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Radiation of a certain wavelength causes electrons with a maximum kinetic energy of \(0.68 \mathrm{eV}\) to be ejected from a metal whose work function is 2.75 eV. What will be the maximum kinetic energy (in eV) with which this same radiation ejects electrons from another metal whose work function is 2.17 eV?

Short Answer

Expert verified
The maximum kinetic energy is 1.26 eV.

Step by step solution

01

Understanding the Photoelectric Effect

The problem is based on the photoelectric effect, where radiation of a certain wavelength is used to eject electrons from a metal surface. The energy of the incoming radiation is used to overcome the work function of the metal and the remaining energy is transformed into the kinetic energy of the ejected electron. Mathematically, this can be expressed as: \( E_{photon} = ext{Work Function} + ext{Kinetic Energy} \).
02

Calculate Photon Energy

The photon energy needed to just overcome the work function and give ejected electrons a maximum kinetic energy of 0.68 eV from the first metal can be calculated by rearranging the formula: \( E_{photon} = ext{Work Function}_{1} + KE_{max1} \). Here, \( ext{Work Function}_{1} = 2.75 ext{ eV} \) and \( KE_{max1} = 0.68 ext{ eV} \). Thus, \( E_{photon} = 2.75 + 0.68 = 3.43 ext{ eV} \).
03

Calculate the New Kinetic Energy

Now that we have the photon energy, it remains constant as we apply it to the second metal with a different work function. Using \( E_{photon} = ext{Work Function}_{2} + KE_{max2} \), where \( ext{Work Function}_{2} = 2.17 ext{ eV} \), solve for the new kinetic energy: \( KE_{max2} = E_{photon} - ext{Work Function}_{2} = 3.43 - 2.17 = 1.26 ext{ eV} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
In physics, kinetic energy refers to the energy an object possesses due to its motion. For electrons, this is the energy they have while moving after being ejected from a metal surface. In the context of the photoelectric effect, when light strikes a metal surface, it can cause electrons to be emitted from the surface. These emitted electrons carry kinetic energy, a concept crucial to understanding how different metals respond to the same radiation.

The kinetic energy (\( KE \)) of an electron being ejected depends on two factors:
  • The energy of the incoming photons
  • The work function of the metal
If the energy of the photons is greater than the metal's work function, the excess energy becomes the kinetic energy of the emitted electron. This relationship highlights the law of conservation of energy and underscores why a higher photon energy translates into greater kinetic energy for the electrons.
Work Function
The work function is a property of a metal that determines the minimum energy needed to eject an electron from its surface. Essentially, it's a barrier that photons must overcome to liberate electrons. Different metals have different work functions, meaning they require a varying amount of energy for electrons to be released.

The concept of the work function is pivotal in the photoelectric effect, where the equation \( E_{photon} = \text{Work Function} + \text{Kinetic Energy} \) describes the process.

Key points about the work function include:
  • It's measured in electronvolts (eV), a unit of energy suitable for such scale.
  • A smaller work function means that less energy is needed to eject an electron.
  • The work function affects the threshold frequency, which is the minimum frequency of light required to eject an electron.
When solving problems related to the photoelectric effect, knowing the work function allows for calculating how much of the photon energy becomes kinetic energy.
Photon Energy
Photon energy is the crucial energy component in the photoelectric effect process, as it determines whether an electron can be ejected from a metal surface. A photon carries energy, which is proportional to its frequency, in accordance with the Planck's equation \( E = hf \), where \( h \) is Planck's constant and \( f \) is the frequency of the light.

Several key points about photon energy include:
  • The energy of a photon is often described in electronvolts (eV), like kinetic energy and work function.
  • Photon energy must be sufficient to at least equal the work function to liberate an electron from its atomic structure.
  • Any excess energy after overcoming the work function contributes to the kinetic energy of the ejected electron.
Understanding photon energy is essential when analyzing how different metals react to the same wavelength of light, as shown in our original exercise. For the second metal, with the same photon energy applied, calculating the kinetic energy involved adjusting for a lower work function, resulting in greater kinetic energy for the ejected electrons.

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Most popular questions from this chapter

The width of the central bright fringe in a diffraction pattern on a screen is identical when either electrons or red light (vacuum wavelength \(=661 \mathrm{nm}\) ) pass through a single slit. The distance between the screen and the slit is the same in each case and is large compared to the slit width. How fast are the electrons moving?

In a Young's double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is \(\theta_{\mathrm{A}}=1.6 \times 10^{-4}\) degrees when the magnitude of the electron momentum is \(p_{\mathrm{A}}=1.2 \times 10^{-22} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} .\) With the same double slit, what momentum magnitude \(p_{\mathrm{B}}\) is necessary so that an angle of \(\theta_{\mathrm{B}}=4.0 \times 10^{-4}\) degrees locates the first-order bright fringes?

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