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A circular coil of radius 0.11 \(\mathrm{m}\) contains a single turn and is located in a constant magnetic field of magnitude \(0.27 \mathrm{T}\). The magnetic field has the same direction as the normal to the plane of the coil. The radius increases to \(0.30 \mathrm{m}\) in a time of \(0.080 \mathrm{s}\). Concepts: (i) Why is there an emf induced in the coil? (ii) Does the magnitude of the induced emf depend on whether the area is increasing or decreasing? Explain. (iii) What determines the amount of current induced in the coil? (iv) If the coil is cut so it is no longer one continuous piece, are there an induced emf and an induced current? Explain. Calculations: (a) Determine the magnitude of the emf induced in the coil. (b) The coil has a resistance of \(0.70 \Omega .\) Find the magnitude of the induced current.

Short Answer

Expert verified
(i) EMF is induced due to changing flux. (ii) EMF depends on flux change rate, not direction. (iii) Current depends on EMF and resistance. (iv) Breaking the coil stops current but not EMF. (a) EMF: 0.826 V, (b) Current: 1.18 A.

Step by step solution

01

Understanding the Induced EMF

(i) An EMF is induced in a coil due to a change in magnetic flux through the coil. In this problem, the radius of the coil changes, which alters the area and thus the magnetic flux. Faraday's law of electromagnetic induction states that the EMF induced in a circuit is proportional to the rate of change of magnetic flux through the circuit.
02

Effect of Area Change on EMF

(ii) The magnitude of the induced EMF depends on the rate of change of magnetic flux, not on whether the area is increasing or decreasing. The formula for EMF is given by Faraday's law as \( \varepsilon = -\frac{d\Phi}{dt} \), where \( \Phi \) is the magnetic flux.
03

Determining Induced Current

(iii) The amount of current induced in the coil is determined by Ohm's law \( I = \frac{\varepsilon}{R} \), where \( I \) is the current, \( \varepsilon \) is the induced EMF, and \( R \) is the resistance of the coil.
04

Impact of Breaking the Coil

(iv) If the coil is cut, there is still an induced EMF because it is related to the change in magnetic flux, which occurs independently of whether the coil is a continuous loop. However, an induced current requires a closed path, so breaking the coil would prevent current from flowing.
05

Calculate Area Change on the Coil

First, calculate the initial and final areas of the coil. The area of a circle is \( A = \pi r^2 \).Initial area: \[ A_1 = \pi (0.11)^2 = 0.0380 \text{ m}^2 \]Final area: \[ A_2 = \pi (0.30)^2 = 0.2827 \text{ m}^2 \]Change in area: \[ \Delta A = A_2 - A_1 = 0.2827 - 0.0380 = 0.2447 \text{ m}^2 \]
06

Calculate Change in Magnetic Flux

Using the change in area, calculate the change in magnetic flux:The magnetic flux \( \Phi = B \cdot A \) where \( B = 0.27 \text{ T} \).Change in magnetic flux: \[ \Delta \Phi = B \cdot \Delta A = 0.27 \cdot 0.2447 = 0.066069 \text{ Wb} \]
07

Determine the Induced EMF

Use Faraday's law to calculate the induced EMF:\[ \varepsilon = -\frac{d\Phi}{dt} = -\frac{\Delta \Phi}{\Delta t} = -\frac{0.066069}{0.080} = -0.8259 \text{ V} \]The negative sign indicates the direction of the induced EMF, but only the magnitude is needed here.
08

Calculate the Induced Current

Use Ohm's law to find the induced current in the coil:Given that the resistance \( R = 0.70 \Omega \),\[ I = \frac{\varepsilon}{R} = \frac{0.8259}{0.70} = 1.18 \text{ A} \]
09

Final Answers

The magnitude of the induced EMF is approximately \(0.826 \ ext{V}\) and the magnitude of the induced current is approximately \(1.18 \ ext{A}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law of electromagnetic induction is a fundamental principle that describes how an electric field is generated by a changing magnetic field. In its simplest form, it states that an electromotive force (EMF) is induced in a coil when there is a change in magnetic flux through the coil.

This principle is mathematically represented as \( \varepsilon = -\frac{d\Phi}{dt} \), where \( \varepsilon \) is the induced EMF, and \( \Phi \) represents the magnetic flux. The negative sign denotes the direction of the induced EMF as per Lenz's law, which opposes the change in flux.

