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An 81 -kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is \(0.49 .\) (a) What is the magnitude of the frictional force? (b) If the player comes to rest after \(1.6 \mathrm{s}\), what was his initial velocity?

Short Answer

Expert verified
(a) 389.962 N. (b) Initial velocity was 7.7024 m/s.

Step by step solution

01

Identify the frictional force

To find the magnitude of the frictional force, use the formula for kinetic friction: \[ f_k = \mu_k \cdot N \]where \(f_k\) is the kinetic frictional force, \(\mu_k = 0.49\) is the coefficient of kinetic friction, and \(N\) is the normal force. Since the player is moving horizontally on a flat surface, the normal force \(N\) is equal to the gravitational force, \(N = mg\). The gravitational force can be calculated using the player's mass \(m = 81\, \text{kg}\) and acceleration due to gravity \(g = 9.8\, \text{m/s}^2\). So,\[ N = 81 \times 9.8 = 793.8 \text{ N} \]Then,\[ f_k = 0.49 \times 793.8 = 389.962 \text{ N} \]
02

Determine the acceleration

The frictional force produces the acceleration that causes the player to stop. Using Newton's second law, the net force \(f_k\) is equal to mass \(m\) times acceleration \(a\):\[ f_k = m \cdot a \]Solving for \(a\), we get:\[ a = \frac{f_k}{m} = \frac{389.962}{81} = 4.814 \text{ m/s}^2 \]Since this force is opposing the motion, the acceleration is negative, \( a = -4.814 \; \text{m/s}^2 \).
03

Calculate the initial velocity

The player comes to rest in \(1.6 \text{ s}\), which means the final velocity \(v_f = 0 \text{ m/s}\). Using the kinematic equation,\[ v_f = v_i + a \cdot t \]where \(v_i\) is the initial velocity, \(a = -4.814 \text{ m/s}^2\), and \(t = 1.6 \text{ s}\), substitute the values and solve for \(v_i\):\[ 0 = v_i - 4.814 \times 1.6 \]\[ v_i = 4.814 \times 1.6 = 7.7024 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Frictional Force
Frictional force is the resistive force that opposes the motion or attempted motion of an object in contact with a surface. It's a key factor in everyday phenomena and is crucial in this exercise. There are different types of friction, but here we focus on kinetic friction, which acts on moving objects.
To calculate the kinetic frictional force (\( f_k \)), you use the formula \( f_k = \mu_k \cdot N \). Here, \( \mu_k \) is the coefficient of kinetic friction, a dimensionless value representing the frictional properties between two surfaces. The normal force (\( N \)) is the force perpendicular to the contact surface, often equal to the gravitational force in cases where motion is parallel to the earth's surface.
This exercise provides values for both the mass of the player and the coefficient of kinetic friction. The first step involves calculating the normal force, given by \( N = mg \), where \( m \) is mass and \( g \) is gravity (approximately \( 9.8 \; \text{m/s}^2 \)). Multiplying the coefficient by the normal force gives the frictional force, essential for solving the rest of the problem.
Exploring Newton's Second Law
Newton's second law provides a fundamental principle in understanding motion: "The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass." This is mathematically expressed as \( F = ma \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration.
In the context of the baseball player, the frictional force becomes our net force. This is the force that causes the player to decelerate as he slides into the base. By rearranging the formula to \( a = \frac{F}{m} \), we can solve for the acceleration using the frictional force calculated in the previous step. Since friction opposes motion, the acceleration is negative, indicating a decrease in the player's velocity.
Understanding this principle helps us link the motion of the player to the forces involved, allowing us to determine forces like friction that aren't always immediately visible.
Introduction to Kinematic Equations
Kinematic equations describe the motion of objects under constant acceleration. They are fundamental in physics when predicting the future location or velocity of an object.
In this exercise, the equation \( v_f = v_i + a \cdot t \) is employed, where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, \( a \) is the constant acceleration, and \( t \) is the time the acceleration is applied.
Given that the player comes to a stop after 1.6 seconds (\( v_f = 0 \)), this is rearranged to find the initial velocity (\( v_i \)) before sliding. By inserting the known values into the equation, we solve for \( v_i \) and understand how motion changes over the time interval.
These equations are powerful because they facilitate solving motion problems where initial conditions and forces acting are known, providing insight into the dynamics of motion.

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Most popular questions from this chapter

While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction between the box and the floor is 0.41. The pushing force is directed downward at an angle \(\theta\) below the horizontal. When \(\theta\) is greater than a certain value, it is not possible to move the box, no matter how large the pushing force is. Find that value of \(\theta\).

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