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A beam of polarized light with an average intensity of \(15 \mathrm{W} / \mathrm{m}^{2}\) is sent through a polarizer. The transmission axis makes an angle of \(25^{\circ}\) with respect to the direction of polarization. Determine the rms value of the electric field of the transmitted beam.

Short Answer

Expert verified
The rms value of the electric field for the transmitted beam is approximately 68.3 V/m.

Step by step solution

01

Understand the Relationship Between Intensity and Electric Field

The intensity of electromagnetic waves is related to the root mean square (rms) value of the electric field by the formula:\[ I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2 \]where\( I \) is the intensity,\( c \) is the speed of light (approximately \(3 \times 10^8 \text{ m/s}\)),\( \varepsilon_0 \) is the permittivity of free space (approximately \(8.85 \times 10^{-12} \text{ F/m}\)),and \( E_{\text{rms}} \) is the root mean square of the electric field.
02

Apply Malus' Law to Determine Transmitted Intensity

Malus' Law describes how the intensity of polarized light changes as it passes through a polarizer. It states that\[ I = I_0 \cos^2(\theta) \]where \( I_0 \) is the initial intensity (15 \text{ W/m}^2),and \( \theta \) is the angle between the light's polarization direction and the transmission axis (25°).
03

Calculate Transmitted Intensity

Plug the given values into Malus' Law:\[ I = 15 \cos^2(25°) \]Calculate \( \cos(25°) \) and then square the result:\[ \cos(25°) \approx 0.906 \]\[ \cos^2(25°) \approx 0.821 \]Thus,\[ I = 15 \times 0.821 \approx 12.315 \text{ W/m}^2 \]
04

Relate Transmitted Intensity to Electric Field

Now, use the equation from Step 1 to find \( E_{\text{rms}} \):Rearrange the intensity equation for electric field:\[ I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2 \]\[ E_{\text{rms}} = \sqrt{\frac{2I}{c \varepsilon_0}} \]
05

Substitute Known Values and Solve for Electric Field

Substitute \( I = 12.315 \text{ W/m}^2 \), \( c = 3 \times 10^8 \text{ m/s} \), and \( \varepsilon_0 = 8.85 \times 10^{-12} \text{ F/m} \):\[ E_{\text{rms}} = \sqrt{\frac{2 \times 12.315}{3 \times 10^8 \times 8.85 \times 10^{-12}}} \]Calculate to find the rms value:\[ E_{\text{rms}} \approx 68.3 \text{ V/m} \]
06

Interpret the Result

The root mean square value of the electric field for the transmitted beam is approximately 68.3 V/m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus' Law
Malus' Law is an essential concept for understanding how polarized light behaves when it passes through a polarizer. It predicts the intensity reduction of light based on the angle between the light's polarization direction and the polarizer's transmission axis. According to Malus' Law, the transmitted intensity \( I \) is given by the formula:
  • \( I = I_0 \cos^2(\theta) \)
Here, \( I_0 \) represents the initial intensity of the light before it encounters the polarizer, and \( \theta \) is the angle between the light's polarization direction and the transmission axis of the polarizer.
By applying the cosine square of this angle, we calculate how much light is permitted to pass through. For instance, when light polarized at a certain angle (like 25°) hits the polarizer, its intensity diminishes according to this principle. In our example, applying Malus' Law to light with an intensity of 15 W/m² results in a reduced transmitted intensity of approximately 12.315 W/m².
Understanding Malus' Law helps in grasping the quantitative changes in light intensity after polarization.
Root Mean Square (RMS) Value
The root mean square (RMS) value is a measure of the effective or average magnitude of a varying electric field. In the context of electromagnetic waves, the RMS value of the electric field (\( E_{\text{rms}} \)) is crucial for linking intensity and electric fields. The relationship between intensity \( I \) and the RMS value of the electric field is presented by the formula:
  • \( I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2 \)
Here,
  • \( c \) is the speed of light, approximately \(3 \times 10^8\) m/s
  • \( \varepsilon_0 \) is the permittivity of free space, about \(8.85 \times 10^{-12} \) F/m
This formula helps in deriving the RMS value by rearranging and solving for \( E_{\text{rms}} \). In practice, knowing the RMS value of an electric field provides us with an understanding of how strong the field is, which is crucial in numerous applications of light and wave technology.
For the given exercise, the transmitted light results in an \( E_{\text{rms}} \) of approximately 68.3 V/m.
Intensity of Electromagnetic Waves
The intensity of electromagnetic waves measures the power per unit area carried by the waves. It is usually represented as \( I \) and is related to the amplitude of the electric and magnetic fields in the wave. For light waves, the intensity can change when the light interacts with materials such as polarizers.
In the formula \( I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2 \), intensity depends on several factors:
  • \( E_{\text{rms}} \): shows how strong the wave's electric field is.
  • \( c \): speed of light.
  • \( \varepsilon_0 \): permittivity of free space.
Understanding intensity is important for predicting and controlling how waves propagate through different media and interact with devices and objects.
Light intensity before passing through a polarizer reflects the full power of the beam, but after applying Malus' Law, intensity declines. In our study case, light with an intensity of 15 W/m² becomes approximately 12.315 W/m² after passing through the polarizer at a 25° angle.
Polarizer Transmission Axis
The transmission axis of a polarizer determines how much polarized light is allowed to pass through. It's an imaginary line along which the electric fields of the light waves are aligned when they exit the polarizer. When polarized light hits a polarizer, the angle between its initial direction and the transmission axis dictates the intensity of the light that successfully passes through.
This concept ties tightly with Malus' Law, where the angle between the light's polarization direction and the transmission axis (\( \theta \)) is crucial. A smaller angle allows more light to pass through, while at larger angles, the transmitted intensity decreases. In our case, the transmission axis forms a 25° angle with the original light polarization, requiring us to compute the change in intensity by using \( \cos^2(25°) \).
The knowledge of the polarizer transmission axis is pivotal in numerous applications, from sunglasses reducing glare to advanced scientific instruments minimizing unwanted light interference, as light behavior is altered directly depending on this axis.

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Most popular questions from this chapter

The maximum strength of the magnetic field in an electromagnetic wave is \(3.3 \times 10^{-6} \mathrm{T}\). What is the maximum strength of the wave's electric field?

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