/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 On a cloudless day, the sunlight... [FREE SOLUTION] | 91Ó°ÊÓ

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On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about \(1.0 \times 10^{3} \mathrm{W} / \mathrm{m}^{2} .\) What is the electromagnetic energy contained in \(5.5 \mathrm{m}^{3}\) of space just above the earth's surface?

Short Answer

Expert verified
The electromagnetic energy is approximately \(1.83 \times 10^{-5} \ \mathrm{J}\).

Step by step solution

01

Understanding the Concepts

We need to find the electromagnetic energy contained in a given volume. The intensity of sunlight is given, which represents power per unit area. We can relate this to energy density to find the energy in a specified volume.
02

Relating Intensity and Energy Density

The intensity \(I\) of electromagnetic waves is related to the energy density \(u\) by the speed of light \(c\). The relationship is \(I = u \times c\). Given \(I = 1.0 \times 10^{3} \ \mathrm{W/m}^{2}\), we use this formula to find \(u\).
03

Calculating Energy Density

Rearrange the formula \(I = u \times c\) to solve for \(u\):\[u = \frac{I}{c}\]Substitute \(I = 1.0 \times 10^{3} \ \mathrm{W/m}^{2}\) and \(c = 3.0 \times 10^{8} \ \mathrm{m/s}\):\[u = \frac{1.0 \times 10^{3}}{3.0 \times 10^{8}} = 3.33 \times 10^{-6} \ \mathrm{J/m}^{3}\]
04

Calculating the Total Energy

The energy \(E\) in a volume can be found using the energy density \(u\):\[E = u \times V\]Where \(V = 5.5 \ \mathrm{m}^{3}\). Substitute the values:\[E = 3.33 \times 10^{-6} \times 5.5 = 1.83 \times 10^{-5} \ \mathrm{J}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intensity of Sunlight
The intensity of sunlight is an essential measure in understanding how much solar power reaches the Earth's surface. On a clear day, this intensity is roughly given as \(1.0 \times 10^{3} \ \mathrm{W/m}^{2}\). This value represents the amount of power received per unit area from the sun. This large amount of energy supports various biological and ecological processes on Earth.
However, intensity is not only significant for natural processes but is also crucial for harnessing solar power in technology. It is a key value to consider when calculating how much energy solar panels can capture and convert into electricity.
Understanding the intensity helps us gauge the potential of solar energy in various environmental and geographical settings, thus aiding in effective energy planning and development.
Energy Density
Energy density is a measure of how much electromagnetic energy is present in a unit volume of space. It is closely related to intensity, being derived from it using the speed of light. To relate the intensity \(I\) and energy density \(u\), we use the equation:
\[I = u \times c\] where \(c\) is the speed of light (approximately \(3.0 \times 10^{8} \ \mathrm{m/s}\)).
This relationship is essential because it provides a direct way to calculate how much energy is contained within a certain space by using known values of light intensity.
For example, if we know the intensity of sunlight, we can find the energy density, which then helps us determine how much energy is in a set volume, like a cube of space right at the surface of the Earth.
Speed of Light
The speed of light, denoted as \(c\), is a fundamental constant in physics. It has a value of approximately \(3.0 \times 10^{8} \ \mathrm{m/s}\), making it the fastest speed at which information or energy can travel. This constant is not only crucial in optics and general physics but also plays a pivotal role in electromagnetic theory.
In the context of electromagnetic energy, the speed of light serves as the factor that links intensity \(I\) to energy density \(u\), in the equation:
\[I = u \times c\]This equation illustrates how light's speed determines the distribution and flux of electromagnetic energy through space. Understanding the speed of light helps students grasp why changes in energy density directly affect sunlight intensity observed at any given point.
Volume Calculation
Calculating volume is a fundamental part of determining how much electromagnetic energy resides in a certain space. In physics problems, volume calculations often come into play when dealing with the spatial distribution of energy and matter.
Volume, denoted as \(V\), represents the three-dimensional space occupied by an object or substance. When you know the energy density \(u\), the total energy \(E\) in a certain space or volume can be calculated as:
\[E = u \times V\]For practical applications, like the problem of sunlight energy, knowing the volume of space (e.g., \(5.5 \ \mathrm{m}^{3}\) in the original problem), lets us calculate the total energy contained within that space given its energy density. This approach is critical for various calculations in physics and engineering, where energy quantification is needed for design and analysis purposes.

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Most popular questions from this chapter

The average intensity of light emerging from a polarizing sheet is \(0.764 \mathrm{W} / \mathrm{m}^{2},\) and the average intensity of the horizontally polarized light incident on the sheet is \(0.883 \mathrm{W} / \mathrm{m}^{2} .\) Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

A flat coil of wire is used with an \(L C\) -tuned circuit as a receiving antenna. The coil has a radius of \(0.25 \mathrm{m}\) and consists of 450 turns. The transmitted radio wave has a frequency of \(1.2 \mathrm{MHz}\). The magnetic field of the wave is parallel to the normal to the coil and has a maximum value of \(2.0 \times 10^{-13} \mathrm{T}\). Using Faraday's law of electromagnetic induction and the fact that the magnetic field changes from zero to its maximum value in one-quarter of a wave period, find the magnitude of the average emf induced in the antenna during this time.

A lidar (laser radar) gun is an alternative to the standard radar gun that uses the Doppler effect to catch speeders. A lidar gun uses an infrared laser and emits a precisely timed series of pulses of infrared electromagnetic waves. The time for each pulse to travel to the speeding vehicle and return to the gun is measured. In one situation a lidar gun in a stationary police car observes a difference of \(1.27 \times 10^{-7} \mathrm{s}\) in round-trip travel times for two pulses that are emitted 0.450 s apart. Assuming that the speeding vehicle is approaching the police car essentially head-on, determine the speed of the vehicle.

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is \(3.85 \times 10^{8} \mathrm{m}\). Find the time it took for his voice to reach the earth via radio waves. (b) Someday a person will walk on Mars, which is \(5.6 \times 10^{10} \mathrm{m}\) from the earth at the point of closest approach. Determine the minimum time that will be required for a message from Mars to reach the earth via radio waves.

A distant galaxy emits light that has a wavelength of \(434.1 \mathrm{nm}\). On earth, the wavelength of this light is measured to be \(438.6 \mathrm{nm}\). (a) Decide whether this galaxy is approaching or receding from the earth. Give your reasoning. (b) Find the speed of the galaxy relative to the earth.

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