/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 How fast must a meter stick be m... [FREE SOLUTION] | 91Ó°ÊÓ

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How fast must a meter stick be moving if its length is observed to shrink to one-half of a meter?

Short Answer

Expert verified
The meter stick must be moving at approximately 86.6% the speed of light.

Step by step solution

01

Understand the Concept of Length Contraction

Length contraction is a concept from Albert Einstein's theory of relativity, where the length of an object is measured to be shorter when it is moving relative to an observer, compared to its proper length when at rest.
02

Identify the Given Values

According to the problem, the proper length of the meter stick (when at rest) is 1 meter, and the observed length (when moving) is 0.5 meters.
03

Use the Length Contraction Formula

The length contraction formula is given by: \[L = L_0 \sqrt{1 - \frac{v^2}{c^2}} \]where:- \(L\) is the contracted length- \(L_0\) is the proper length- \(v\) is the velocity of the object- \(c\) is the speed of light.
04

Plug in the Known Values

Substitute the known values into the formula:\[0.5 = 1 \cdot \sqrt{1 - \frac{v^2}{c^2}} \]
05

Solve for Velocity \(v\)

First, solve the equation for \(v\):\[0.5 = \sqrt{1 - \frac{v^2}{c^2}}\]Square both sides to get:\[0.25 = 1 - \frac{v^2}{c^2}\]Rearrange to solve for \(v^2\):\[\frac{v^2}{c^2} = 0.75\]Therefore,\[v^2 = 0.75c^2\]\[v = \sqrt{0.75}c\]
06

Calculate the Velocity

Calculate \(v\) using the approximate value for the square root:\[v \approx \sqrt{0.75} \cdot c \approx 0.866c\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Theory of Relativity
In Einstein's Theory of Relativity, time and space are not separate entities but are intertwined in a four-dimensional continuum known as spacetime. This groundbreaking idea contrasts the classical Newtonian view, where time and space are seen as independent. A crucial part of the theory is the special relativity aspect, which introduces fascinating phenomena like time dilation and length contraction. Length contraction occurs when an object moves at a high velocity relative to an observer, causing its length parallel to the motion direction to be measured as shorter. This concept can be counterintuitive because it defies everyday experiences with stationary objects, bringing excitement yet a need for careful understanding. Einstein's relativity showed that these effects only become appreciable at speeds close to the speed of light, denoted as "c," highlighting how differently the universe behaves when observed at such incredible velocities. Understanding the theory of relativity involves grasping both its impact on how we perceive the world at these high speeds and its mathematical underpinnings that lead to startling predictions verified by numerous experiments.
Velocity Calculation
Velocity Calculation involves determining the speed at which an object must travel to exhibit certain relativistic effects, like length contraction. In the given exercise, we are tasked to find the velocity required for a meter stick to contract to half its length when moving relative to an observer. To achieve this, we utilize the length contraction formula: \[L = L_0 \sqrt{1 - \frac{v^2}{c^2}}\].Here, \(L\) represents the contracted length, \(L_0\) denotes the meter stick's proper length, \(v\) is its velocity, and \(c\) is the speed of light (approximately \(3 \times 10^8\) meters per second). Given that \(L\) is half of \(L_0\), substituting these values helps us measure the speed needed. Solving the equation involves rearranging it to determine \(v\), and through simple algebraic steps: First, you isolate \( \frac{v^2}{c^2} \). Then, taking the square root, you'll find \(v \approx 0.866c\). This result reveals just how quickly objects must move for relativistic effects to be noticeable, providing a clear illustration of the power and strangeness of relativity.
Einstein's Theories
Einstein's Theories fundamentally altered our understanding of physics and the universe. His theories are often split into two main areas: special relativity and general relativity. Both are crucial in understanding the behavior of objects at high speeds and within strong gravitational fields.
  • Special Relativity: This covers the scenarios when objects move at constant high speeds. It postulates that the laws of physics are the same for all non-accelerating observers and introduces the constancy of light speed. Time dilation, length contraction, and the equation \(E = mc^2\), which denotes that mass and energy are interchangeable, are products of this theory.
  • General Relativity: Expanding on special relativity, this part of Einstein's work addresses gravity, not as a force, but as a curvature of spacetime. It explains how massive objects influence spacetime, bending the paths of smaller masses and even light. This has been confirmed by phenomena such as the bending of light around stars or the orbit of Mercury.
Through these theories, Einstein provided a more comprehensive model of the universe that corrected and extended Newtonian mechanics, elegantly explaining events in both the massive and quantum realms. Understanding these concepts is essential for appreciating why and how such phenomena as length contraction occur in relativity.

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Most popular questions from this chapter

Two atomic particles approach each other in a head-on collision. Each particle has a mass of \(2.16 \times 10^{-25} \mathrm{kg} .\) The speed of each particle is \(2.10 \times 10^{8} \mathrm{m} / \mathrm{s}\) when measured by an observer standing in the laboratory. (a) What is the speed of one particle as seen by the other particle? (b) Determine the magnitude of the relativistic momentum of one particle, as it would be observed by the other.

A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed \(v=0.80 c\) relative to it. Assume that the three planets do not move relative to each other during the trip. The distance between Mars and Venus is \(1.20 \times 10^{11} \mathrm{m}\), as measured by a person on earth. (a) What does the Martian measure for the distance between Mars and Venus? (b) What is the time of the trip (in seconds) as measured by the Martian?

A radar antenna is rotating and makes one revolution every \(25 \mathrm{s}\), as measured on earth. However, instruments on a spaceship moving with respect to the earth at a speed \(v\) measure that the antenna makes one revolution every \(42 \mathrm{s}\). What is the ratio \(v / c\) of the speed \(v\) to the speed \(c\) of light in a vacuum?

Spaceships of the future may be powered by ion-propulsion engines in which ions are ejected from the back of the ship to drive it forward. In one such engine the ions are to be ejected with a speed of \(0.80 c\) relative to the spaceship. The spaceship is traveling away from the earth at a speed of \(0.70 \mathrm{c}\) relative to the earth. What is the velocity of the ions relative to the earth? Assume that the direction in which the spaceship is traveling is the positive direction, and be sure to assign the correct plus or minus signs to the velocities.

You are driving down a two-lane country road, and a truck in the opposite lane is traveling toward you. Suppose that the speed of light in a vacuum is \(c=65 \mathrm{m} / \mathrm{s}\). Determine the speed of the truck relative to you when (a) your speed is \(25 \mathrm{m} / \mathrm{s}\) and the truck's speed is \(35 \mathrm{m} / \mathrm{s}\) and (b) your speed is \(5.0 \mathrm{m} / \mathrm{s}\) and the truck's speed is \(55 \mathrm{m} / \mathrm{s}\). The speeds given in parts (a) and (b) are relative to the ground.

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