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The first-order principle maximum produced by a grating is located at an angle of \(\theta=18.0^{\circ} .\) What is the angle for the third-order maximum with the same light?

Short Answer

Expert verified
The third-order maximum angle exceeds 90°, so it doesn't exist.

Step by step solution

01

Understand the grating equation

The grating equation is given by \(d \sin \theta = m \lambda\), where \(d\) is the grating spacing, \(m\) is the order of the maximum (1st order, 2nd order, etc.), and \(\lambda\) is the wavelength of the light. We will use this equation to find the angle for higher-order maxima by knowing the first-order maximum.
02

Solve for the wavelength \(\lambda\) using the first-order maximum

For the first-order maximum (\(m = 1\)) and the given angle \(\theta = 18.0^{\circ}\), rearrange the equation to solve for \(\lambda\):\[\lambda = \frac{d \sin 18.0^{\circ}}{1}\]
03

Rearrange the formula for the third-order maximum

To find the angle for the third-order maximum, plug \(m = 3\) into the equation:\[d \sin \theta_3 = 3 \lambda\]We already know \(\lambda = d \sin 18.0^{\circ}\), so:\[d \sin \theta_3 = 3(d \sin 18.0^{\circ})\]
04

Simplify and solve for \(\sin \theta_3\)

Cancel \(d\) from both sides of the equation to obtain:\[sin \theta_3 = 3 \sin 18.0^{\circ}\]Evaluate this to find \(\sin \theta_3\).
05

Calculate \(\theta_3\) using the inverse sine

After calculating \(\sin \theta_3\), use the inverse sine function to find \(\theta_3\):\[\theta_3 = \sin^{-1}(3 \sin 18.0^{\circ})\]
06

Evaluate the limits of \(\theta_3\)

Finally, check if \(\theta_3\) is less than or equal to \(90^{\circ}\). If \(\theta_3\) exceeds \(90^{\circ}\), then the third-order maximum does not exist under normal circumstances because the path difference cannot be resolved to create a constructive interference pattern.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grating Equation
The grating equation is a key formula in understanding how light diffracts through a grating. A grating is essentially a series of closely spaced lines used to split and diffract light into several beams. The fundamental equation for a diffraction grating is given by:
  • \[ d \sin \theta = m \lambda \]
Here, \( d \) represents the spacing between the grating lines (grating spacing), \( \theta \) is the angle of the diffracted light, \( m \) is the order of the maximum (which can be 1, 2, 3, etc.), and \( \lambda \) is the wavelength of the light. This equation allows you to calculate the angle \( \theta \) at which a certain wavelength will be at its maximum intensity for a given order \( m \).

The grating equation is essential in many applications, including spectrometry and the study of light properties. By rearranging this equation, students can find different quantities like the wavelength or angle, depending on what information is provided.
Order of Maximum
In light diffraction through a grating, the term 'order of maximum' refers to the bright spots of light, formed due to constructive interference. These spots, or 'maxima', occur at specific angles where the light waves overlapping from the different slits reinforce each other, making them appear brighter.

  • The first-order maximum (\( m = 1 \)) happens at a certain angle, where light waves from adjacent slits align.
  • Similarly, the second-order maximum (\( m = 2 \)) occurs at another angle where every second wave aligns.
  • The process continues with third-order (\( m = 3 \)), fourth-order, and so on, with each order representing different angles and intensities.
Notably, higher-order maxima can potentially overlap or be too faint to observe, especially beyond a certain angle limit (typically 90 degrees). In the scenario presented, calculating up to the third order and checking its feasibility within the angles shows how far light can reinforce visibly when diffracted.
Wavelength of Light
The wavelength of light is a crucial factor in understanding how light behaves when it passes through a grating. Wavelength is the distance between successive crests of a wave, typically measured in nanometers (nm) or meters (m), and it determines how light will diffract and interfere when passing through a grating.

Using the grating equation, the wavelength of light can be determined when the angle \( \theta \), grating spacing \( d \), and order \( m \) are known:
  • For a known angle and a first-order maximum, the wavelength can be calculated by rearranging the equation: \[ \lambda = \frac{d \sin \theta}{m} \]
  • This allows for an understanding of the specific light properties through practical experimentation.
Understanding the wavelength helps determine what colors of light are visible or how a particular material affects light transmission, crucial for optical experiments and technologies such as fiber optics and lasers.

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Most popular questions from this chapter

In Young's experiment a mixture of orange light \((611 \mathrm{nm})\) and blue light \((471 \mathrm{nm})\) shines on the double slit. The centers of the first- order bright blue fringes lie at the outer edges of a screen that is located \(0.500 \mathrm{m}\) away from the slits. However, the first-order bright orange fringes fall off the screen. By how much and in which direction (toward or away from the slits) should the screen be moved so that the centers of the first-order bright orange fringes will just appear on the screen? It may be assumed that \(\theta\) is small, so that \(\sin \theta \approx \tan \theta\).

A diffraction grating is \(1.50 \mathrm{cm}\) wide and contains 2400 lines. When used with light of a certain wavelength, a third-order maximum is formed at an angle of \(18.0^{\circ} .\) What is the wavelength (in \(\mathrm{nm}\) )?

A nonreflective coating of magnesium fluoride \((n=1.38)\) covers the glass \((n=1.52)\) of a camera lens. Assuming that the coating prevents reflection of yellow-green light (wavelength in vacuum \(=565 \mathrm{nm}\) ), determine the minimum nonzero thickness that the coating can have.

In a Young's double-slit experiment, the seventh dark fringe is located \(0.025 \mathrm{m}\) to the side of the central bright fringe on a flat screen, which is \(1.1 \mathrm{m}\) away from the slits. The separation between the slits is \(1.4 \times 10^{-4} \mathrm{m}\) What is the wavelength of the light being used?

Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is \(\lambda_{\mathrm{A}}=645 \mathrm{nm} .\) The other wavelength is \(\lambda_{\mathrm{B}}\) and is unknown. On a viewing screen, the light with wavelengthV \(\lambda_{\mathrm{A}}=645 \mathrm{nm}\) produces its third-order bright fringe at the same place where the light with wavelength \(\lambda_{\mathrm{B}}\) produces its fourth dark fringe. The fringes are counted relative to the central or zeroth-order bright fringe. What is the unknown wavelength?

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