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The fan blades on a jet engine make one thousand revolutions in a time of \(50.0 \mathrm{ms}\). Determine (a) the period (in seconds) and (b) the frequency (in Hz) of the rotational motion. (c) What is the angular frequency of the blades?

Short Answer

Expert verified
(a) Period: 0.00005 s, (b) Frequency: 20000 Hz, (c) Angular frequency: 40000Ï€ rad/s.

Step by step solution

01

Determine the Period (T)

The period \(T\) is the time taken for one complete revolution. To find \(T\), divide the total time \(t = 50.0 \text{ ms} = 0.050 \text{ s}\) by the number of revolutions \(n = 1000\). Thus, \( T = \frac{t}{n} = \frac{0.050 \text{ s}}{1000} = 0.00005 \text{ s}\).
02

Calculate the Frequency (f)

Frequency \(f\) is the number of revolutions per second and is the reciprocal of the period. Therefore, \( f = \frac{1}{T} = \frac{1}{0.00005 \text{ s}} = 20000 \text{ Hz}\).
03

Calculate the Angular Frequency (ω)

Angular frequency \(\omega\) is related to frequency by the equation \(\omega = 2\pi f\). Using \(f = 20000 \text{ Hz}\), \(\omega = 2\pi \times 20000 = 40000\pi \text{ rad/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Period
The period, often represented by the symbol \( T \), is a fundamental concept in the study of rotational motion. It describes the time required for a system to complete one full cycle of motion. In the context of a rotational system, like the fan blades of a jet engine, it indicates the time taken for one complete revolution.
To compute the period, you divide the total time taken by the number of complete cycles or revolutions. In our example, with the jet engine fan blades, the total time is \( 50.0 \) ms, which is equivalent to \( 0.050 \) seconds. With \( 1000 \) revolutions, the period can be calculated using the formula:
\[ T = \frac{t}{n} \]
where:
  • \( t = 0.050 \) seconds (total time)
  • \( n = 1000 \) revolutions (complete cycles)
Using these values in the formula, you find:
\[ T = \frac{0.050 \, \text{s}}{1000} = 0.00005 \, \text{s} \]
This indicates that each blade takes \( 0.00005 \) seconds to complete one full revolution.
Frequency
Frequency in the context of rotational motion is defined as the number of cycles or revolutions per unit of time. It is a measure of how often an event occurs within a particular time frame and is expressed in hertz (Hz), where \( 1 \text{ Hz} = 1 \text{ cycle/second} \).
For rotational systems, there's a simple relationship between frequency \( f \) and period \( T \): They are reciprocals of each other. The formula to find frequency is:
\[ f = \frac{1}{T} \]
From the previous calculation, we know that the period \( T \) is \( 0.00005 \text{ s} \). Thus, the frequency is calculated as:
\[ f = \frac{1}{0.00005 \, \text{s}} = 20,000 \, \text{Hz} \]
This means the fan blades rotate \( 20,000 \) times each second, indicating a high-speed rotation typical of jet engines.
Angular Frequency
Angular frequency, denoted \( \omega \), is a measure of how quickly something rotates or oscillates and is expressed in radians per second. It's directly tied to the frequency that we've already determined.
The relationship is given by the formula:
\[ \omega = 2\pi f \]
where:
  • \( \omega \) is the angular frequency in radians per second
  • \( f \) is the regular frequency in hertz
The factor of \( 2\pi \) comes from the mathematical constant \( \pi \), since there are \( 2\pi \) radians in one complete cycle of a circle.
By using the calculated frequency, \( f = 20,000 \text{ Hz} \), the angular frequency becomes:
\[ \omega = 2\pi \times 20,000 = 40,000\pi \, \text{rad/s} \]
This high angular frequency reflects the rapid rotation characteristic of machinery such as jet engine fan blades.

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