/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 An inkjet printer uses tiny dots... [FREE SOLUTION] | 91Ó°ÊÓ

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An inkjet printer uses tiny dots of red, green, and blue ink to produce an image. Assume that the dot separation on the printed page is the same for all colors. At normal viewing distances, the eye does not resolve the individual dots, regardless of color, so that the image has a normal look. The wavelengths for red, green, and blue are \(\lambda_{\text {red }}=660 \mathrm{nm}, \lambda_{\text {green }}=550 \mathrm{nm},\) and \(\lambda_{\text {blue }}=470 \mathrm{nm} .\) The diameter of the pupil through which light enters the eye is \(2.0 \mathrm{mm}\). For a viewing distance of \(0.40 \mathrm{m},\) what is the maximum allowable dot separation?

Short Answer

Expert verified
The maximum dot separation is calculated for blue light, as it has the shortest wavelength and smallest separation.

Step by step solution

01

Understand the Problem

We need to determine the maximum dot separation that allows the eye not to resolve individual dots across red, green, and blue colors at a specific viewing distance. This involves using the Rayleigh criterion for resolution.
02

Apply the Rayleigh Criterion

The Rayleigh criterion states that the angular resolution \( \theta \) is given by \( \theta = 1.22 \times \frac{\lambda}{D} \), where \( \lambda \) is the wavelength of light, and \( D \) is the diameter of the aperture (pupil in this case).We will calculate this for each color.
03

Calculate Angular Resolution for Red

First, convert the diameter of the pupil to meters: \(D = 2.0 \, \text{mm} = 2.0 \times 10^{-3} \, \text{m}\).Then calculate \( \theta_{\text{red}} \):\( \theta_{\text{red}} = 1.22 \times \frac{660 \, \text{nm}}{2.0 \times 10^{-3} \, \text{m}} = 1.22 \times \frac{660 \times 10^{-9} \, \text{m}}{2.0 \times 10^{-3} \, \text{m}} \).
04

Calculate Separation Using Red Wavelength

Use the angular resolution to find the maximum dot separation \( s \). The formula relating linear separation \( s \) to angular resolution \( \theta \) and distance \( L \) is \( s = \theta \times L \).Substitute for red light:\[ s_{\text{red}} = 1.22 \times \frac{660 \times 10^{-9}}{2.0 \times 10^{-3}} \times 0.40 \].
05

Calculate and Compare Separations for Green and Blue

Repeat the above calculation for green (\(550 \, \text{nm}\)) and blue (\(470 \, \text{nm}\)): \( \theta_{\text{green}} = 1.22 \times \frac{550 \times 10^{-9}}{2.0 \times 10^{-3}} \) and\( \theta_{\text{blue}} = 1.22 \times \frac{470 \times 10^{-9}}{2.0 \times 10^{-3}} \).Then, compute \( s \) for each color:\[ s_{\text{green}} = \theta_{\text{green}} \times 0.40 \],\[ s_{\text{blue}} = \theta_{\text{blue}} \times 0.40 \].
06

