/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 In \(1998,\) NASA launched Deep ... [FREE SOLUTION] | 91Ó°ÊÓ

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In \(1998,\) NASA launched Deep Space \(I(\mathrm{DS}-1),\) a spacecraft that successfully flew by the asteroid named \(1992 \mathrm{KD}\) (which orbits the sun millions of miles from the earth). The propulsion system of DS-1 worked by ejecting high-speed argon ions out the rear of the engine. The engine slowly increased the velocity of DS-1 by about \(+9.0 \mathrm{m} / \mathrm{s}\) per day. (a) How much time (in days) would it take to increase the velocity of \(D S-1\) by \(+2700 m / s ?\) (b) What was the acceleration of DS-1 (in \(\mathrm{m} / \mathrm{s}^{2}\) )?

Short Answer

Expert verified
(a) DS-1 needs 300 days to increase the velocity by 2700 m/s. (b) The acceleration of DS-1 is approximately \(1.04 \times 10^{-4} \text{ m/s}^2\).

Step by step solution

01

Identify the Initial Values

We are given that the propulsion system of the DS-1 spacecraft increases its velocity by \(+9.0\, \text{m/s}\) per day. We need to determine the total change in velocity and the increase required.
02

Determine Time for Velocity Increase

We need to find how long it takes to increase the velocity by \(+2700\, \text{m/s}\). Since each day increases the velocity by \(+9.0\, \text{m/s}\), divide the total change in velocity by the daily increase rate: \[\text{Time (days)} = \frac{2700\, \text{m/s}}{9.0\, \text{m/s per day}} = 300 \text{ days}.\]
03

Calculate Acceleration

Acceleration is defined as the change in velocity per unit time. We know that each day the velocity increases by \(+9.0\, \text{m/s}\). Convert days into seconds to find the acceleration in standard units \((\text{m/s}^2)\):\[1 \text{ day} = 24 \times 60 \times 60 = 86400 \text{ seconds}\]The acceleration per second is:\[\text{Acceleration} = \frac{9.0\, \text{m/s}}{86400 \text{ s}} \approx 1.04 \times 10^{-4}\, \text{m/s}^2.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Laws of Motion
Newton's Laws of Motion are the foundation of classical physics. These laws describe the relationship between a body and the forces acting upon it, and the body's motion in response to those forces. Let's look at each law briefly:

  • First Law (Law of Inertia): A body at rest will stay at rest, and a body in motion will stay in motion at a constant velocity unless acted upon by a net external force.
  • Second Law (Law of Acceleration): The force acting on an object is equal to the mass of that object times its acceleration (\( F = ma \)). This explains how the propulsion of DS-1 results in its acceleration as the force from the engine changes the spacecraft's velocity.
  • Third Law (Action and Reaction): For every action, there is an equal and opposite reaction. This is evident in DS-1’s propulsion by ejecting ions backward, propelling the spacecraft forward.
Understanding these laws helps in analyzing how external forces interact with an object and cause changes in its motion.
Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the forces that cause the motion. It involves parameters like displacement, velocity, and acceleration.

In the case of DS-1, kinematics helped in determining how long it would take to achieve a certain change in velocity. Given that DS-1’s velocity increases by \(+9.0\, \text{m/s}\) each day, you can calculate other parameters of its motion, such as the total time over which this change occurs. To find out how quickly DS-1 reaches a velocity increase of \(+2700\, \text{m/s}\), you divide the total desired change by the daily increase rate (\(+2700 \div 9.0 = 300\, \text{days}\)).

This illustrates the application of kinematic equations and concepts to solve motion problems without directly involving forces.
Spacecraft Propulsion
Spacecraft propulsion is the technology that enables a spacecraft to move through space. The DS-1 spacecraft uses an ion propulsion system, which works by ejecting high-speed ions to create thrust. This is an example of the third law of motion, where the expulsion of ions out of the spacecraft results in a thrust in the opposite direction, accelerating the spacecraft.

Ion propulsion systems are highly efficient compared to traditional chemical rockets. They provide a small but continuous acceleration over a long time, making them ideal for deep space missions like DS-1. Although the acceleration might be extremely small when measured in \( \text{m/s}^2 \), the cumulative effect over days, months, or even years can significantly alter the spacecraft's velocity, enabling it to travel vast distances in space.
Acceleration Calculation
Acceleration is defined as the rate of change of velocity with respect to time. For DS-1, calculating acceleration involves understanding how its velocity change each day translates into standard units like \( \text{m/s}^2\).

Given that DS-1's velocity increases by \(+9.0\, \text{m/s}\) per day, one must convert days into seconds to express acceleration in \( \text{m/s}^2\). Since one day equals \(86400\, \text{seconds}\), the acceleration is calculated as follows:

\[\text{Acceleration} = \frac{9.0\, \text{m/s}}{86400\, \text{s}} \approx 1.04 \times 10^{-4}\, \text{m/s}^2\]

This demonstrates how even minute forces can lead to continuous acceleration in space, a critical concept for understanding spacecraft trajectories and mission planning.

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Most popular questions from this chapter

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