/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Just after a motorcycle rides of... [FREE SOLUTION] | 91Ó°ÊÓ

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Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 7700 rev/min. The motorcycle rider forgets to throttle back, so the engine"s angular speed increases to 12.500 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 3.8 rev/min. Calculate the ratio \(I_{\mathrm{L}} / I_{\mathrm{M}}\) of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Short Answer

Expert verified
The ratio \( I_L / I_M \) is approximately 1263.16.

Step by step solution

01

Understand the System

The problem involves a motorcycle where the engine accelerates while the rest of the motorcycle (including the rider) compensates by rotating. We need to find the ratio of the moment of inertia of the engine to the motorcycle.
02

Identify Initial and Final Conditions

Initially, the engine rotates counterclockwise at 7700 rev/min. As the engine accelerates to 12,500 rev/min, the remaining mass (motorcycle + rider) begins to rotate clockwise at 3.8 rev/min.
03

Apply the Conservation of Angular Momentum

The total angular momentum of the system must be conserved. The initial angular momentum is the angular momentum of the engine alone. The final angular momentum is the sum of the angular momentum of the engine and the motorcycle with the rider. Initial angular momentum:\[ L_i = I_M \cdot w_i \]where \( I_M \) is the moment of inertia of the engine and \( w_i \) is the initial angular velocity.Final angular momentum:\[ L_f = I_M \cdot w_f - I_L \cdot w_L \]where \( w_f \) is the final angular velocity of the engine and \( w_L \) is the angular velocity of the motorcycle (clockwise rotation is treated as negative).
04

Set Up the Angular Momentum Equation

Setting initial and final angular momenta equal gives:\[ I_M \cdot w_i = I_M \cdot w_f - I_L \cdot w_L \]Rearranging for \( I_L / I_M \), we get:\[ \frac{I_L}{I_M} = \frac{w_f - w_i}{w_L} \]
05

Convert Angular Velocities to Radians per Second

Convert all given angular velocities from revolutions per minute to radians per second since rad/s is the standard unit for angular velocities.- \( w_i = 7700 \times \frac{2\pi}{60} \)- \( w_f = 12500 \times \frac{2\pi}{60} \)- \( w_L = 3.8 \times \frac{2\pi}{60} \)
06

Compute the Ratio \( \frac{I_L}{I_M} \)

Substitute the converted velocities into the equation:\[ \frac{I_L}{I_M} = \frac{12500 \times \frac{2\pi}{60} - 7700 \times \frac{2\pi}{60}}{3.8 \times \frac{2\pi}{60}} \]Cancel the \( \frac{2\pi}{60} \) factor:\[ \frac{I_L}{I_M} = \frac{12500 - 7700}{3.8} = \frac{4800}{3.8} \approx 1263.16\]
07

Conclude the Calculation

The ratio of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle, \( I_L / I_M \), is approximately 1263.16.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia is a crucial concept in rotational dynamics. It describes how difficult it is to change the rotational motion of an object. Imagine trying to spin a large merry-go-round versus a small bicycle wheel. The merry-go-round is harder to spin due to its larger moment of inertia. In mathematical terms, the moment of inertia, denoted as \( I \), depends on the mass of the object and how this mass is distributed relative to the axis of rotation.

When dealing with a system like a motorcycle and its engine, the moment of inertia will affect how the vehicle's and driver's rotation behaves. The distribution of mass around the engine and the rest of the motorcycle, including the rider, dictates how these sections will react when rotational forces act upon them. In our problem, there's separate moment of inertia for the engine \( I_M \) and for the rest of the motorcycle \( I_L \), playing an essential role in determining their respective rotational responses.
Angular Velocity
Angular velocity describes how quickly an object rotates. It's the rate of change of the angle through which an object moves over time. Measured in revolutions per minute (rev/min) or radians per second (rad/s), angular velocity changes when forces act to speed up or slow down the rotation.

In our motorcycle exercise, the angular velocity of the engine and the rest of the motorcycle change when the throttle is left open. The engine increases its angular velocity from 7700 rev/min to 12,500 rev/min, while the rest of the motorcycle begins rotating in the opposite direction at 3.8 rev/min. This change illustrates how rotational motion is influenced by varying angular velocities, as described by the angular momentum conservation in the system.
Rotational Motion
Rotational motion occurs when an object spins around an axis. Unlike linear motion, it's governed by angular parameters like angular velocity and moment of inertia. The conservation of angular momentum is an important principle in rotational motion. It states that in the absence of external torques, the total angular momentum of a system remains constant.

For the motorcycle in the example, as it flips in the air, the angular momentum initially present in the engine is redistributed, causing the rest of the motorcycle to counter-rotate. This rotational adjustment ensures that the system's total angular momentum remains unchanged. Such interactions highlight the fascinating dynamics of rotational motion, showcasing how rotational forces create and influence motion in everyday objects.

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Most popular questions from this chapter

Two spheres are each rotating at an angular speed of \(24 \mathrm{rad} / \mathrm{s}\) about axes that pass through their centers. Each has a radius of \(0.20 \mathrm{m}\) and a mass of \(1.5 \mathrm{kg}\). However, as the figure shows, one is solid and the other is a thin-walled spherical shell. Suddenly, a net external torque due to friction (magnitude \(=0.12 \mathrm{N} \cdot \mathrm{m}\) ) begins to act on each sphere and slows the motion down. Concepts: (i) Which sphere has the greater moment of inertia and why? (ii) Which sphere has the angular acceleration (a deceleration) with the smaller magnitude? (iii) Which sphere takes a longer time to come to a halt? Calculations: How long does it take each sphere to come to a halt?

A thin rod has a length of \(0.25 \mathrm{m}\) and rotates in a circle on a frictionless tabletop. The axis is perpendicular to the length of the rod at one of its ends. The rod has an angular velocity of \(0.32 \mathrm{rad} / \mathrm{s}\) and a moment of inertia of \(1.1 \times 10^{-3} \mathrm{kg} \cdot \mathrm{m}^{2}\), A bug standing on the axis decides to crawl out to the other end of the rod. When the bug (mass \(=4.2 \times 10^{-3} \mathrm{kg}\) ) gets where it's going, what is the angular velocity of the rod?

A helicopter has two blades (see Figure 8.11 ); each blade has a mass of \(240 \mathrm{kg}\) and can be approximated as a thin rod of length \(6.7 \mathrm{m} .\) The blades are rotating at an angular speed of \(44 \mathrm{rad} / \mathrm{s}\). (a) What is the total moment of inertia of the two blades about the axis of rotation? (b) Determine the rotational kinetic energy of the spinning blades.

A solid sphere is rolling on a surface. What fraction of its total kinetic energy is in the form of rotational kinetic energy about the center of mass?

In outer space two identical space modules are joined together by a massless cable. These modules are rotating about their center of mass, which is at the center of the cable because the modules are identical (see the drawing). In each module, the cable is connected to a motor, so that the modules can pull each other together. The initial tangential speed of each module is \(v_{0}=17 \mathrm{m} / \mathrm{s} .\) Then they pull together until the distance between them is reduced by a factor of two. Each module has a final tangential speed of \(v_{\mathrm{r}}\). Find the value of \(v_{\mathrm{f}}\)

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