/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 The rear window of a van is coat... [FREE SOLUTION] | 91Ó°ÊÓ

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The rear window of a van is coated with a layer of ice at \(0^{\circ} \mathrm{C}\). The density of ice is \(917 \mathrm{kg} / \mathrm{m}^{3} .\) The driver of the van turns on the rear-window defroster, which operates at \(12 \mathrm{V}\) and \(23 \mathrm{A}\). The defroster directly heats an area of \(0.52 \mathrm{m}^{2}\) of the rear window. What is the maximum thickness of ice coating this area that the defroster can melt in 3.0 minutes?

Short Answer

Expert verified
Maximum thickness of ice melted is approximately 0.302 mm.

Step by step solution

01

Calculate the Energy Produced by the Defroster

The power output of the defroster is given by the formula \( P = IV \), where \( I \) is the current in amperes and \( V \) is the voltage. Here, \( I = 23 \) A and \( V = 12 \) V. Thus, the power is \( P = 23 \, \text{A} \times 12 \, \text{V} = 276 \, \text{W} \). Then, we calculate the total energy produced in 3 minutes (180 seconds) by multiplying the power by time: \( E = P \times t = 276 \, \text{W} \times 180 \, \text{s} = 49680 \, \text{J} \).
02

Calculate the Energy Required to Melt the Ice

The energy required to melt ice is \( E = m \cdot L_f \), where \( m \) is the mass of the ice and \( L_f = 334,000 \, \text{J/kg} \) is the latent heat of fusion for ice. We express mass \( m \) in terms of volume \( V \) and density \( \rho \): \( m = \rho \cdot V \). The volume can further be expressed as \( V = A \cdot d \) where \( A = 0.52 \, \text{m}^2 \) is the area and \( d \) is the thickness. Thus, \( E = \rho \cdot A \cdot d \cdot L_f = 917 \, \text{kg/m}^3 \times 0.52 \, \text{m}^2 \times d \times 334,000 \, \text{J/kg} \).
03

Solve for the Maximum Thickness

From Step 1, we know the total energy provided is \( 49680 \, \text{J} \). Using this in our equation for \( E \) from Step 2, we set \( 49680 = 917 \times 0.52 \times d \times 334,000 \). Solving for \( d \), we get: \[ d = \frac{49680}{917 \times 0.52 \times 334,000} \approx 0.000302 \, \text{m} = 0.302 \, \text{mm} \].
04

Conclusion

The maximum thickness of ice that the defroster can melt is about \( 0.302 \, \text{mm} \). This thickness is obtained by using the energy calculated from the power and time available to operate the defroster.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Latent Heat of Fusion
Latent heat of fusion is a thermodynamic concept that refers to the amount of energy required to change a substance from solid to liquid at a constant temperature. It is an essential property when dealing with phase transitions like melting or freezing.

To melt ice at its melting point, a specific amount of energy known as the latent heat of fusion must be supplied. For ice, this energy is approximately 334,000 J/kg, meaning each kilogram of ice requires 334,000 joules to turn into water without changing temperature.

This concept is crucial for calculating the amount of energy needed to melt a certain mass of ice, as seen in exercises involving energy conversion like the rear-window defroster problem. By understanding latent heat of fusion, we can determine how much ice can be melted given a certain energy input, provided the temperature remains at the melting point. This understanding helps us apply the equation \( E = m \cdot L_f \) effectively, where \( L_f \) is the latent heat of fusion.
Power and Energy Calculation
Calculating power and energy forms the backbone of understanding how much work an electronic device can do, which is vital in physics. Power is the rate at which energy is transferred or converted, and it is typically measured in watts (W). In our example, we calculated power using the formula \( P = IV \), where \( I \) is current in amperes and \( V \) is voltage.

For the defroster, this power formula gives \( P = 23 \, \text{A} \times 12 \, \text{V} = 276 \, \text{W} \). To find the total energy provided over time, we multiply power by time: \( E = P \times t \). This results in \( 276 \, \text{W} \times 180 \, \text{s} = 49,680 \, \text{J} \), where 180 seconds represent the 3-minute operation period.

Understanding these calculations allows you to predict the energy capability of systems, such as knowing whether a defroster can adequately melt ice based on its power rating and operational time.
Density and Volume Relationship
The relationship between density and volume is essential in identifying how much substance is present in a given space, which is critical for calculating mass when given volume and density.

Density, denoted by \( \rho \), is defined as mass per unit volume. In the context of the ice-melting example, knowing the density of ice allows us to convert volume into mass. The formula \( m = \rho \cdot V \) applies here, where \( m \) is mass, \( \rho \) is density, and \( V \) is volume.

Volume can further be described in terms of area (\( A \)) and thickness (\( d \)), giving us \( V = A \cdot d \). By rearranging these formulas, we can find the thickness of the ice from energy equations. This dimensional relationship provides a basis for understanding how much material occupies a certain space, crucial when dealing with energy and phase transition calculations in physics.

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Most popular questions from this chapter

A \(2.00-\mu \mathrm{F}\) and a \(4.00-\mu \mathrm{F}\) capacitor are connected to a \(60.0-\mathrm{V}\) battery. What is the total charge supplied to the capacitors when they are wired (a) in parallel and (b) in series with each other?

Two wires have the same cross-sectional area and are joined end to end to form a single wire. One is tungsten, which has a temperature coefficient of resistivity of \(\alpha=0.0045\left(\mathrm{C}^{\circ}\right)^{-1} .\) The other is carbon, for which \(\alpha=-0.0005\left(\mathrm{C}^{\circ}\right)^{-1} .\) The total resistance of the composite wire is the sum of the resistances of the pieces. The total resistance of the composite does not change with temperature. What is the ratio of the lengths of the tungsten and carbon sections? Ignore any changes in length due to thermal expansion.

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A \(7.0-\mu \mathrm{F}\) and a \(3.0-\mu \mathrm{F}\) capacitor are connected in series across a \(24-\mathrm{V}\) battery. What voltage is required to charge a parallel combination of the two capacitors to the same total energy?

A blow-dryer and a vacuum cleaner each operate with a voltage of \(120 \mathrm{V} .\) The current rating of the blow-dryer is \(11 \mathrm{A}\), and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blowdryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one-half hour.

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