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A meteoroid is traveling east through the atmosphere at \(18.3 \mathrm{km} / \mathrm{s}\) while descending at a rate of \(11.5 \mathrm{km} / \mathrm{s}\). What is its speed, in \(\mathrm{km} / \mathrm{s} ?\)

Short Answer

Expert verified
The meteoroid's speed is approximately \(21.62\, \text{km/s}\).

Step by step solution

01

Identify Motion Components

The meteoroid has two components to its velocity: one horizontal (east) and one vertical (downwards). The horizontal component is given as \(18.3\, \text{km/s}\), and the vertical component is \(11.5\, \text{km/s}\).
02

Apply the Pythagorean Theorem

To find the speed of the meteoroid, consider the components as sides of a right triangle where the speed is the hypotenuse. Use the Pythagorean theorem: \[ v = \sqrt{v_x^2 + v_y^2} \] where \( v_x = 18.3\, \text{km/s} \) and \( v_y = 11.5\, \text{km/s} \).
03

Calculate the Speed

Substitute the values into the formula: \[ v = \sqrt{(18.3)^2 + (11.5)^2} \]. Calculate each square: \( 18.3^2 = 334.89 \) and \( 11.5^2 = 132.25 \).
04

Add the Squares

Add the squares of the components: \[ 334.89 + 132.25 = 467.14 \].
05

Find the Square Root

Take the square root of the sum to find the speed of the meteoroid: \[ v = \sqrt{467.14} \approx 21.62\, \text{km/s} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry, particularly when dealing with right triangles. It states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. This can be expressed in the formula: \[ c^2 = a^2 + b^2 \]where \(c\) is the hypotenuse and \(a\) and \(b\) are the other two sides.
In our exercise with the meteoroid, the Pythagorean theorem helps us calculate its overall speed by treating the eastward and downward motions as perpendicular components.
This means that the meteoroid's total speed is like the hypotenuse of a right triangle formed by these two velocity components.
  • The eastward movement is the base of this right triangle.
  • The downward motion is the height of the triangle.
Using this theorem allows us to combine these perpendicular velocities into a single speed value.
motion components
In physics, particularly in kinematics, motion components refer to breaking complex motion into simpler parts, usually along perpendicular axes. In the case of the meteoroid, its motion is divided into two components: one horizontal and one vertical.
The horizontal component for the meteoroid moving east is given as \(18.3 \, \text{km/s}\). This represents the speed along the eastward direction. Similarly, the vertical component, which is its speed while descending, is \(11.5 \, \text{km/s}\). By treating these components separately, we gain a clear understanding of how the meteoroid is traveling through space.
This division is incredibly useful because it allows us to use mathematical tools like the Pythagorean theorem to combine them back into a single value when needed, such as finding the actual velocity.
speed calculation
Calculating speed involves determining how fast an object is moving irrespective of its direction. For our meteoroid problem, speed calculation involves combining the horizontal and vertical motion components.
The formula derived from the Pythagorean theorem gives us the meteoroid's speed: \[ v = \sqrt{v_x^2 + v_y^2} \]where \(v_x\) is the horizontal component (eastward) and \(v_y\) is the vertical component (downward).
Inserting the known values:
  • Eastward speed: \(v_x = 18.3 \, \text{km/s}\)
  • Downward speed: \(v_y = 11.5 \, \text{km/s}\)
We calculate:
  • \(v_x^2 = 334.89\)
  • \(v_y^2 = 132.25\)
Adding these gives \(467.14\). Finally, taking the square root results in the meteoroid's speed: \(21.62 \, \text{km/s}\).
right triangle
A right triangle is a type of triangle where one of the angles is exactly 90 degrees. The relationship between its sides is described by the Pythagorean theorem, making it a crucial tool for many scientific calculations, including motion-related problems.
In the setting of our meteoroid problem, visualizing the horizontal and vertical components as the two shorter sides of a right triangle helps you understand how these independent motions combine into a single trajectory. The hypotenuse then represents the meteoroid's total speed, which we solve for using the Pythagorean theorem.
Understanding the concept of a right triangle not only gives us a great visual aid but also provides the necessary mathematical grounding for effectively combining the motion components.

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Most popular questions from this chapter

A bird watcher meanders through the woods, walking \(0.50 \mathrm{km}\) due east, \(0.75 \mathrm{km}\) due south, and \(2.15 \mathrm{km}\) in a direction \(35.0^{\circ}\) north of west. The time required for this trip is 2.50 h. Determine the magnitude and direction (relative to due west) of the bird watcher's (a) displacement and (b) average velocity. Use kilometers and hours for distance and time, respectively.

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Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of \(4.0 \mathrm{m} / \mathrm{s}\). Neil is in front of her. With respect to the ground, Neil is skating due west at a speed of \(3.2 \mathrm{m} / \mathrm{s}\). Find Neil's velocity (magnitude and direction relative to due west), as seen by Barbara.

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Relative to the ground, a car has a velocity of \(16.0 \mathrm{m} / \mathrm{s}\), directed due north. Relative to this car, a truck has a velocity of \(24.0 \mathrm{m} / \mathrm{s}\), directed \(52.0^{\circ}\) north of east. What is the magnitude of the truck's velocity relative to the ground?

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