Chapter 3: Problem 65
Two boats are heading away from shore. Boat 1 heads due north at a speed of \(3.00 \mathrm{m} / \mathrm{s}\) relative to the shore. Relative to boat \(1,\) boat 2 is moving \(30.0^{\circ}\) north of east at a speed of \(1.60 \mathrm{m} / \mathrm{s} .\) A passenger on boat 2 walks due east across the deck at a speed of \(1.20 \mathrm{m} / \mathrm{s}\) relative to boat 2 What is the speed of the passenger relative to the shore?
Short Answer
Step by step solution
Understand the Problem
Resolve Boat 2's Velocity
Add Boat 1 and Boat 2's Northward Velocities
Determine Passenger's Eastward Velocity Relative to the Shore
Calculate the Passenger's Total Speed
Final Calculation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometry
For example, when boat 2 moves at an angle of 30° north of east, we can resolve this velocity into two perpendicular components using trigonometric functions:
- Cosine: This function helps us find the northward component by taking the cosine of the angle (30°) multiplied by the velocity (1.60 m/s), resulting in the formula: \[ v_{n2} = 1.60 \cos(30^{\circ}) \]
- Sine: This function is used to calculate the eastward component by multiplying the sine of the angle (30°) by the velocity, resulting in: \[ v_{e2} = 1.60 \sin(30^{\circ}) \]
Pythagorean theorem
In the context of the passenger's speed relative to the shore, we use the Pythagorean theorem to determine the resultant velocity from the northward (\(v_{nt}\)) and eastward (\(v_{et}\)) components of velocity. Specifically, after finding the total velocity components:
- Northward component calculated as: \[ v_{nt} = 3.00 + 1.60 \cos(30^{\circ}) \]
- Eastward component combined from boat's and passenger's velocity: \[ v_{et} = 1.60 \sin(30^{\circ}) + 1.20 \]
Vector Components
When we resolve a vector, like the velocity of boat 2, into components:
- The northward component, defined by the cosine of 30°, aligns with the north axis and is expressed by the formula: \[ v_{n2} = 1.60 \cos(30^{\circ}) \]
- The eastward component, determined by the sine of 30°, aligns with the east axis and can be computed as: \[ v_{e2} = 1.60 \sin(30^{\circ}) \]
Velocity Addition
To find the passenger's overall velocity relative to the shore, follow these steps:
- Add the northward velocity of boat 1 and the northward component of boat 2: \[ v_{nt} = 3.00 + 1.60 \cos(30^{\circ}) \]
- Combine the eastward velocity of the passenger and the eastward component of boat 2: \[ v_{et} = 1.60 \sin(30^{\circ}) + 1.20 \]