Faraday's Law can be applied to various scenarios where the magnetic environment around a conductor changes. It forms the basis of how transformers, inductors, and many types of electrical generators work. By understanding Faraday's law, we can predict how alterations in magnetic fields impact electrical circuits.
Magnetic Flux
Magnetic flux refers to the amount of magnetic field passing through a given area, such as a loop of wire. It's a measure of how many magnetic field lines penetrate a certain area, and it is vital for understanding electromagnetic induction.

The magnetic flux \( \Phi \) is calculated by the formula \( \Phi = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field strength, \( A \) is the area the field lines pass through, and \( \theta \) is the angle between the magnetic field and the perpendicular to the surface. For the problem given, the magnetic field is aligned with the normal to the coil, making \( \theta = 0 \), thus \( \cos(\theta) = 1 \).

Changes in magnetic flux, whether through variations in field strength, area, or orientation, lead to induced EMFs according to Faraday's Law. Some practical applications include electric motors and generators, where magnetic flux is manipulated to produce energy or motion.
Ohm's Law
Ohm's Law is a simple yet powerful relationship that connects voltage (or EMF), current, and resistance in an electric circuit. It is given by \( I = \frac{\varepsilon}{R} \), where \( I \) is the current, \( \varepsilon \) is the electromotive force or voltage, and \( R \) is the resistance.

In the context of electromagnetic induction, the induced EMF from Faraday's Law creates a current which can be computed using Ohm's Law, provided the circuit is closed and the resistance is known.

Ohm's Law helps evaluate the current's magnitude once we know the induced EMF and the circuit's total resistance. This relation is crucial for designing electrical components and ensuring that they function correctly without overheating or breaking down.

For circuits with an induced EMF but broken paths (as in the cut coil scenario), no current flows because there is no closed loop, demonstrating the importance of a continuous path in a circuit.
Induced EMF
Induced EMF is the electric potential generated in a coil due to a change in magnetic flux. This concept lies at the heart of electromagnetic induction and is crucial for understanding how electric currents are generated in many practical devices.

For a dynamic system, changes in the shape or position of a coil within a magnetic field, or changes in the magnetic field itself, can result in an induced EMF. In the given exercise, the radius of the coil increases, which changes the magnetic flux and induces an EMF according to Faraday's Law.

The magnitude of the induced EMF depends on several factors:
  • The rate at which the magnetic flux changes.
  • The number of loops in the coil.
  • The nature and characteristics (like resistance) of the material in the coil.
These factors must be considered when analyzing or designing circuits that rely on induction, such as those in transformers and electric generators.

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Most popular questions from this chapter

A flat circular coil with 105 turns, a radius of \(4.00 \times 10^{-2} \mathrm{m}\), and a resistance of \(0.480 \Omega\) is exposed to an external magnetic field that is directed perpendicular to the plane of the coil. The magnitude of the external magnetic field is changing at a rate of \(\Delta B / \Delta t=0.783 \mathrm{T} / \mathrm{s}\), thereby inducing a current in the coil. Find the magnitude of the magnetic field at the center of the coil that is produced by the induced current.

A circular loop of wire rests on a table. A long, straight wire lies on this loop, directly over its center, as the drawing illustrates. The current \(I\) in the straight wire is decreasing. In what direction is the induced current, if any, in the loop? Give your reasoning.

A motor is designed to operate on \(117 \mathrm{V}\) and draws a current of \(12.2 \mathrm{A}\) when \(\mathrm{it}\) first starts up. At its normal operating speed, the motor draws a current of 2.30 A. Obtain (a) the resistance of the armature coil, (b) the back emf developed at normal speed, and (c) the current drawn by the motor at one-third of the normal speed.

Parts \(a\) and \(b\) of the drawing show the same uniform and constant (in time) magnetic field \(\overrightarrow{\mathbf{B}}\) directed perpendicularly into the paper over a rectangular region. Outside this region, there is no field. Also shown is a rectangular coil (one turn), which lies in the plane of the paper. In part \(a\) the long side of the coil (length \(=L\) ) is just at the edge of the field region, while in part \(b\) the short side (width \(=W\) ) is just at the edge. It is known that \(L / W=3.0 .\) In both parts of the drawing the coil is pushed into the field with the same velocity \(\overrightarrow{\mathbf{v}}\) until it is completely within the field region. The magnitude of the average emf induced in the coil in part \(a\) is 0.15 V. What is its magnitude in part \(b ?\)

A long solenoid of length \(8.0 \times 10^{-2} \mathrm{m}\) and cross-sectional area \(5.0 \times 10^{-5} \mathrm{m}^{2}\) contains 6500 turns per meter of length. Determine the emf induced in the solenoid when the current in the solenoid changes from 0 to 1.5 A during the time interval from 0 to 0.20 s.

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