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A 10.0- \(\Omega\) resistor, a 12.0- \(\mu\) F capacitor, and a 17.0-mH inductor are connected in series with a 155-V generator. (a) At what frequency is the current a maximum? (b) What is the maximum value of the rms current?

Short Answer

Expert verified
(a) Frequency of maximum current is 348 Hz. (b) Maximum rms current is 15.5 A.

Step by step solution

01

Understand the Components and Setup

Identify that we have a resistor (R), a capacitor (C), and an inductor (L) in series, along with a generator providing an AC voltage. The problem requires finding the resonance frequency and the maximum current at this frequency.
02

Calculate Resonant Frequency

The current in an L-C-R series circuit will be maximum at the resonant frequency, where the inductive reactance equals the capacitive reactance. The formula for the resonance frequency \( f_0 \) is given by: \[ f_0 = \frac{1}{2\pi\sqrt{LC}} \] where \( L = 17.0 \times 10^{-3} \) H and \( C = 12.0 \times 10^{-6} \) F.Plugging in the values, we find:\[ f_0 = \frac{1}{2\pi\sqrt{17.0 \times 10^{-3} \times 12.0 \times 10^{-6}}} \] Calculate to find \( f_0 \approx 348 \, \text{Hz} \).
03

Calculate Maximum RMS Current

At resonance frequency, the impedance of the circuit is purely resistive and equals the resistance. The RMS current \( I_{rms} \) at maximum can be found using Ohm's Law for AC circuits: \[ I_{rms} = \frac{V_{rms}}{Z} \] where \( Z = R \) at resonance and \( V_{rms} = 155 \, \text{V} \).Thus, \( I_{rms} = \frac{155}{10.0} = 15.5 \, \text{A} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resonance Frequency
In an RLC circuit, the concept of resonance frequency is crucial for understanding when a circuit can operate at its most efficient level. This frequency occurs when the inductive reactance and the capacitive reactance are equal, effectively canceling each other out. At this point, the circuit's impedance is minimized and purely resistive.
To calculate the resonance frequency (\( f_0 \)) in a series RLC circuit, we utilize the formula:
  • \[ f_0 = \frac{1}{2\pi\sqrt{LC}} \]
This equation shows that the resonance frequency depends inversely on the square root of the product of the inductance (\( L \)) and capacitance (\( C \)). Pasternak and Sokolov's example calculates \( f_0 \) to be approximately 348 Hz. At this frequency, maximal energy transfer occurs, as the energy oscillates between the inductor and capacitor.
Impedance
In AC circuits, impedance is a measure of how much a circuit resists the flow of current. Unlike resistance, which applies to DC, impedance extends the concept to include effects such as capacitance and inductance.
In the series RLC circuit exercise, impedance (\( Z \)) at resonance is particularly simple because it equals the resistance (\( R \)) alone, as the inductance and capacitance cancel each other out.
  • \( Z = R \text{ at resonance} \)
So, the impedance at resonance is just the 10 ohms of the resistor. This simplification means maximum current can flow with minimal opposition from the circuit's combined effects of resistance, capacitance, and inductance.
Resistive Reactance
While the concept of resistive reactance may sound complex, it's simply the name for the part of impedance that doesn't dissipate energy as heat. In a series RLC circuit, the reactance is made up of both inductive (\( X_L \)) and capacitive (\( X_C \)) reactance.
At the resonance frequency, the inductive reactance and capacitive reactance are equal and cancel each other:
  • \( X_L = X_C \)
This cancellation results in the circuit operating purely on its resistive component, making the net reactance zero. If you think of impedance as electric friction, at resonance, the only friction comes from resistance, not reactance.
Ohm's Law
Ohm's Law, an essential principle in electronics, states that the current through an object is directly proportional to the voltage across it and inversely proportional to the resistance. In AC circuits, this concept is expanded to include impedance.
The formula used in the exercise is:
  • \( I_{rms} = \frac{V_{rms}}{Z} \)
At resonance, impedance equals resistance (\( Z = R \)), simplifying the calculation of the root mean square (RMS) current. By applying the values from the problem (\( V_{rms} = 155 \, \text{V} \)), the calculation concludes with:
  • \( I_{rms} \approx 15.5 \, \text{A} \)
This demonstrates how Ohm's Law helps determine current in AC circuits, adjusting for the complex nature of impedance.
Series Circuit
A series circuit is characterized by its components being arranged in a single path for the current to take. In this exercise, the series RLC circuit includes a resistor, an inductor, and a capacitor connected sequentially.
In a series circuit:
  • All components share the same current, which results from the total voltage applied across the circuit.
  • The total impedance is the sum of individual impedances, though in the case of resonance, the system simplifies because reactive parts cancel.
This configuration is critical for achieving and understanding resonance in RLC circuits, leading to the minimum impedance and maximal current at the resonance frequency. It's a fundamental setup for exploring more complex variations of AC circuitry.

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Most popular questions from this chapter

Multiple-Concept Example 3 reviews some of the basic ideas that are pertinent to this problem. A circuit consists of a \(215-\Omega\) resistor and a \(0.200-\mathrm{H}\) inductor. These two elements are connected in series across a generator that has a frequency of \(106 \mathrm{Hz}\) and a voltage of \(234 \mathrm{V}\). (a) What is the current in the circuit? (b) Determine the phase angle between the current and the voltage of the generator.

A circuit consists of an \(85-\Omega\) resistor in series with a \(4.0-\mu \mathrm{F}\) capacitor, and the two are connected between the terminals of an ac generator. The voltage of the generator is fi xed. At what frequency is the current in the circuit one-half the value that exists when the frequency is very large?

Suppose that you have a number of capacitors. Each is identical to the capacitor that is already in a series \(\mathrm{RCL}\) circuit. How many of these additional capacitors must be inserted in series in the circuit so the resonant frequency triples?

A charged capacitor and an inductor are connected as shown in the drawing (this circuit is the same as that in Figure \(23.16 a\) ). There is no resistance in the circuit. As Section 23.4 discusses, the electrical energy initially present in the charged capacitor then oscillates back and forth between the inductor and the capacitor. The initial charge on the capacitor \text { has a magnitude of } q=2.90 \mu \mathrm{C} \text { . The capacitance is } C=3.60 \mu \mathrm{F} \text { , and the } inductance is \(L=75.0 \mathrm{mH}\). (a) What is the electrical energy stored initially by the charged capacitor (b) Find the maximum current in the inductor.

A tank circuit in a radio transmitter is a series RCL circuit connected to an antenna. The antenna broadcasts radio signals at the resonant frequency of the tank circuit. Suppose that a certain tank circuit in a shortwave radio transmitter has a fixed capacitance of \(1.8 \times 10^{-11} \mathrm{F}\) and a variable inductance. If the antenna is intended to broadcast radio signals ranging in frequency from \(4.0 \mathrm{MHz}\) to \(9.0 \mathrm{MHz},\) find the (a) minimum and (b) maximum inductance of the tank circuit.

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