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Computer-controlled display screens provide drivers in the Indianapolis 500 with a variety of information about how their cars are performing. For instance, as a car is going through a turn, a speed of \(221 \mathrm{mi} / \mathrm{h}\) \((98.8 \mathrm{m} / \mathrm{s})\) and centripetal acceleration of \(3.00 \mathrm{g}\) (three times the acceleration due to gravity) are displayed. Determine the radius of the turn (in meters).

Short Answer

Expert verified
The radius of the turn is approximately 331.30 meters.

Step by step solution

01

Understand the given information

We are given the speed of the car as 98.8 m/s and the centripetal acceleration as 3 times the gravitational acceleration. Gravitational acceleration \( g \) is \( 9.8 \, \text{m/s}^2 \), so the centripetal acceleration is \( 3g = 3 \times 9.8 = 29.4 \, \text{m/s}^2 \).
02

Recall the centripetal acceleration formula

The formula for centripetal acceleration \( a_c \) is given by \( a_c = \frac{v^2}{r} \), where \( v \) is the speed and \( r \) is the radius of the turn.
03

Rearrange the formula to solve for radius

We need to find the radius \( r \). Rearrange the formula \( a_c = \frac{v^2}{r} \) to \( r = \frac{v^2}{a_c} \).
04

Substitute the known values into the formula

Substitute the given values into the rearranged formula: \( r = \frac{(98.8)^2}{29.4} \).
05

Perform the calculation

Calculate \( v^2 = (98.8)^2 = 9751.04 \). Then divide by the centripetal acceleration: \( r = \frac{9751.04}{29.4} \approx 331.30 \).
06

State the result

The radius of the turn is approximately 331.30 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Acceleration
Centripetal acceleration is a key concept when discussing motion in a circular path. It refers to the acceleration required to keep an object moving in a circle at a constant speed. This acceleration is directed towards the center of the circle, ensuring the object does not fly off in a straight line, due to inertia.
It's important to understand that even if an object moves at a steady speed in a circular path, its velocity is not constant because its direction is continually changing. To quantify centripetal acceleration, we use the formula:
  • \( a_c = \frac{v^2}{r} \)
Here, \( v \) is the object's speed, and \( r \) is the radius of the circle. In the exercise, the car’s centripetal acceleration is described as three times the acceleration due to gravity, which translates to about \( 29.4 \, \text{m/s}^2 \). This significant level of acceleration highlights the speedy and tight nature of the racetrack turn.
Physics Problem Solving
Physics problem solving is a structured approach that involves understanding, planning, and executing steps to find the solution. Let's break it down using the exercise provided:
First, it’s crucial to understand what is given and what is asked. Here, we know the car’s speed and its centripetal acceleration, with our task being to find the radius of the turn.
Once clarity on knowns and unknowns is achieved, selecting the correct formula forms the next step. For circular motion problems, formulas for centripetal forces and acceleration often illumine the path forward.
After choosing the formula, rearrange it if needed, and substitute the known values. It often helps to keep all calculations clear and organized to avoid errors. Finally, executing these calculations leads us to a logical and correct result. This methodical approach ensures even the most complex problems are tackled efficiently.
Kinematics
Kinematics is a branch of physics that deals with the motion of objects without considering the forces causing the motion. It helps us understand the relationship between velocity, acceleration, time, and displacement. These principles play a vital role in solving questions like the exercise above, where we need to work out the radius based on speed and acceleration.
In circular motion problems, understanding how an object accelerates as it changes direction is vital. While constant speed may imply zero acceleration in linear motion, speed around a turn involves changing velocity due to the directional change. Hence centripetal acceleration becomes central to understanding circular kinematics.
This part of physics emphasizes the elegant relationships that exist in motion, helping us derive accurate predictions about how objects behave and interact with paths, whether linear or circular.
Acceleration due to Gravity
The acceleration due to gravity on Earth's surface is approximately \( 9.8 \, \text{m/s}^2 \). This is a crucial constant in many physics calculations, particularly for problems involving forces and accelerations.
In the original problem, the car's centripetal acceleration is given as "3g," which means three times the gravitational acceleration, equivalent to around \( 29.4 \, \text{m/s}^2 \).
This use of multiples of \( g \) is common in physics as it gives an intuitive understanding of the situation, connecting the familiar experience of gravity to the more abstract concept of centripetal forces for circular motion.
Understanding how \( g \) applies in various contexts aids in visualizing the significance of forces and motions, whether an object is falling vertically under gravity’s pull or racing around a circular track.

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Most popular questions from this chapter

A \(0.20-\mathrm{kg}\) ball on a stick is whirled on a vertical circle at a constant speed. When the ball is at the three o'clock position, the stick tension is \(16 \mathrm{N}\). Find the tensions in the stick when the ball is at the twelve o'clock and at the six o'clock positions.

The second hand and the minute hand on one type of clock are the same length. Find the ratio \(\left(a_{\mathrm{c}, \text { second }} / a_{\mathrm{c}, \text { minute }}\right)\) of the centripetal accelerations of the tips of the second hand and the minute hand.

Pilots of high-performance fighter planes can be subjected to large centripetal accelerations during high-speed turns. Because of these accelerations, the pilots are subjected to forces that can be much greater than their body weight, leading to an accumulation of blood in the abdomen and legs. As a result, the brain becomes starved for blood, and the pilot can lose consciousness ("black out"). The pilots wear "anti-G suits" to help keep the blood from draining out of the brain. To appreciate the forces that a fighter pilot must endure, consider the magnitude \(F_{\mathrm{N}}\) of the normal force that the pilot's seat exerts on him at the bottom of a dive. The magnitude of the pilot's weight is \(W\). The plane is traveling at \(230 \mathrm{m} / \mathrm{s}\) on a vertical circle of radius \(690 \mathrm{m} .\) Determine the ratio \(F_{\mathrm{N}} / W .\) For comparison, note that blackout can occur for values of \(F_{\mathrm{N}} / W\) as small as 2 if the pilot is not wearing an anti-G suit.

Multiple-Concept Example 7 reviews the concepts that play a role in this problem. Car A uses tires for which the coefficient of static friction is 1.1 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is \(25 \mathrm{m} / \mathrm{s}\). Car \(\mathrm{B}\) uses tires for which the coefficient of static friction is 0.85 on the same curve. What is the maximum speed at which car B can negotiate the curve?

The National Aeronautics and Space Administration (NASA) studies the physiological effects of large accelerations on astronauts. Some of these studies use a machine known as a centrifuge. This machine consists of a long arm, to one end of which is attached a chamber in which the astronaut sits. The other end of the arm is connected to an axis about which the arm and chamber can be rotated. The astronaut moves on a circular path, much like a model airplane flying in a circle on a guideline. The chamber is located \(15 \mathrm{m}\) from the center of the circle. At what speed must the chamber move so that an astronaut is subjected to 7.5 times the acceleration due to gravity?

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