/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 The maximum strength of the eart... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The maximum strength of the earth's magnetic field is about \(6.9 \times 10^{-5} \mathrm{T}\) near the south magnetic pole. In principle, this field could be used with a rotating coil to generate \(60.0-\mathrm{Hz}\) ac electricity. What is the minimum number of turns (area per turn \(=0.022 \mathrm{m}^{2}\) ) that the coil must have to produce an rms voltage of \(120 \mathrm{V} ?\)

Short Answer

Expert verified
The coil must have at least 20197 turns.

Step by step solution

01

Understanding the Problem

We need to find the minimum number of turns in a coil that generates a root mean square (RMS) voltage of 120 V using a rotating coil in the Earth's magnetic field, given that the frequency of the alternating current (AC) is 60 Hz, the maximum magnetic field strength is \(6.9 \times 10^{-5} \mathrm{T}\), and the area per turn is \(0.022 \mathrm{m}^2\).
02

Using Faraday's Law of Induction

Faraday's Law states that the electromotive force (EMF) induced in a coil is given by \( \text{EMF}_{max} = NAB\omega \sin(\theta) \), where \( B \) is the magnetic field, \( A \) is the area of the coil turn, \( N \) is the number of turns, and \( \omega \) is the angular frequency \( (2\pi f) \). The RMS voltage \( V_{rms} \) is related to the maximum EMF by \( V_{rms} = \frac{\text{EMF}_{max}}{\sqrt{2}} \).
03

Calculating Angular Frequency

The angular frequency \( \omega \) is calculated using the formula \( \omega = 2\pi f \), where \( f = 60 \text{ Hz} \). Thus, \( \omega = 2\pi \times 60 = 120\pi \text{ rad/s} \).
04

Setting Up the Equation for RMS Voltage

The equation for RMS voltage is \( V_{rms} = \frac{NAB\omega}{\sqrt{2}} \). Given \( V_{rms} = 120 \, \text{V} \), \( A = 0.022 \, \text{m}^2 \), \( B = 6.9 \times 10^{-5} \, \text{T} \), and \( \omega = 120\pi \, \text{rad/s} \), substitute these values into the equation.
05

Solving for the Number of Turns N

Rearrange the equation to solve for \( N \): \( N = \frac{120 \sqrt{2}}{AB\omega} \). Substitute the values: \( A = 0.022 \, \text{m}^2 \), \( B = 6.9 \times 10^{-5} \, \text{T} \), and \( \omega = 120\pi \, \text{rad/s} \), to find \( N \).
06

Computing the Number of Turns

Calculate \( N = \frac{120 \sqrt{2}}{0.022 \times 6.9 \times 10^{-5} \times 120\pi} \approx 20197 \). Therefore, the minimum number of turns needed for the coil is approximately 20197.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromotive Force (EMF)
Electromotive force, or EMF, is a fundamental concept in electromagnetism. It's not a force in the traditional sense but rather the energy provided by a source to move electrons through a circuit. This energy is what causes current to flow in a closed loop.
Understanding EMF in terms of Faraday's Law of Induction is crucial. According to Faraday's Law, the EMF induced in a coil is directly proportional to the rate of change of magnetic flux through the coil. The formula is:
  • \( \text{EMF}_{\text{max}} = NAB\omega \sin(\theta) \)
where:
  • \( N \) is the number of turns in the coil
  • \( A \) is the area of each turn
  • \( B \) is the magnetic field strength
  • \( \omega \) is the angular frequency
  • \( \theta \) is the angle between the magnetic field and normal to the plane of coil
Typically, the sine component reaches its maximum when \( \theta \) is 90°, therefore \( \sin(\theta) = 1 \). In such cases, the induced EMF depends on all these factors. Understanding how EMF relates to these parameters can help predict and control the generation of electricity.
Angular Frequency
Angular frequency, denoted by \( \omega \), measures how rapidly a periodic event repeats, particularly in circular motion or oscillations. It's quite important when analyzing alternating current (AC) circuits.
Angular frequency is related to the regular frequency, \( f \), which is measured in hertz (Hz), via the formula:
  • \( \omega = 2\pi f \)
where:
  • \( \omega \) is the angular frequency measured in radians per second (rad/s)
  • \( f \) is the linear frequency, which represents cycles per second
In the given exercise, the linear frequency of the AC electricity is 60 Hz. Hence, applying the formula, we find:
  • \( \omega = 2\pi \times 60 = 120\pi \text{ rad/s} \)
This value of angular frequency is crucial for the calculation of induced EMF and thus influences how effective the coil is in generating electricity. By knowing \( \omega \), it becomes easier to determine how the system behaves over time.
Root Mean Square (RMS) Voltage
Root mean square (RMS) voltage is a way of expressing AC voltage in a comparable form to DC voltage. It's particularly meaningful because AC voltages vary over time.
RMS voltage provides a measure of the effective power in AC circuits. For a sine wave, the relationship between the maximum voltage (or peak voltage) and the RMS voltage is given by:
  • \( V_{\text{rms}} = \frac{V_{\text{max}}}{\sqrt{2}} \)
This formula simplifies the comparison, allowing us to use RMS voltage to predict the power capability of AC electricity just like with DC voltage. In the problem, we are looking for a coil that produces an RMS voltage of 120 V. This RMS value is directly used to calculate the number of turns in the coil based on the maximum EMF and angular frequency, using the relation:
  • \( V_{\text{rms}} = \frac{NAB\omega}{\sqrt{2}} \)
where each variable pertains to the coil or magnetic field values. Thus, understanding RMS voltage helps in specifically designing electrical systems for safe and efficient operation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A step-down transformer (turns ratio \(=1: 8\) ) is used with an electric train to reduce the voltage from the wall receptacle to a value needed to operate the train. When the train is running, the current in the secondary coil is \(1.6 \mathrm{A}\). What is the current in the primary coil?

Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addition, assume that your house is the only one using electric power. At a substation the primary coil of a step-down transformer (turns ratio \(=1: 29\) ) receives the voltage from the high-voltage transmission line. Because of your usage, a current of \(48 \mathrm{mA}\) exists in the primary coil of this transformer. The secondary coil is connected to the primary of another step-down transformer (turns ratio \(=1: 32\) ) somewhere near your house, perhaps up on a telephone pole. The secondary coil of this transformer delivers a \(240-\mathrm{V}\) emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.

In some places, insect "zappers," with their blue lights, are a familiar sight on a summer's night. These devices use a high voltage to electrocute insects. One such device uses an ac voltage of \(4320 \mathrm{V},\) which is obtained from a standard \(120.0-\mathrm{V}\) outlet by means of a transformer. If the primary coil has 21 turns, how many turns are in the secondary coil?

The magnetic flux that passes through one turn of a 12 -turn coil of wire changes to 4.0 from \(9.0 \mathrm{Wb}\) in a time of \(0.050 \mathrm{s}\). The average induced current in the coil is 230 A. What is the resistance of the wire?

A \(5.40 \times 10^{-5} \mathrm{H}\) solenoid is constructed by wrapping 65 turns of wire around a cylinder with a cross-sectional area of \(9.0 \times 10^{-4} \mathrm{m}^{2} .\) When the solenoid is shortened by squeezing the turns closer together, the inductance increases to \(8.60 \times 10^{-5}\) H. Determine the change in the length of the solenoid.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.