil,- \( c_{o} = 2700 \, \text{J/(kg°C)} \) is the specific heat capacity of the oil,- \( T_{o} = 32 \, \text{°C} \) is the initial temperature of the oil.
03

Substitute Known Values

Substitute the known values into the heat transfer equation:\[ 75 \, \text{kg} \times 430 \, \text{J/(kg°C)} \times (T_{i} - 47 \, \text{°C}) = 710 \, \text{kg} \times 2700 \, \text{J/(kg°C)} \times (47 \, \text{°C} - 32 \, \text{°C}) \]
04

Simplify and Solve the Equation

Simplify the equation:\[ 32250(T_{i} - 47) = 19197000 \]Next, solve for \( T_{i} \):\[ T_{i} - 47 = \frac{19197000}{32250} \] \[T_{i} - 47 \approx 595 \] \[T_{i} \approx 642 \, \text{°C} \]
05

Final Considerations

Check the calculations to ensure there are no mistakes. The negative sign makes sense because the forging was originally hotter and is losing heat to the oil.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
When we talk about specific heat capacity, we’re discussing the amount of heat required to change the temperature of a unit mass of a substance by one degree Celsius. This is a fundamental concept in understanding how different materials absorb and release heat. Specific heat capacity is denoted by the symbol \( c \), and it is expressed in units of \( \text{J/(kg°C)} \).

Different substances have different specific heat capacities, which means they will heat up or cool down at different rates for the same heat energy. For example, in the exercise, we can see that the specific heat capacity of the hot metal forging is \( 430 \, \text{J/(kg°C)} \), whereas the specific heat capacity of the oil is much higher at \( 2700 \, \text{J/(kg°C)} \).
  • This difference in specific heat capacity indicates how quickly each substance can reach thermal equilibrium.
  • It’s a key factor in determining how much the temperature of each substance will change when they exchange heat.
Recognizing these values helps us predict and calculate the heat transfer between different materials when they are combined.
Heat Transfer
Heat transfer is the process by which thermal energy moves from a hotter object to a cooler one. In our scenario, this occurs between the hot metal forging and the cooler oil. The driving force behind this process is temperature difference. The forging, which was initially hotter, transfers heat to the oil so that eventually, both reach the same final temperature, known as thermal equilibrium.

In the context of the exercise, the formula provided helps us to quantify this heat transfer. It’s expressed as:\[ m_{f}c_{f}(T_{i} - T_{f}) = m_{o}c_{o}(T_{f} - T_{o})\]
  • The left side represents the heat lost by the forging, where \( m_f \) is the mass and \( c_f \) is the specific heat capacity.
  • The right side indicates the heat gained by the oil, defined by its mass \( m_o \) and specific heat capacity \( c_o \).
This expression ensures we can systematically solve for the initial temperature of the forging by making the assumption that all the heat lost by the forging is gained by the oil.
Conservation of Energy
The principle of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. In the context of thermal systems, this means the total heat before and after an exchange should remain the same.

In the exercise, the concept is applied by equating the heat lost by the forging to the heat gained by the oil. This direct application of the conservation of energy principle allows us to systematically calculate unknowns in thermal interactions. The equation is evidence of this principle:
  • The initial heat content of the forging is decreased as it transfers energy to the cooler oil.
  • Conversely, the oil gains an equal amount of heat, symbolizing a direct energy swap under an isolated system with no external additions or losses.
Understanding this principle helps tie together concepts of temperature change, specific heat capacity, and mass to ensure all aspects of a closed thermal system are balanced.

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Most popular questions from this chapter

A steel bicycle wheel (without the rubber tire) is rotating freely with an angular speed of \(18.00 \mathrm{rad} / \mathrm{s}\). The temperature of the wheel changes from \(-100.0 \mathrm{to}+300.0^{\circ} \mathrm{C} .\) No net external torque acts on the wheel, and the mass of the spokes is negligible. (a) Does the angular speed increase or decrease as the wheel heats up? Why? (b) What is the angular speed at the higher temperature?

A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 240 Calories ( 1 Calorie \(=4186\) J). What mass of perspiration would one have to lose to get rid of this energy? At body temperature, the latent heat of vaporization of water is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} .\)

A 0.35-kg coffee mug is made from a material that has a specific heat capacity of \(920 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right)\) and contains \(0.25 \mathrm{kg}\) of water. The cup and water are at \(15^{\circ} \mathrm{C}\). To make a cup of coffee, a small electric heater is immersed in the water and brings it to a boil in three minutes. Assume that the cup and water always have the same temperature and determine the minimum power rating of this heater.

If a nonhuman civilization were to develop on Saturn's largest moon, Titan, its scientists might well devise a temperature scale based on the properties of methane, which is much more abundant on the surface than water is. Methane freezes at \(-182.6^{\circ} \mathrm{C}\) on Titan, and boils at \(-155.2^{\circ} \mathrm{C}\) Taking the boiling point of methane as \(100.0^{\circ} \mathrm{M}\) (degrees Methane) and its freezing point as \(0^{\circ} \mathrm{M},\) what temperature on the Methane scale corresponds to the absolute zero point of the Kelvin scale?

The latent heat of vaporization of \(\mathrm{H}_{2} \mathrm{O}\) at body temperature \(\left(37.0^{\circ} \mathrm{C}\right)\) is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} .\) To cool the body of a \(75-\mathrm{kg}\) jogger [average specific heat capacity \(\left.=3500 \mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right)\right]\) by \(1.5 \mathrm{C}^{\circ},\) how many kilograms of water in the form of sweat have to be evaporated?

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