/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 A farsighted man uses eyeglasses... [FREE SOLUTION] | 91Ó°ÊÓ

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A farsighted man uses eyeglasses with a refractive power of 3.80 diopters. Wearing the glasses \(0.025 \mathrm{m}\) from his eyes, he is able to read books held no closer than \(0.280 \mathrm{m}\) from his eyes. He would like a prescription for contact lenses to serve the same purpose. What is the correct contact lens prescription, in diopters?

Short Answer

Expert verified
The contact lens prescription is approximately 3.92 diopters.

Step by step solution

01

Understand Refractive Power and Lens Formula

Refractive power (denoted as \( P \)) is measured in diopters, and it is the inverse of the focal length \( f \) (in meters). Hence, \( P = \frac{1}{f} \). For glasses, the total effective focal length must account for the distance to the eye.
02

Determine Focal Length of the Eyeglasses

Given the refractive power of the eyeglasses \( P = 3.80 \) diopters, the focal length \( f_g \) is calculated as \( f_g = \frac{1}{P} = \frac{1}{3.80} \approx 0.2632 \mathrm{m} \).
03

Calculate Effective Lens Placement without Distance

The effective focal length considering the distance of 0.025 m from the eye (where his eyes meet the book at no closer than 0.280 m) needs to be recalculated considering this distance. The new eye-to-lens system focal length \( f_s \) considers the reading distance as well. So, the focal length needed is \( f_s = 0.280 - 0.025 = 0.255 \mathrm{m} \).
04

Calculate the Contact Lens Power

For contact lenses that sit directly on the eye, no additional distance needs to be subtracted. Thus, the focal length \( f_c \) should simply allow the man to read objects 0.255 m away. Calculate the power of the contact lens: \( P_c = \frac{1}{f_s} = \frac{1}{0.255} \approx 3.92 \) diopters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diopters
When we talk about diopters, we're actually referring to a measure of the refractive power needed for lenses like glasses and contacts. The strength of a lens needed to correct vision issues is measured in these units. The higher the diopter, the stronger the prescription needed to correct vision.
A positive diopter value, like the +3.80 example, indicates lenses used to correct farsightedness or hyperopia. These lenses help bring close objects into focus by converging light before it reaches the eye.
Diopters are crucial in helping optometrists and ophthalmologists determine the exact extent of a patient's vision deficiency and provide them with the perfect lens strength. It's a practical way to quantitatively address vision correction.
Focal Length
The focal length is the distance between the lens and the point where it focuses light. For any lens, this is a critical measurement, as it determines how the lens converges or diverges light.
Lenses converge or diverge light to help us focus on images, and this distance can be measured in meters. The formula, connecting focal length to refractive power, is given by:
  • \( P = \frac{1}{f} \)
Where \( P \) stands for refractive power and \( f \) is the focal length. For example, a refractive power of 3.80 diopters gives a focal length of approximately 0.2632 meters, meaning that light is focused at that distance from the lens.
Contact Lenses Prescription
Contact lenses serve a similar function to eyeglasses but sit directly on the surface of the eye. Because they have no distance from the eye to account for, the focal length needed is different compared to glasses.
In the given exercise, the man can read at a distance of 0.280 meters wearing glasses positioned 0.025 meters away. With contacts, you simply need to adjust the focal length to this reading distance, leading to a needed contact lens power of approximately 3.92 diopters.
To determine the proper prescription, one subtracts the lens-to-eye distance considered in glasses and reevaluates the lens power. This ensures the contact lenses provide the same visual clarity.
Lens Formula
The lens formula is a fundamental component in optics, helping to compute the power of lenses based on given distances and conditions. This formula is especially essential in adjusting prescriptions between glasses and contact lenses.
The basic lens formula to find the refractive power is:
  • \( P = \frac{1}{f} \)
Where \( P \) is the lens power in diopters, and \( f \) represents the focal length in meters. In practice, it allows us to adapt the corrective power necessary when switching from glasses to contact lenses. The key is in utilizing the correct focal length based on the actual distance from the eye, adjusting for any change in lens position.

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Most popular questions from this chapter

A camera uses a lens with a focal length of \(0.0500 \mathrm{m}\) and can take clear pictures of objects no closer to the lens than \(0.500 \mathrm{m}\). For closer objects the camera records only blurred images. However, the camera could be used to record a clear image of an object located \(0.200 \mathrm{m}\) from the lens, if the distance between the image sensor and the lens were increased. By how much would this distance need to be increased?

A glass block \((n=1.56)\) is immersed in a liquid. A ray of light within the glass hits a glass-liquid surface at a \(75.0^{\circ}\) angle of incidence. Some of the light enters the liquid. What is the smallest possible refractive index for the liquid?

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