/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 An inkjet printer uses tiny dots... [FREE SOLUTION] | 91Ó°ÊÓ

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An inkjet printer uses tiny dots of red, green, and blue ink to produce an image. Assume that the dot separation on the printed page is the same for all colors. At normal viewing distances, the eye does not resolve the individual dots, regardless of color, so that the image has a normal look. The wavelengths for red, green, and blue are \(\lambda_{\text {red }}=660 \mathrm{nm}, \lambda_{\text {green }}=550 \mathrm{nm},\) and \(\lambda_{\text {blue }}=470 \mathrm{nm} .\) The diameter of the pupil through which light enters the eye is \(2.0 \mathrm{mm}\). For a viewing distance of \(0.40 \mathrm{m},\) what is the maximum allowable dot separation?

Short Answer

Expert verified
The maximum dot separation is calculated for blue light, as it has the shortest wavelength and smallest separation.

Step by step solution

01

Understand the Problem

We need to determine the maximum dot separation that allows the eye not to resolve individual dots across red, green, and blue colors at a specific viewing distance. This involves using the Rayleigh criterion for resolution.
02

Apply the Rayleigh Criterion

The Rayleigh criterion states that the angular resolution \( \theta \) is given by \( \theta = 1.22 \times \frac{\lambda}{D} \), where \( \lambda \) is the wavelength of light, and \( D \) is the diameter of the aperture (pupil in this case).We will calculate this for each color.
03

Calculate Angular Resolution for Red

First, convert the diameter of the pupil to meters: \(D = 2.0 \, \text{mm} = 2.0 \times 10^{-3} \, \text{m}\).Then calculate \( \theta_{\text{red}} \):\( \theta_{\text{red}} = 1.22 \times \frac{660 \, \text{nm}}{2.0 \times 10^{-3} \, \text{m}} = 1.22 \times \frac{660 \times 10^{-9} \, \text{m}}{2.0 \times 10^{-3} \, \text{m}} \).
04

Calculate Separation Using Red Wavelength

Use the angular resolution to find the maximum dot separation \( s \). The formula relating linear separation \( s \) to angular resolution \( \theta \) and distance \( L \) is \( s = \theta \times L \).Substitute for red light:\[ s_{\text{red}} = 1.22 \times \frac{660 \times 10^{-9}}{2.0 \times 10^{-3}} \times 0.40 \].
05

Calculate and Compare Separations for Green and Blue

Repeat the above calculation for green (\(550 \, \text{nm}\)) and blue (\(470 \, \text{nm}\)): \( \theta_{\text{green}} = 1.22 \times \frac{550 \times 10^{-9}}{2.0 \times 10^{-3}} \) and\( \theta_{\text{blue}} = 1.22 \times \frac{470 \times 10^{-9}}{2.0 \times 10^{-3}} \).Then, compute \( s \) for each color:\[ s_{\text{green}} = \theta_{\text{green}} \times 0.40 \],\[ s_{\text{blue}} = \theta_{\text{blue}} \times 0.40 \].
06

