Chapter 20: Problem 124
An aluminum wire is hung between two towers and has a length of \(175 \mathrm{m} .\) A current of \(125 \mathrm{A}\) exists in the wire, and the potential difference between the ends of the wire is \(0.300 \mathrm{V} .\) The density of aluminum is \(2700 \mathrm{kg} / \mathrm{m}^{3} .\) Find the mass of the wire.
Short Answer
Step by step solution
Determine the Resistance of the Wire
Use the Resistivity Formula
Calculate the Cross-Sectional Area
Find the Volume of the Wire
Calculate the Mass of the Wire
Provide the Mass of the Wire in a Practical Value
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
- **\( V \) represents the voltage or potential difference (measured in volts)**,
- **\( I \) denotes the current (measured in amperes)**, and
- **\( R \) symbolizes the resistance (measured in ohms)**.
Resistivity
- **\( R \) is resistance**,
- **\( L \) is the length of the wire**, and
- **\( A \) is its cross-sectional area**.