/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 A bicyclist rides 5.0 km due eas... [FREE SOLUTION] | 91Ó°ÊÓ

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A bicyclist rides 5.0 km due east, while the resistive force from the air has a magnitude of \(3.0 \mathrm{N}\) and points due west. The rider then turns around and rides \(5.0 \mathrm{km}\) due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of \(3.0 \mathrm{N}\) and points due east. (a) Find the work done by the resistive force during the round trip. (b) Based on your answer to part (a), is the resistive force a conservative force? Explain.

Short Answer

Expert verified
(a) The total work done is \(-30000 \, \mathrm{J}\). (b) The resistive force is non-conservative.

Step by step solution

01

Define the Formula for Work Done

The work done by a force is given by the formula \( W = F \cdot d \cdot \cos(\theta) \), where \( F \) is the magnitude of the force, \( d \) is the displacement, and \( \theta \) is the angle between the force and displacement directions. When the force and displacement are in opposite directions, \( \theta = 180^\circ \) and \( \cos(180^\circ) = -1 \).
02

Calculate Work Done During the Eastward Trip

For the eastward trip, the force of air resistance is 3.0 N pointing west, while the displacement is 5.0 km due east. Thus, \( \theta = 180^\circ \), making \( \cos(\theta) = -1 \). Therefore, the work done is: \[ W_1 = 3.0 \, \mathrm{N} \times 5.0 \, \mathrm{km} \times (-1) = -15.0 \, \mathrm{kJ} \].
03

Convert Kilometers to Meters

Since work involves the product of force (in Newtons) and displacement (in meters), convert 5.0 km to meters: \( 5.0 \, \mathrm{km} = 5000 \, \mathrm{m} \). Thus, \[ W_1 = 3.0 \, \mathrm{N} \times 5000 \, \mathrm{m} \times (-1) = -15000 \, \mathrm{J} \].
04

Calculate Work Done During the Westward Trip

For the westward trip, the resistive force of air is again 3.0 N but points east, and the displacement is 5.0 km due west. As before, \( \theta = 180^\circ \), so: \[ W_2 = 3.0 \, \mathrm{N} \times 5000 \, \mathrm{m} \times (-1) = -15000 \, \mathrm{J} \].
05

Calculate Total Work Done During the Round Trip

The total work done by the resistive force during the entire round trip is the sum of the work done on each leg of the trip: \[ W_\text{total} = W_1 + W_2 = -15000 \, \mathrm{J} + (-15000 \, \mathrm{J}) = -30000 \, \mathrm{J} \].
06

Determine if the Resistive Force is Conservative

A force is considered conservative if the work done by it over a closed path is zero. Since the total work done by the resistive force is \(-30000 \, \mathrm{J}\), which is not zero, the resistive force is non-conservative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resistive Force
Resistive force is a type of force that opposes the motion of an object. This can be due to friction, air resistance, or any other forces that resist the motion. In the context of a bicyclist riding against the wind, the resistive force is the air resistance trying to slow them down.

Key characteristics of resistive forces:
  • They always act in the direction opposite to the direction of motion.
  • The magnitude can vary depending on factors such as speed, surface area, and medium through which the object is moving.
  • As shown in the exercise, the resistive force from air is 3.0 N, opposing the cyclist’s motion in both directions of the trip.
Resistive forces are important because they contribute to energy loss in mechanical systems, often converting kinetic energy into thermal energy. In physics problems, determining the work done by resistive forces helps understand how much energy is lost as an object moves through resisting mediums.
Conservative Force
Conservative forces are forces where the work done depends only on the initial and final positions of an object, not on the path taken. A hallmark of conservative forces is that the work done in a closed loop is zero.

Characteristics of conservative forces include:
  • The path between starting and ending points doesn’t affect the amount of work done.
  • Examples include gravitational and elastic forces, where potential energy can be defined.
In the exercise, to determine if the resistive force is conservative, we examine the total work done over the round trip. The work done by the resistive force in returning to the start point isn’t zero (\(-30000 \, \mathrm{J}\)), proving it is non-conservative. This means energy is lost to the environment, which can’t be fully recovered by simply returning to the starting position.
Work-Energy Principle
The work-energy principle is a fundamental concept in physics. It states that the work done by all forces acting on an object results in a change in the object's kinetic energy.

The principle can be formulated as:\[ W = \Delta KE = KE_{\text{final}} - KE_{\text{initial}} \]Where:
  • \( W \) is the work done by forces.
  • \( \Delta KE \) is the change in kinetic energy.
This principle is especially useful in analyzing systems where forces do work, like in our bicyclist example. The negative work done by resistive forces (\(-30000 \, \mathrm{J}\)) on the cyclist shows there is a decrease in the mechanical energy of the system. Energy is dissipated primarily as heat due to air resistance. Understanding the work-energy principle helps predict how objects behave under various forces, offering insights into energy conservation and loss in moving systems.

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Most popular questions from this chapter

6\. A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of \(22.0 \mathrm{m} .\) She pushes in a direction \(29.0^{\circ}\) below the horizontal. A \(48.0-N\) frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts? Determine the work done by (b) the pushing force, (c) the frictional force, and (d) the gravitational force.

A \(35-\mathrm{kg}\) girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 210 J from 440 J. How high does she rise during this interval? Neglect air resistance.

Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the drive force is shut off, the snowmobile coasts to a halt. The snowmobile and its rider have a mass of \(136 \mathrm{kg}\). Under the influence of a drive force of \(205 \mathrm{N},\) it is moving at a constant velocity whose magnitude is \(5.50 \mathrm{m} / \mathrm{s}\) The drive force is then shut off. Find (a) the distance in which the snowmobile coasts to a halt and (b) the time required to do so.

A 16-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of \(24 \mathrm{N}\). Starting from rest, the sled attains a speed of \(2.0 \mathrm{m} / \mathrm{s}\) in \(8.0 \mathrm{m} .\) Find the coefficient of kinetic friction between the runners of the sled and the snow.

You are working out on a rowing machine. Each time youpull the rowing bar (which simulates the oars) toward you, it moves a distance of \(1.2 \mathrm{m}\) in a time of \(1.5 \mathrm{s}\). The readout on the display indicates that the average power you are producing is 82 W. What is the magnitude of the force that you exert on the handle?

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