/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 An object is located \(9.0 \math... [FREE SOLUTION] | 91Ó°ÊÓ

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An object is located \(9.0 \mathrm{cm}\) in front of a converging lens \((f=6.0 \mathrm{cm}) .\) Using an accurately drawn ray diagram, determine where the image is located.

Short Answer

Expert verified
The image is located 18 cm behind the lens.

Step by step solution

01

Understanding the Lens Formula

The lens formula is given by \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where \( f \) is the focal length of the lens, \( d_o \) is the object distance, and \( d_i \) is the image distance. For our problem, \( f = 6.0 \text{ cm} \) and \( d_o = 9.0 \text{ cm} \).
02

Substituting the Known Values

Substitute the given values into the lens formula: \( \frac{1}{6} = \frac{1}{9} + \frac{1}{d_i} \).
03

Simplifying the Equation

Simplify the equation \( \frac{1}{6} = \frac{1}{9} + \frac{1}{d_i} \) by finding a common denominator for \( \frac{1}{6} \) and \( \frac{1}{9} \), which is 18. This gives us \( \frac{3}{18} = \frac{2}{18} + \frac{1}{d_i} \).
04

Solving for Image Distance \( d_i \)

Rearrange and solve for \( \frac{1}{d_i} \) to get \( \frac{1}{d_i} = \frac{3}{18} - \frac{2}{18} = \frac{1}{18} \). Thus, \( d_i = 18 \text{ cm} \).
05

Interpreting the Solution

The positive value of \( d_i = 18 \text{ cm} \) indicates that the image is formed on the opposite side of the lens, making it a real image.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lens Formula
The lens formula is an essential tool in optics, used to relate the focal length, object distance, and image distance of a lens. This formula is defined as: \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \). In this equation:
  • \( f \) is the focal length of the lens.
  • \( d_o \) is the distance from the object to the lens, known as the object distance.
  • \( d_i \) is the distance from the image to the lens, known as the image distance.
For converging lenses, a positive focal length indicates the focal point is on the same side as the outgoing rays. When solving problems, the key is to appropriately substitute values and solve for the unknown variable. This formula helps determine where the image is formed when an object is placed in front of a lens.
Ray Diagram
A ray diagram is a graphical method to find the position and size of the image formed by a lens. It visually represents how light travels through the lens. To construct a ray diagram for a converging lens, follow these steps:
  • Draw the principal axis, a straight horizontal line that passes through the center of the lens.
  • Indicate the focal point on either side of the lens.
  • From the top of the object, draw a ray parallel to the principal axis. After passing through the lens, make this ray pass through the focal point on the opposite side.
  • Draw another ray through the center of the lens, continuing straight across without bending.
  • The intersection of these two rays on the opposite side of the lens demarks the image location.
This method is an intuitive way to visualize the path light rays take and how they converge to form an image. While approximating, this also verifies the calculation using the lens formula.
Focal Length
Focal length \((f)\) is a fundamental property of a lens that measures its ability to converge or diverge light. It is the distance from the lens to the focal point, where parallel rays of light converge or appear to diverge. For a converging lens, which is thicker in the middle and thinner at the edges, the focal length is positive. When dealing with converging lenses, these lenses focus parallel incoming light rays to a single point known as the focal point. The focal length influences how powerful the lens is in bending light rays. A shorter focal length means stronger convergence of light, resulting in a magnified image. This property plays a crucial role in various optical devices like cameras and corrective lenses.
Image Distance
Image distance \((d_i)\) refers to the distance from the image formed by the lens to the lens itself. Using the lens formula, after substituting the known values and solving, you can determine where the image will appear relative to the lens.In the given exercise, the image distance was calculated as \(18\, \text{cm}\), indicating a real image formed on the opposite side of the lens.
  • A real image implies that the light rays actually converge at the image location.
  • Real images can be projected onto a screen since the light rays physically meet at a point.
  • In contrast, virtual images are formed where rays appear to converge.
Understanding the concept of image distance helps in predicting the behavior of images produced by lenses, whether they will be real or virtual and the characteristics such as image orientation and size.

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Most popular questions from this chapter

A converging lens \((f=25.0 \mathrm{cm})\) is used to project an image of an object onto a screen. The object and the screen are \(125 \mathrm{cm}\) apart, and between them the lens can be placed at either of two locations. Find the two object distances.

An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one- half the size of the object. The distance between the object and the image is \(90.0 \mathrm{cm} .\) (a) How far from the lens is the object? (b) What is the focal length of the lens?

A filmmaker wants to achieve an interesting visual effect by filming a scene through a converging lens with a focal length of \(50.0 \mathrm{m}\). The lens is placed between the camera and a horse, which canters toward the camera at a constant speed of \(7.0 \mathrm{m} / \mathrm{s} .\) The camera starts rolling when the horse is \(40.0 \mathrm{m}\) from the lens. Find the average speed of the image of the horse (a) during the first \(2.0 \mathrm{s}\) after the camera starts rolling and (b) during the following \(2.0 \mathrm{s}\).

A point source of light is submerged \(2.2 \mathrm{m}\) below the surface of a lake and emits rays in all directions. On the surface of the lake, directly above the source, the area illuminated is a circle. What is the maximum radius that this circle could have?

Visitors at a science museum are invited to sit in a chair to the right of a full-length diverging lens \(\left(f_{1}=-3.00 \mathrm{m}\right)\) and observe a friend sitting in a second chair, \(2.00 \mathrm{m}\) to the left of the lens. The visitor then presses a button and a converging lens \(\left(f_{2}=+4.00 \mathrm{m}\right)\) rises from the floor to a position \(1.60 \mathrm{m}\) to the right of the diverging lens, allowing the visitor to view the friend through both lenses at once. Find (a) the magnification of the friend when viewed through the diverging lens only and (b) the overall magnification of the friend when viewed through both lenses. Be sure to include the algebraic signs \((+\) or \(-)\) with your answers.

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