/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 A fan blade is rotating with a c... [FREE SOLUTION] | 91Ó°ÊÓ

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A fan blade is rotating with a constant angular acceleration of \(+12.0 \mathrm{rad} / \mathrm{s}^{2} .\) At what point on the blade, as measured from the axis of rotation, does the magnitude of the tangential acceleration equal that of the acceleration due to gravity?

Short Answer

Expert verified
The point is approximately 0.817 meters from the axis of rotation.

Step by step solution

01

Identify Given Information

We know that the blade has an angular acceleration \( \alpha = 12.0 \, \text{rad/s}^2 \) and the magnitude of the gravitational acceleration is \( g = 9.8 \, \text{m/s}^2 \). We need to find the radius where the tangential acceleration equals the gravitational acceleration.
02

Relate Tangential and Angular Acceleration

The tangential acceleration \( a_t \) at a point on the blade is given by the formula \( a_t = r \cdot \alpha \), where \( r \) is the distance from the axis of rotation.
03

Set Up the Equation

To find the condition where the tangential acceleration equals gravitational acceleration, we set \( a_t = g \). This gives us the equation \( r \cdot \alpha = g \).
04

Solve for the Radius \( r \)

Solve the equation \( r \cdot \alpha = g \) for \( r \):\[ r = \frac{g}{\alpha} \]Substitute \( g = 9.8 \, \text{m/s}^2 \) and \( \alpha = 12.0 \, \text{rad/s}^2 \) into the equation.\[ r = \frac{9.8}{12.0} \approx 0.817 \, \text{m} \]
05

Interpret the Result

The result \( r \approx 0.817 \, \text{m} \) means that at 0.817 meters from the axis of rotation, the tangential acceleration of the blade matches the acceleration due to gravity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangential Acceleration
Tangential acceleration is an important concept in rotational motion. It is the measure of how fast the velocity of a point on a rotating object is changing along the tangent to the circle of rotation.
  • It is directly proportional to the distance from the axis of rotation. This means the farther a point is from the axis, the greater the tangential acceleration will be, provided the angular acceleration remains constant.
  • The formula for tangential acceleration is expressed as \( a_t = r \cdot \alpha \), where \( a_t \) represents the tangential acceleration, \( r \) is the radius or distance from the axis, and \( \alpha \) is the angular acceleration.
This formula tells us that you can find the tangential acceleration by multiplying the angular acceleration with the radius of rotation. When a fan blade accelerates, each point on the blade experiences tangential acceleration, and it is this acceleration that changes their speed over time.
Gravitational Acceleration
Gravitational acceleration, often denoted by \( g \), is the acceleration experienced by an object due to the force of gravity. On Earth, this acceleration is approximately \( 9.8 \ ext{m/s}^2 \).
  • This acceleration remains constant near the Earth's surface, meaning all objects, regardless of their mass, will fall with the same rate of acceleration when only gravity is acting on them.
  • In problems related to physics, gravitational acceleration is typically used as a constant value unless specified otherwise with context (e.g., different planets, heights, or specific circumstances).
In the context of the rotating fan blade, we set up an equation such that the tangential acceleration equals the gravitational acceleration. This is to find the point on the blade where these two accelerations are equivalent. This comparison provides a practical way to relate two seemingly different kinds of acceleration in rotational dynamics.
Radius of Rotation
The radius of rotation plays a crucial role in rotational motion. It is the distance from the axis of rotation to any point on the rotating object.
  • The radius determines how far a certain point on an object travels when the object rotates 360 degrees around its axis.
  • In rotational motion dynamics, the radius \( r \) is used in various formulas, especially when connecting linear and angular quantities; for example, \( a_t = r \cdot \alpha \).
In problems like the rotating fan blade example, finding the exact radius where a particular condition is met (like the tangential acceleration equaling gravitational acceleration) is essential. The steps outlined in the original solution involved solving for the radius, providing us with a distance of approximately \( 0.817 \, \text{m} \), where the tangential and gravitational accelerations are equal. Understanding the radius's role can help in visualizing the path traveled by each point on the rotating object and its corresponding acceleration and velocity.

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Most popular questions from this chapter

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