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A wire carries a current of 0.66 A. This wire makes an angle of \(58^{\circ}\) with respect to a magnetic field of magnitude \(4.7 \times 10^{-5} \mathrm{T}\). The wire experiences a magnetic force of magnitude \(7.1 \times 10^{-5} \mathrm{N}\). What is the length of the wire?

Short Answer

Expert verified
The length of the wire is approximately 0.276 m.

Step by step solution

01

Identify the Formula

The force on a current-carrying wire in a magnetic field is given by the formula \( F = I \cdot L \cdot B \cdot \sin(\theta) \), where \( F \) is the magnetic force, \( I \) is the current, \( L \) is the length of the wire, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the wire and the magnetic field.
02

Rearrange the Formula for Length

We need to find the length \( L \) of the wire. Rearrange the given formula to solve for \( L \): \[ L = \frac{F}{I \cdot B \cdot \sin(\theta)} \]
03

Substitute Known Values

Plug in the values from the exercise into the formula: \( F = 7.1 \times 10^{-5} \mathrm{N} \), \( I = 0.66 \mathrm{A} \), \( B = 4.7 \times 10^{-5} \mathrm{T} \), and \( \theta = 58^{\circ} \).
04

Calculate \(\sin(\theta)\)

Calculate \( \sin(58^{\circ}) \). Using a calculator, you find \( \sin(58^{\circ}) \approx 0.8480\).
05

Calculate the Length

Substitute \( \sin(58^{\circ}) = 0.8480 \) into the length equation: \[ L = \frac{7.1 \times 10^{-5}}{0.66 \cdot 4.7 \times 10^{-5} \cdot 0.8480} \] Simplify to find \( L \approx 0.276 \mathrm{m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current-Carrying Wire
A current-carrying wire is a fundamental concept in electromagnetism that refers to a wire through which an electric current flows. When an electric current, which is the flow of electric charge, moves through a wire, it causes several interesting effects. One of these effects is its interaction with magnetic fields.

This interaction results in the wire experiencing a force, known as the magnetic force. The magnitude of this force depends on several factors, such as the magnitude of the current, the magnetic field strength, and the orientation of the wire in relation to the magnetic field.

A convenient way to calculate this force is by using the formula:
  • \( F = I \cdot L \cdot B \cdot \sin(\theta) \)
where:
  • \( F \) is the magnetic force,
  • \( I \) is the current through the wire,
  • \( L \) is the length of the wire,
  • \( B \) is the magnetic field strength, and
  • \( \theta \) is the angle between the wire and the magnetic field.
Magnetic Field Strength
Magnetic field strength, often denoted by \( B \), is a measure of the magnetic field's ability to exert force on moving electric charges, such as those in a current-carrying wire. It is measured in teslas (T), which indicates the strength of the magnetic field at a given point. A stronger magnetic field exerts a greater force on a wire or any other charged particle moving within it.

In real-world applications, understanding and determining the magnetic field strength is crucial for designing and operating electrical devices effectively. This includes things like electric motors, generators, and other equipment dependent on electromagnetic principles.

In the study of a current-carrying wire, magnetic field strength \( B \) is a critical component of the formula for calculating magnetic force. As given in the formula:
  • \( F = I \cdot L \cdot B \cdot \sin(\theta) \)
You can see that the magnetic force is directly proportional to the magnetic field strength \( B \). Hence, increasing \( B \) will increase the magnitude of the force acting on the wire.
Angle Between Wire and Field
The angle between the wire and the magnetic field, represented by \( \theta \), plays a pivotal role in determining the strength of the magnetic force acting on a current-carrying wire. This is because the force depends on the sine of this angle, \( \sin(\theta) \).

When the wire is aligned perfectly parallel with the magnetic field (\( \theta = 0^{\circ} \) or \( 180^{\circ} \)), the sine function results in zero, meaning no force acts on the wire. Conversely, when the wire is perpendicular to the field (\( \theta = 90^{\circ} \)), \( \sin(\theta) \) reaches its maximum value of 1, resulting in the maximum possible force.

This concept is important when calculating the force and is often visually represented in problems and experiments, showing how the orientation of the wire relative to the magnetic field lines affects the force experienced. It's one reason why it's crucial to accurately determine \( \theta \) in practical applications and involve it accurately when using the equation:
  • \( F = I \cdot L \cdot B \cdot \sin(\theta) \)
By understanding this principle, one can manipulate \( \theta \) to achieve the desired magnetic effects in various technological and industrial applications.

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Most popular questions from this chapter

A long, cylindrical conductor is solid throughout and has a radius \(R\). Electric charges flow parallel to the axis of the cylinder and pass uniformly through the entire cross section. The arrangement is, in effect, a solid tube of current \(I_{0} .\) The current per unit cross-sectional area (i.e., the current density) is \(I_{0} /\left(\pi R^{2}\right) .\) Use Ampère's law to show that the magnetic field inside the conductor at a distance \(r\) from the axis is \(\mu_{0} I_{0} r /\left(2 \pi R^{2}\right)\). (Hint: For a closed path, use a circle of radius r perpendicular to and centered on the axis. Note that the current through any surface is the area of the surface times the current density.)

The ion source in a mass spectrometer produces both singly and doubly ionized species, \(X^{+}\) and \(X^{2+} .\) The difference in mass between these species is too small to be detected. Both species are accelerated through the same electric potential difference, and both experience the same magnetic field, which causes them to move on circular paths. The radius of the path for the species \(\mathrm{X}^{+}\) is \(r_{1}\), while the radius for species \(\mathrm{X}^{2+}\) is \(r_{2}\). Find the ratio \(r_{1} / r_{2}\) of the radii.

In New England, the horizontal component of the earth's magnetic field has a magnitude of \(1.6 \times 10^{-5} \mathrm{T} .\) An electron is shot vertically straight up from the ground with a speed of \(2.1 \times 10^{6} \mathrm{m} / \mathrm{s} .\) What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron.

A wire has a length of \(7.00 \times 10^{-2} \mathrm{m}\) and is used to make a circular coil of one turn. There is a current of \(4.30 \mathrm{A}\) in the wire. In the presence of a \(2.50-\mathrm{T}\) magnetic field, what is the maximum torque that this coil can experience?

Two of the isotopes of carbon, carbon- 12 and carbon- \(13,\) have masses of \(19.93 \times 10^{-27} \mathrm{kg}\) and \(21.59 \times 10^{-27} \mathrm{kg},\) respectively. These two isotopes are singly ionized ( \(+e\) ), each given a speed of \(6.667 \times 10^{5} \mathrm{m} / \mathrm{s}\). The ions then enter the bending region of a mass spectrometer where the magnetic field is \(0.8500 \mathrm{T}\). Determine the spatial separation between the two isotopes after they have traveled through a half-circle.

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