/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 During takeoff, an airplane clim... [FREE SOLUTION] | 91Ó°ÊÓ

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During takeoff, an airplane climbs with a speed of \(180 \mathrm{m} / \mathrm{s}\) at an angle of \(34^{\circ}\) above the horizontal. The speed and direction of the airplane constitute a vector quantity known as the velocity. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)

Short Answer

Expert verified
The shadow moves at approximately 149.22 m/s.

Step by step solution

01

Understand the problem

We need to find the horizontal component of the airplane's velocity, which is essentially the speed of the airplane's shadow along the ground.
02

Identify known quantities

The airplane's velocity is given as \( v = 180 \, \mathrm{m/s} \), and the angle of elevation is \( \theta = 34^{\circ} \).
03

Apply trigonometric relation

To find the horizontal component of the velocity, we use the cosine function: \( v_x = v \cdot \cos \theta \), where \( v_x \) is the horizontal component of the velocity.
04

Calculate the horizontal component

Substitute the known values into the equation: \( v_x = 180 \, \mathrm{m/s} \cdot \cos(34^{\circ}) \).
05

Compute the result

Using a calculator, \( \cos(34^{\circ}) \approx 0.829 \). Thus, \( v_x = 180 \cdot 0.829 \approx 149.22 \, \mathrm{m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Components
In physics, understanding velocity components is essential when analyzing motion in two or three dimensions. Velocity is a vector quantity, meaning it has both a magnitude and a direction. To break this down into components helps us visualize and solve different parts of the motion independently. In the context of our airplane example, the velocity of 180 m/s at an angle of 34 degrees above the horizontal has both horizontal and vertical components.
  • The horizontal component represents how fast the airplane's shadow is moving along the ground. This is crucial because this component stays consistent when the only external influence is the angle.
  • The vertical component would indicate how quickly the airplane is ascending into the air. While this is not directly needed to find the shadow's velocity, it gives us a complete picture of the plane's trajectory.
By separating the velocity into these components, predictions about movement, such as the distance over time in each direction, become much easier to handle.
Trigonometry in Physics
Trigonometry plays a fundamental role in resolving vectors into their components, especially when dealing with angles. At its core, trigonometry involves the study of triangles, particularly right triangles, and relates the angles to the lengths of their sides using specific functions: sine, cosine, and tangent. In the airplane example, we use the cosine function to find the horizontal component of the velocity. Why cosine? Because cosine relates the adjacent side to the hypotenuse in a right triangle. Here, the hypotenuse is the airplane's total velocity (180 m/s), and the adjacent side would be the horizontal velocity component we want to calculate. To find any vector's horizontal portion:
  • Multiply the vector's magnitude by the cosine of the angle.
  • For the airplane, this becomes: \( v_x = 180 \times \cos(34^{\circ}) \).
  • Using a calculator, \( \cos(34^{\circ}) \approx 0.829 \).
Thus, trigonometry transforms an abstract angled motion into tangible horizontal and vertical speeds, facilitating easier analysis and predictions.
Horizontal Motion
Horizontal motion in physics refers to the movement of an object parallel to the horizon. In simpler terms, it's what you observe when watching something move directly left or right with no change in its vertical position. Analyzing horizontal motion often involves understanding how speed and time interact. In the case of the airplane, the important aspect of horizontal motion is the speed of the shadow on the ground. Even though the airplane is moving along a path that takes it higher into the sky, its shadow is only concerned with the horizontal component of its velocity. This horizontal motion doesn't just apply to shadows. Consider:
  • Cars driving in a straight line on a flat road exhibit pure horizontal motion.
  • Things moving along conveyor belts or escalators mainly experience horizontal motion.
Bringing it back to our shadow example, understanding horizontal motion tells us how much ground the shadow covers over any period, solidifying how to consider time and speed in physics-like scenarios. That's why calculating the horizontal component is essential for real-world applications like navigation, aviation, and sports.

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