/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Two people start at the same pla... [FREE SOLUTION] | 91Ó°ÊÓ

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Two people start at the same place and walk around a circular lake in opposite directions. One walks with an angular speed of \(1.7 \times 10^{-3} \mathrm{rad} / \mathrm{s}\), while the other has an angular speed of \(3.4 \times 10^{-3} \mathrm{rad} / \mathrm{s} .\) How long will it be before they meet?

Short Answer

Expert verified
1232.2 seconds

Step by step solution

01

Understanding the Problem

Two people walk around a circular lake with different angular speeds and in opposite directions. We want to find out how long it takes for them to meet, starting from the same point.
02

Finding the Relative Angular Speed

Since both people are moving towards each other, their relative angular speed is the sum of their individual angular speeds. Calculate this as follows:\[\omega = \omega_1 + \omega_2 = 1.7 \times 10^{-3} + 3.4 \times 10^{-3} = 5.1 \times 10^{-3} \, \text{rad/s}\]
03

Formulating the Equation for Angular Position

They will meet when the sum of their angular positions equals \(2\pi\), since they need to cover the full circle. The equation is:\[\Delta \theta = \omega \cdot t = 2\pi\]where \(\Delta \theta\) is the angular displacement, \(\omega\) is the relative angular speed, and \(t\) is the time.
04

Solving for Time

Solve the equation \(\omega \cdot t = 2\pi\) for \(t\):\[t = \frac{2\pi}{\omega} = \frac{2\pi}{5.1 \times 10^{-3}} \approx 1232.2 \, \text{s}\]
05

Conclusion

The two people will meet after approximately 1232.2 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
Angular speed is a measure of how quickly an object rotates or revolves relative to another point or axis. It tells us how fast the angle is changing over time as the object moves along its circular path. Angular speed is typically denoted by the Greek letter \(\omega\) and expressed in radians per second (rad/s).
  • Angular speed is constant if the speed of rotation does not change over time.
  • The formula for angular speed is \(\omega = \frac{\Delta \theta}{\Delta t}\), where \(\Delta \theta\) is the angular displacement and \(\Delta t\) is the time duration.
In the context of the exercise, each person walking around the lake has a distinct angular speed. Their speeds are given as \(1.7 \times 10^{-3} \) rad/s and \(3.4 \times 10^{-3} \) rad/s. These values help us understand how quickly each person progresses along their paths.
Relative Angular Speed
When two moving objects have different angular speeds and are traveling in opposite directions, we often look at their relative angular speed. This idea is crucial when determining when two objects will meet along a circular path, as in our exercise.The relative angular speed is simply the sum of their individual angular speeds:
  • Formula: \(\omega_{\text{relative}} = \omega_1 + \omega_2\)
  • This is because the two objects are moving toward each other, effectively reducing the distance between them faster than if only one were moving.
For the people walking around the lake, it is calculated as:\[\omega_{\text{relative}} = 1.7 \times 10^{-3} + 3.4 \times 10^{-3} = 5.1 \times 10^{-3} \, \text{rad/s}\]Understanding relative angular speed allows us to compute the time it takes for them to meet by letting us know how fast this combined angular progression is.
Angular Displacement
Angular displacement represents the angle through which an object moves on a circular path. It is a measure of the change in the angular position of the object around that circle. In simpler terms, it shows how far the object has rotated in a given time interval, measured in radians.In our exercise, we need to determine when the people meet, which requires them to collectively cover the whole circle. The key points include:
  • For a full circle, the angular displacement is \(2\pi\) radians.
  • The formula connecting angular displacement and relative angular speed is: \(\Delta \theta = \omega \cdot t\)
Using this in the exercise's context, we set up the equation \(5.1 \times 10^{-3} \cdot t = 2\pi\) to solve for the time \(t\). This equation shows how the total relative angular speed leads to the two people having a collective angular displacement that equals a full circle. Solving it gives the meeting time of approximately 1232.2 seconds.

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Most popular questions from this chapter

An electric fan is running on HIGH. After the LOW button is pressed, the angular speed of the fan decreases to \(83.8 \mathrm{rad} / \mathrm{s}\) in \(1.75 \mathrm{s}\). The deceleration is \(42.0 \mathrm{rad} / \mathrm{s}^{2} .\) Determine the initial angular speed of the fan.

The initial angular velocity and the angular acceleration of four rotating objects at the same instant in time are listed in the table that follows. For each of the objects (a), (b), (c), and (d), determine the final angular speed after an elapsed time of \(2.0 \mathrm{s}\). $$ \begin{array}{lcc} \hline & \begin{array}{c} \text { Initial angular } \\ \text { velocity } \omega_{0} \end{array} & \begin{array}{c} \text { Angular } \\ \text { acceleration } \alpha \end{array} \\ \hline \text { (a) } & +12 \mathrm{rad} / \mathrm{s} & +3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \text { (b) } & +12 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \text { (c) } & -12 \mathrm{rad} / \mathrm{s} & +3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \text { (d) } & -12 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s}^{2} \\\ \hline \end{array} $$

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 47 rev/s, and its tip has a tangential speed of \(54 \mathrm{m} / \mathrm{s}\). What is the length of the rotating string?

The earth orbits the sun once a year \(\left(3.16 \times 10^{7} \mathrm{s}\right)\) in a nearly circular orbit of radius \(1.50 \times 10^{11} \mathrm{m} .\) With respect to the sun, determine (a) the angular speed of the earth, (b) the tangential speed of the earth, and (c) the magnitude and direction of the earth's centripetal acceleration.

A rider on a mountain bike is traveling to the left in the figure. Each wheel has an angular velocity of \(+21.7 \mathrm{rad} / \mathrm{s},\) where, as usual, the plus sign indicates that the wheel is rotating in the counterclockwise direction. (a) To pass another cyclist, the rider pumps harder, and the angular velocity of the wheels increases from +21.7 to \(+28.5 \mathrm{rad} / \mathrm{s}\) in a time of 3.50 s. (b) After passing the cyclist, the rider begins to coast, and the angular velocity of the wheels decreases from +28.5 to +15.3 rad/s in a time of 10.7 s. Concepts: (i) Is the angular acceleration positive or negative when the rider is passing the cyclist and the angular speed of the wheels is increasing? (ii) Is the angular acceleration positive or negative when the rider is coasting and the angular speed of the wheels is decreasing? Calculations: In both instances, (a) and (b), determine the magnitude and direction of the angular acceleration (assumed constant) of the wheels.

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