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The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of \(7.0 \mathrm{T},\) and the current in the solenoid is \(2.0 \times 10^{2} \mathrm{A}\). What is the number of turns per meter of length of the solenoid? Note that the solenoid used to produce the magnetic field in this type of system has a length that is not very long compared to its diameter. Because of this and other design considerations, your answer will be only an approximation.

Short Answer

Expert verified
The solenoid has approximately 27800 turns per meter.

Step by step solution

01

Understand the equation for the magnetic field in a solenoid

The magnetic field inside a long, tightly wound solenoid is given by the formula: \( B = \mu_0 \cdot n \cdot I \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space \( (4\pi \times 10^{-7} \; \text{T}\cdot\text{m/A}) \), \( n \) is the number of turns per unit length, and \( I \) is the current.
02

Rearrange the equation to solve for the number of turns per meter

We need to find \( n \), the number of turns per meter. Rearrange the formula to get: \( n = \frac{B}{\mu_0 \cdot I} \).
03

Substitute the given values into the equation

Substitute the given values into the rearranged equation: \( B = 7.0 \; \text{T} \), \( I = 2.0 \times 10^2 \; \text{A} \), and \( \mu_0 = 4\pi \times 10^{-7} \; \text{T}\cdot\text{m/A} \). The formula becomes: \( n = \frac{7.0}{4\pi \times 10^{-7} \times 2.0 \times 10^2} \).
04

Calculate the number of turns per meter

Calculate \( n \) using the substituted values: \( n = \frac{7.0}{4\pi \times 10^{-7} \times 2.0 \times 10^2} \approx \frac{7.0}{2.513 \times 10^{-4}} \approx 27800 \; \text{turns/m} \). This means there are approximately 27800 turns per meter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Resonance Imaging (MRI)
Magnetic Resonance Imaging (MRI) is a non-invasive medical imaging technique used to visualize the internal structures of the body in detail. MRI systems utilize powerful magnetic fields, radio waves, and field gradients to generate images of organs, tissues, and other body structures. One crucial component of an MRI machine is the solenoid, which is responsible for producing a uniform magnetic field necessary for high-resolution imaging.
The solenoid in an MRI machine is designed to create a strong and homogeneous magnetic field. This field interacts with hydrogen nuclei in the body. When exposed to this magnetic field, these nuclei resonate at specific frequencies, allowing the MRI system to capture detailed images. The stability and strength of the magnetic field in the solenoid greatly influence the quality and clarity of the MRI images.
Magnetic Field Strength
The magnetic field strength in an MRI solenoid is a crucial factor in the imaging process. It is typically measured in teslas (T) and determines how well the MRI can create images of soft tissues and subtle details. The stronger the magnetic field, the better the quality of the images.
In our example, the field strength is given as 7.0 T, which is quite strong for MRI systems. Higher magnetic field strengths can provide better resolution and more detailed images than lower strengths. However, they also require more sophisticated technology and greater safety measures.
  • A consistent and strong magnetic field ensures reliable image quality.
  • High field strength improves clarity, especially for smaller structures within the body.
  • Field strength can affect patient comfort and safety, making solenoid design vital.
Solenoid Design
The design of a solenoid in MRI systems is critical to achieving the desired magnetic field properties. A solenoid is essentially a coil of wire, and its primary function is to generate a magnetic field when an electric current passes through it. The field strength within the solenoid primarily depends on several factors:
  • The number of turns per unit length (n).
  • The current flowing through the coil (I).
  • The physical dimensions, such as the diameter and length of the solenoid.
The solenoid used in our example has a specific construction that affects its magnetic field. In practical applications, solenoids must be carefully engineered to ensure that they produce a consistent magnetic field despite any constraints like the solenoid’s length or external factors.
Engineers focus on optimizing the solenoid's dimensions and winding technique to maximize efficiency and achieve the required magnetic field strength.
Permeability of Free Space
The permeability of free space, denoted as \( \mu_0 \), is a fundamental physical constant essential in the study of electromagnetism. It represents the ability of a vacuum to support the formation of a magnetic field and is crucial for calculating magnetic fields created by current-carrying solenoids and wires. The value of \mu_0\ is approximately \(4\pi \times 10^{-7} \text{T}\cdot\text{m/A}\).
This constant is an important parameter in the formula for the magnetic field inside a solenoid: \ B = \mu_0 \cdot n \cdot I \. In this equation:
  • \mu_0\ remains constant, signifying the unchanging nature of this property in a vacuum.
  • It helps define how effectively a solenoid can generate a magnetic field, given a set number of turns and current.
  • The permeability forms a baseline for understanding more complex materials that may replace air or vacuum in applications like MRI.
Understanding \mu_0\ allows engineers to predict and modify the magnetic fields in devices like MRI machines by adjusting the solenoid’s design and electrical parameters. These adjustments help produce high-quality images necessary for medical diagnostics.

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Most popular questions from this chapter

Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions \(\left(\mathrm{Au}^{2+}\right),\) each with a mass of \(3.27 \times 10^{-25} \mathrm{kg} .\) The ions are accelerated from rest through a potential difference of \(1.00 \mathrm{kV}\). Then, a 0.500-T magnetic field causes the ions to follow a circular path. Determine the radius of the path.

You have a wire of length \(L=1.00 \mathrm{m}\) from which to make the square coil of a dc motor. The current in the coil is \(I=1.7 \mathrm{A}\), and the magnetic field of the motor has a magnitude of \(B=0.34 \mathrm{T}\). Find the maximum torque exerted on the coil when the wire is used to make a single-turn square coil and a two-turn square coil.

Two infinitely long, straight wires are parallel and separated by a distance of one meter. They carry currents in the same direction. Wire 1 carries four times the current that wire 2 carries. On a line drawn perpendicular to both wires, locate the spot (relative to wire 1 ) where the net magnetic field is zero. Assume that wire 1 lies to the left of wire 2 and note that there are three regions to consider on this line: to the left of wire \(1,\) between wire 1 and wire \(2,\) and to the right of wire 2.

Two pieces of the same wire have the same length. From one piece, a square coil containing a single loop is made. From the other, a circular coil containing a single loop is made. The coils carry different currents. When placed in the same magnetic field with the same orientation, they experience the same torque. What is the ratio \(I_{\text {square }} / I_{\text {circle }}\) of the current in the square coil to the current in the circular coil?

At a certain location, the horizontal component of the earth's magnetic field is \(2.5 \times 10^{-5} \mathrm{T}\), due north. A proton moves eastward with just the right speed for the magnetic force on it to balance its weight. Find the speed of the proton.

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