Determine Maximum Separation

The maximum allowable dot separation will correspond to the smallest calculated separation among the three colors since resolving any one color requires more precision. Calculate and compare the separations to find which is smallest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Resolution
Angular resolution is a crucial concept when understanding how our eyes perceive details at a distance. It refers to the ability to distinguish small details or objects that are close together in the line of sight.
The angular resolution is determined by the Rayleigh criterion, which states it depends on the wavelength of the observed light and the diameter of the viewing aperture, often represented by the formula:
  • \( \theta = 1.22 \times \frac{\lambda}{D} \)
Here \( \theta \) is the angular resolution in radians, \( \lambda \) is the wavelength of light, and \( D \) is the aperture diameter (in this case, the pupil of the eye).
With greater angular resolution, the eye or optical system can resolve finer details. This concept helps in calculating the ability of the human eye to differentiate between colors like red, green, and blue from a specified distance based on the wavelengths of these lights.
Wavelength of Light
Light is composed of electromagnetic waves, and each color of light has its unique wavelength. The wavelength of light affects how it interacts with materials and how it is perceived by our eyes.
Different colors have varying wavelengths:
  • Red light has a wavelength around 660 nm.
  • Green light has a wavelength around 550 nm.
  • Blue light has a wavelength around 470 nm.
In the context of resolving images or details in a scene, the wavelength is directly linked to the resolving power through the Rayleigh criterion.
Shorter wavelengths of light allow for better resolution because they reduce the angular separation \( \theta \). This is why blue light provides better resolution than red light when details are closely spaced.
Dot Separation
Dot separation is a term used often in printing and displays, referring to the physical distance between individual dots that make up an image. In this exercise, it's about maintaining a separation that allows the eye to perceive the full image clearly without noticing individual dots.
To find the maximum allowable dot separation, we use the formula that links the angular resolution to linear separation:
  • \( s = \theta \times L \)
Here \( s \) is the dot separation, \( \theta \) is the angular resolution, and \( L \) is the viewing distance.
By calculating \( \theta \) for different wavelengths (red, green, and blue), we determine which color limits the dot separation due to the smallest \( \theta \). Typically, the calculation for different colors involves determining which yields the shortest distance \( s \), ensuring no individual dots can be resolved by the human eye.
Inkjet Printer Resolution
Inkjet printers achieve images by spraying tiny droplets of ink onto paper. The resolution of an inkjet printer depends on the size, arrangement, and combination of these droplets.
Printers use a combination of colors (often red, green, and blue) to recreate various hues and shades. The fine control over dot placement and separation determines the sharpness and clarity of the printed image.
A higher printer resolution implies smaller and more closely spaced dots, resulting in finer detail in the image without noticeable individual dots.
When considering printer resolution in relation to the Rayleigh criterion, it's vital to supplement this understanding with the observer's distance from the printed page.
If the dot separation exceeds the perceptibility limit determined by the chosen wavelength and observed distance, individual dots may become visible, affecting image quality. Thus, balancing these factors is essential in printing technology to ensure clear, high-quality images.

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Most popular questions from this chapter

In a Young's double-slit experiment, two rays of monochromatic light emerge from the slits and meet at a point on a distant screen, as in Figure \(27.6 a .\) The point on the screen where these two rays meet is the eighth-order bright fringe. The difference in the distances that the two rays travel is \(4.57 \times 10^{-6} \mathrm{m} .\) What is the wavelength (in \(\mathrm{nm}\) ) of the monochromatic light?

Late one night on a highway, a car speeds by you and fades into the distance. Under these conditions the pupils of your eyes have diameters of about \(7.0 \mathrm{mm}\). The taillights of this car are separated by a distance of \(1.2 \mathrm{m}\) and emit red light (wavelength \(=660 \mathrm{nm}\) in vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction?

In a single-slit diffraction pattern, the central fringe is 450 times as wide as the slit. The screen is 18000 times farther from the slit than the slit is wide. What is the ratio \(\lambda / W,\) where \(\lambda\) is the wavelength of the light shining through the slit and \(W\) is the width of the slit? Assume that the angle that locates a dark fringe on the screen is small, so that \(\sin \theta \approx \tan \theta\)

A transparent film \((n=1.43)\) is deposited on a glass plate \((n=1.52)\) to form a nonreflecting coating. The film has a thickness that is \(1.07 \times 10^{-7} \mathrm{m} .\) What is the longest possible wavelength (in vacuum) of light for which this film has been designed?

(a) As Section 17.3 discusses, high-frequency sound waves exhibit less diffraction than low-frequency sound waves do. However, even highfrequency sound waves exhibit much more diffraction under normal circumstances than do light waves that pass through the same opening. The highest frequency that a healthy ear can typically hear is \(2.0 \times 10^{4} \mathrm{Hz}\) Assume that a sound wave with this frequency travels at \(343 \mathrm{m} / \mathrm{s}\) and passes through a doorway that has a width of \(0.91 \mathrm{m}\). Determine the angle that locates the first minimum to either side of the central maximum in the diffraction pattern for the sound. This minimum is equivalent to the first dark fringe in a single-slit diffraction pattern for light. (b) Suppose that yellow light (wavelength \(=580 \mathrm{nm}\) in vacuum) passes through a doorway and that the first dark fringe in its diffraction pattern is located at the angle determined in part (a). How wide would this hypothetical doorway have to be?

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