Determine Maximum Separation

The maximum allowable dot separation will correspond to the smallest calculated separation among the three colors since resolving any one color requires more precision. Calculate and compare the separations to find which is smallest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Resolution
Angular resolution is a crucial concept when understanding how our eyes perceive details at a distance. It refers to the ability to distinguish small details or objects that are close together in the line of sight.
The angular resolution is determined by the Rayleigh criterion, which states it depends on the wavelength of the observed light and the diameter of the viewing aperture, often represented by the formula:
  • \( \theta = 1.22 \times \frac{\lambda}{D} \)
Here \( \theta \) is the angular resolution in radians, \( \lambda \) is the wavelength of light, and \( D \) is the aperture diameter (in this case, the pupil of the eye).
With greater angular resolution, the eye or optical system can resolve finer details. This concept helps in calculating the ability of the human eye to differentiate between colors like red, green, and blue from a specified distance based on the wavelengths of these lights.
Wavelength of Light
Light is composed of electromagnetic waves, and each color of light has its unique wavelength. The wavelength of light affects how it interacts with materials and how it is perceived by our eyes.
Different colors have varying wavelengths:
  • Red light has a wavelength around 660 nm.
  • Green light has a wavelength around 550 nm.
  • Blue light has a wavelength around 470 nm.
In the context of resolving images or details in a scene, the wavelength is directly linked to the resolving power through the Rayleigh criterion.
Shorter wavelengths of light allow for better resolution because they reduce the angular separation \( \theta \). This is why blue light provides better resolution than red light when details are closely spaced.
Dot Separation
Dot separation is a term used often in printing and displays, referring to the physical distance between individual dots that make up an image. In this exercise, it's about maintaining a separation that allows the eye to perceive the full image clearly without noticing individual dots.
To find the maximum allowable dot separation, we use the formula that links the angular resolution to linear separation:
  • \( s = \theta \times L \)
Here \( s \) is the dot separation, \( \theta \) is the angular resolution, and \( L \) is the viewing distance.
By calculating \( \theta \) for different wavelengths (red, green, and blue), we determine which color limits the dot separation due to the smallest \( \theta \). Typically, the calculation for different colors involves determining which yields the shortest distance \( s \), ensuring no individual dots can be resolved by the human eye.
Inkjet Printer Resolution
Inkjet printers achieve images by spraying tiny droplets of ink onto paper. The resolution of an inkjet printer depends on the size, arrangement, and combination of these droplets.
Printers use a combination of colors (often red, green, and blue) to recreate various hues and shades. The fine control over dot placement and separation determines the sharpness and clarity of the printed image.
A higher printer resolution implies smaller and more closely spaced dots, resulting in finer detail in the image without noticeable individual dots.
When considering printer resolution in relation to the Rayleigh criterion, it's vital to supplement this understanding with the observer's distance from the printed page.
If the dot separation exceeds the perceptibility limit determined by the chosen wavelength and observed distance, individual dots may become visible, affecting image quality. Thus, balancing these factors is essential in printing technology to ensure clear, high-quality images.

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Most popular questions from this chapter

A soap film \((n=1.33)\) is \(375 \mathrm{nm}\) thick and coats a flat piece of glass \((n=1.52) .\) Thus, air is on one side of the film and glass is on the other side, as the figure illustrates. Sunlight, whose wavelengths (in vacuum) extend from 380 to \(750 \mathrm{nm},\) travels through air and strikes the film nearly perpendicularly. Concepts: (i) What, if any, phase change occurs when light, traveling in air, reflects from the air-film interface? (ii) What, if any, phase change occurs when light, traveling in the film, reflects from the film-glass interface? (iii) Is the wavelength of the light in the film greater than, smaller than, or equal to the wavelength in a vacuum? Calculations: For what wavelengths in the range of 380 to 750 nm does constructive interference cause the film to look bright in reflected light?

In a Young's double-slit experiment, two rays of monochromatic light emerge from the slits and meet at a point on a distant screen, as in Figure \(27.6 a .\) The point on the screen where these two rays meet is the eighth-order bright fringe. The difference in the distances that the two rays travel is \(4.57 \times 10^{-6} \mathrm{m} .\) What is the wavelength (in \(\mathrm{nm}\) ) of the monochromatic light?

In Young's experiment a mixture of orange light \((611 \mathrm{nm})\) and blue light \((471 \mathrm{nm})\) shines on the double slit. The centers of the first- order bright blue fringes lie at the outer edges of a screen that is located \(0.500 \mathrm{m}\) away from the slits. However, the first-order bright orange fringes fall off the screen. By how much and in which direction (toward or away from the slits) should the screen be moved so that the centers of the first-order bright orange fringes will just appear on the screen? It may be assumed that \(\theta\) is small, so that \(\sin \theta \approx \tan \theta\).

A flat observation screen is placed at a distance of \(4.5 \mathrm{m}\) from a pair of slits. The separation on the screen between the central bright fringe and the first-order bright fringe is \(0.037 \mathrm{m} .\) The light illuminating the slits has a wavelength of \(490 \mathrm{nm} .\) Determine the slit separation.

A hunter who is a bit of a braggart claims that from a distance of \(1.6 \mathrm{km}\) he can selectively shoot either of two squirrels who are sitting ten centimeters apart on the same branch of a tree. What's more, he claims that he can do this without the aid of a telescopic sight on his rifle. (a) Determine the diameter of the pupils of his eyes that would be required for him to be able to resolve the squirrels as separate objects. In this calculation use a wavelength of \(498 \mathrm{nm}\) (in vacuum) for the light. (b) State whether his claim is reasonable, and provide a reason for your answer. In evaluating his claim, consider that the human eye automatically adjusts the diameter of its pupil over a typical range of 2 to \(8 \mathrm{mm},\) the larger values coming into play as the lighting becomes darker. Note also that under dark conditions, the eye is most sensitive to a wavelength of 498 nm.

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