/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A person in a kayak starts paddl... [FREE SOLUTION] | 91Ó°ÊÓ

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A person in a kayak starts paddling, and it accelerates from 0 to \(0.60 \mathrm{m} / \mathrm{s}\) in a distance of \(0.41 \mathrm{m} .\) If the combined mass of the person and the kayak is \(73 \mathrm{kg}\), what is the magnitude of the net force acting on the kayak?

Short Answer

Expert verified
The net force on the kayak is about 32.05 N.

Step by step solution

01

Understand the Problem

We need to determine the net force acting on the kayak as it accelerates from 0 to 0.60 m/s over a distance of 0.41 m. The combined mass of the person and kayak is 73 kg.
02

Identify the Formula Needed

To find the net force, use the formula: \[ F = ma \] where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration. First, we need to find the acceleration \( a \).
03

Calculate Acceleration using Kinematic Equation

Use the kinematic equation: \[ v^2 = u^2 + 2as \] where \( v = 0.60 \text{ m/s} \) is the final velocity, \( u = 0 \) is the initial velocity, and \( s = 0.41 \text{ m} \) is the distance.Rearrange to find \( a \): \[ a = \frac{v^2 - u^2}{2s} = \frac{(0.60)^2 - 0^2}{2 \times 0.41} \]
04

Compute the Acceleration

Substitute the values into the equation: \[ a = \frac{0.36}{0.82} = 0.439 \text{ m/s}^2 \]
05

Calculate the Net Force

Now, using the formula \( F = ma \), substitute the values for \( m \) and \( a \): \[ F = 73 \times 0.439 = 32.047 \text{ N} \]
06

Final Calculation

The magnitude of the net force acting on the kayak is approximately 32.05 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Net Force
In physics, the concept of net force is pivotal when analyzing motion. Net force is essentially the sum of all the forces acting upon an object. It describes the overall force that leads to the movement or acceleration of that object. When multiple forces act on an object, they combine to form a net force, which determines the state and rate of movement.
  • If the net force is zero, the object remains at rest or continues moving at a constant velocity.
  • If the net force is non-zero, the object will accelerate in the direction of the net force.
In the context of the kayak example, understanding that a net force is what causes the kayak to begin moving from rest is key. This force results from the person paddling, overcoming forces like water resistance. In this case, we calculated the net force needed for the kayak to accelerate from a rest position to a specific velocity over a certain distance.
Explaining Acceleration
Acceleration is the rate at which an object changes its velocity. It's a vector quantity, having both magnitude and direction, and is expressed in meters per second squared (m/s²). Whenever a net force acts on a mass, it causes that mass to accelerate. This concept is captured in Newton's Second Law of Motion, given by the formula:\[ F = ma \]Here, \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration produced.
  • Positive acceleration indicates an increase in speed.
  • Negative acceleration (deceleration) indicates a decrease in speed.
In the kayaking problem, the acceleration caused by the paddling is calculated using initial and final velocities along with the distance traveled. This helps us understand how the kayak speeds up over a small distance, providing a means to then calculate the net force using the mass of the kayak and the acceleration.
Utilizing Kinematic Equations
Kinematic equations are used to describe the motion of objects and are invaluable in solving problems where an object is uniformly accelerating. These equations relate the five key motion parameters: initial velocity (\( u \)), final velocity (\( v \)), acceleration (\( a \)), time (\( t \)), and displacement (\( s \)). A commonly used equation is:\[ v^2 = u^2 + 2as \]This particular equation provided the means for computing acceleration in scenarios where time isn't directly involved. By rearranging this formula, we can solve for acceleration \( a \) when given displacement, initial velocity, and final velocity:
\[ a = \frac{v^2 - u^2}{2s} \]
Given that the person in the kayak started at rest, \( u \) was \( 0 \), simplifying our calculations. This equation effectively bridged the gap between known parameters and unknown acceleration, proving to be instrumental in solving for the net force.

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Most popular questions from this chapter

A damp washcloth is hung over the edge of a table to dry. Thus, part (mass \(\left.=m_{\mathrm{on}}\right)\) of the washcloth rests on the table and part (mass \(\left.=m_{\mathrm{off}}\right)\) does not. The coefficient of static friction between the table and the washcloth is 0.40. Determine the maximum fraction \(\left[m_{\text {off }} /\left(m_{\text {on }}+m_{\text {off }}\right)\right]\) that can hang over the edge without causing the whole washcloth to slide off the table.

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