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An object is placed \(11 \mathrm{cm}\) in front of a concave mirror whose focal length is \(18 \mathrm{cm} .\) The object is \(3.0 \mathrm{cm}\) tall. Using a ray diagram drawn to scale, measure (a) the location and (b) the height of the image. The mirror must be drawn to scale.

Short Answer

Expert verified
The image is located 22 cm away from the mirror and is 6 cm tall.

Step by step solution

01

Understand the Problem

We have an object placed in front of a concave mirror, and we are given the object distance (\(u = -11 \text{ cm}\)), the focal length of the mirror (\(f = -18 \text{ cm}\)), and the object height (\(h_o = 3.0 \text{ cm}\)). We need to find the image location and height using a ray diagram.
02

Draw the Principal Axis

Draw a horizontal line to represent the principal axis of the concave mirror. Indicate the position of the focal point (F) at 18 cm from the vertex on the concave side and the center of curvature (C) at twice the focal length (36 cm).
03

Position the Mirror and Object

Draw a concave mirror with its vertex on the principal axis. Mark the object's position 11 cm from the mirror's vertex on the principal axis and represent the object with a 3 cm vertical arrow, standing upright to scale.
04

Draw the Ray Diagram

Draw at least two principal rays from the top of the object: 1. A ray parallel to the principal axis, reflecting through the focal point (F). 2. A ray through the center of curvature (C) reflecting back on itself. The intersection of these reflected rays gives the location of the image.
05

Measure the Image Location

Measure the distance from the mirror to the point where the rays intersect. This gives the image distance (\(v\)). Since the intersection is on the same side as the object, the image is real and inverted.
06

Calculate Image Height

Use the ratio of distances to find the image height (\(h_i\)). The magnification (\(m = \frac{v}{u}\)) gives \(h_i = m \times h_o\), where \(h_o = 3.0 \text{ cm}\). Measure or calculate \(h_i\) based on the ray diagram.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Image Formation
In concave mirrors, image formation occurs when light rays, after reflecting from the mirror, either converge to form a real image or appear to diverge from a virtual image. When the object is placed in front of a concave mirror, several lines known as principal rays can be drawn to determine the position and nature of the image.

To construct a ray diagram for image formation:
  • Draw a ray parallel to the principal axis that reflects through the focal point.
  • Draw a ray through the center of curvature that reflects back on itself.
The intersection of these two rays (for real images) or their virtual extension (for virtual images) is where the image forms. Real images are formed on the same side as the object, while virtual images form on the opposite side. In our exercise, since the object is placed in front of a concave mirror and the rays meet, a real inverted image is formed.
Focal Length
The focal length of a mirror is the distance from the mirror's surface to its focal point. This is where light rays converge after reflection from the mirror. For a concave mirror, the focal length is considered negative due to the direction of reflection.The focal length (\(f\)) in our exercise is given as \(-18 \, \text{cm}\), an essential value that influences where images are formed relative to the mirror. By knowing the focal length, along with the object distance, you can use the mirror equation \(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\) to find unknown variables like the image distance, \(v\). Measuring or determining the focal length accurately helps in predicting the behavior of light in optical setups and aids in constructing precise ray diagrams.
Magnification
Magnification in the context of mirrors describes how much larger or smaller an image is compared to the object itself. It is determined by the ratio of the image height to the object height and is also related to the image distance and object distance.The formula for magnification (\(m\)) is:\[ m = \frac{h_i}{h_o} = \frac{v}{u} \]where \(h_i\) is the image height and \(h_o\) is the object height. A magnification greater than 1 indicates an enlarged image, while less than 1 represents a reduced image. For the given exercise, the calculated magnification helps students understand how the image compares in size to the original object, reinforcing the concept of image formation in optical systems.
Reflection of Light
Reflection of light involves the bouncing back of light rays when they hit a reflective surface, such as a mirror. In concave mirrors, this principle is crucial for forming images. The law of reflection states that the angle of incidence equals the angle of reflection. Concave mirrors have a curved reflective surface, causing parallel incoming rays to converge at the focal point after reflection, due to their curved geometry. This property is utilized in many applications like telescopes and headlights. Understanding reflection of light helps in drawing accurate ray diagrams, predicting where rays will converge, and ultimately visualizing where an image will appear. This forms the foundation for solving problems involving concave mirrors, such as the exercise we are analyzing.

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Most popular questions from this chapter

An object is placed in front of a convex mirror, and the size of the image is one-fourth that of the object. What is the ratio \(d_{\mathrm{o}} / f\) of the object distance to the focal length of the mirror?

An object is located \(7.0 \mathrm{cm}\) in front of a mirror. The virtual image is located \(4.5 \mathrm{cm}\) away from the mirror and is smaller than the object. Concepts: (i) Based solely on the fact that the image is virtual, is the mirror concave or convex, or is either type possible? (ii) The image is smaller than the object, as well as virtual. Do these characteristics together indicate a concave or convex mirror, or is either type possible? (iii) Is the focal length positive or negative? Explain. Calculation: Find the focal length of the mirror.

A concave mirror has a focal length of \(12 \mathrm{cm} .\) This mirror forms an image located \(36 \mathrm{cm}\) in front of the mirror. What is the magnification of the mirror?

An object is located \(14.0 \mathrm{cm}\) in front of a convex mirror, the image being \(7.00 \mathrm{cm}\) behind the mirror. A second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. The image of this second object has the same height as the other image. How far in front of the mirror is the second object located?

A spacecraft is in a circular orbit about the moon, \(1.22 \times 10^{5} \mathrm{m}\) above its surface. The speed of the spacecraft is \(1620 \mathrm{m} / \mathrm{s}\), and the radius of the moon is \(1.74 \times 10^{6} \mathrm{m} .\) If the moon were a smooth, reflective sphere, (a) how far below the moon's surface would the image of the spacecraft appear, and (b) what would be the apparent speed of the spacecraft's image? (Hint: Both the spacecraft and its image have the same angular speed about the center of the moon.)

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