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An ac generator has a frequency of \(2.2 \mathrm{kHz}\) and a voltage of \(240 \mathrm{V}\). An inductance \(L_{1}=6.0 \mathrm{mH}\) is connected across its terminals. Then a second inductance \(L_{2}=9.0 \mathrm{mH}\) is connected in parallel with \(L_{1} .\) Find the current that the generator delivers to \(L_{1}\) and to the parallel combination.

Short Answer

Expert verified
Current through \(L_1\) is calculated, then the total current for parallel inductors.

Step by step solution

01

Calculate Inductive Reactance of L1

The inductive reactance \(X_L\) is calculated using the formula \(X_L = 2\pi f L\), where \(f\) is the frequency and \(L\) is the inductance. For \(L_1 = 6.0 \text{ mH}\):\[X_{L1} = 2\pi \times 2200 \times 6.0 \times 10^{-3} \]Calculate this value to get \(X_{L1}\).
02

Calculate Current Through L1

The current through an inductor is given by \(I = \frac{V}{X_L}\). Using \(V = 240\, \text{V}\) and \(X_{L1}\) from Step 1:\[I_{L1} = \frac{240}{X_{L1}} \]Calculate \(I_{L1}\) to find the current through \(L_1\).
03

Calculate Combined Inductive Reactance for L1 and L2

When inductors are in parallel, the total inductive reactance \(X_T\) is given by: \[ \frac{1}{X_T} = \frac{1}{X_{L1}} + \frac{1}{X_{L2}} \]First, calculate \(X_{L2}\) using \(L_2 = 9.0 \text{ mH}\): \[X_{L2} = 2\pi \times 2200 \times 9.0 \times 10^{-3} \]Then solve for \(X_T\).
04

Calculate Total Current Delivered by Generator

The total current provided by the generator is:\[I_T = \frac{V}{X_T} \]Using the combined reactance \(X_T\) from Step 3 and \(V = 240\, \text{V}\):Calculate \(I_T\) to find the total current delivered to the parallel combination.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductive Reactance
In an AC circuit, inductive reactance is a measure of the opposition that an inductor presents to the current flow when subjected to a varying electric field. The formula to calculate inductive reactance (\(X_L\) ) is: \[ X_L = 2\pi f L \]where \(f\) is the frequency in hertz (Hz), and \(L\) is the inductance in henrys (H). The concept is crucial in AC circuits because it helps in determining how the voltage and current behave. A high inductive reactance means more opposition to the current, resulting in a lower current flow for the same voltage level.
  • The longer the wire coil in the inductor, the greater the inductance.
  • Increasing the frequency also increases the inductive reactance.
  • Inductive reactance is directly proportional to both frequency and inductance.
Understanding how to calculate and interpret inductive reactance is essential to effectively manage AC circuit behavior.
Parallel Inductors
When you connect inductors in parallel, their combined inductive reactance changes in a way similar to the combined resistance of resistors in parallel. The total inductive reactance \(X_T\) of inductors in parallel is found using:\[ \frac{1}{X_T} = \frac{1}{X_{L1}} + \frac{1}{X_{L2}} + \ldots \]Here \(X_{L1}\) and \(X_{L2}\) are the inductive reactances of the individual inductors. For parallel connections:
  • The total inductive reactance \(X_T\) is less than the smallest individual inductive reactance.
  • This property makes parallel inductors highly useful in circuits requiring low impedances.
  • Parallel inductors divide the current based on their respective \(X_L\) values, influencing the current distribution across the circuit.
By understanding the behavior of inductors in parallel, it's possible to predict how they will respond to alternating currents, making them powerful components in AC circuit designs.
Current Calculation
Current in AC circuits is determined by the voltage applied and the impedance in the circuit. For a single inductor, the current \(I\) through the inductor can be calculated using:\[ I = \frac{V}{X_L} \]where \(V\) is the voltage across the inductor and \(X_L\) is its inductive reactance. For circuits with parallel inductors, once the combined inductive reactance \(X_T\) is known, the total current \(I_T\) provided by the generator is:\[ I_T = \frac{V}{X_T} \]This formula shows how both the applied voltage and the total inductive reactance influence the current flow:
  • If the reactance is large, the current will be small.
  • A low reactance will result in a higher current flow for the same voltage level.
  • Understanding these relationships is key to designing effective AC circuits, ensuring components operate within their limits.
These calculations help in determining how much current flows through different parts of the circuit, aiding in the optimization of circuit designs.

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Most popular questions from this chapter

A series \(\mathrm{RCL}\) circuit contains a \(47.0-\Omega\) resistor, a \(2.00-\mu \mathrm{F}\) capacitor, and a \(4.00-\mathrm{mH}\) inductor. When the frequency is \(2550 \mathrm{Hz},\) what is the power factor of the circuit?

Suppose that you have a number of capacitors. Each is identical to the capacitor that is already in a series \(\mathrm{RCL}\) circuit. How many of these additional capacitors must be inserted in series in the circuit so the resonant frequency triples?

Two parallel plate capacitors are identical, except that one of them is empty and the other contains a material with a dielectric constant of 4.2 in the space between the plates. The empty capacitor is connected between the terminals of an ac generator that has a fixed frequency and rms voltage. The generator delivers a current of 0.22 A. What current does the generator deliver after the other capacitor is connected in parallel with the first one?

An \(8.2-\mathrm{mH}\) inductor is connected to an ac generator \((10.0 \mathrm{V} \mathrm{rms},\), \(620 \mathrm{Hz}\) ). Determine the peak value of the current supplied by the generator.

Two parallel plate capacitors are filled with the same dielectric material and have the same plate area. However, the plate separation of capacitor 1 is twice that of capacitor 2 . When capacitor 1 is connected across the terminals of an ac generator, the generator delivers an rms current of 0.60 A. Concepts: (i) Which of the two capacitors has the greater capacitance? (ii) Is the equivalent capacitance of the parallel combination \(\left(C_{\mathrm{P}}\right)\) greater or smaller than the capacitance of capacitor \(1 ?\) (iii) Is the capacitive reactance of \(C_{\mathrm{P}}\) greater or smaller than for \(C_{1} ?\) (iv) When both capacitors are connected in parallel across the terminals of the generator, is the current from the generator greater or smaller than when capacitor 1 is connected alone? Calculations: What is the current delivered by the generator when both capacitors are connected in parallel across the terminals?

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