/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 The data in the following table ... [FREE SOLUTION] | 91Ó°ÊÓ

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The data in the following table describe the initial and final positions of a moving car. The elapsed time for each of the three pairs of positions listed in the table is 0.50 s. Review the concept of average velocity in Section 2.2 and then determine the average velocity (magnitude and direction) for each of the three pairs. Note that the algebraic sign of your answers will convey the direction. $$ \begin{array}{lcc} \hline & \text { Initial position } x_{0} & \text { Final position } x \\ \hline \text { (a) } & +2.0 \mathrm{m} & +6.0 \mathrm{m} \\ \text { (b) } & +6.0 \mathrm{m} & +2.0 \mathrm{m} \\ \text { (c) } & -3.0 \mathrm{m} & +7.0 \mathrm{m} \\ \hline \end{array} $$

Short Answer

Expert verified
(a) 8.0 m/s, positive; (b) -8.0 m/s, negative; (c) 20.0 m/s, positive.

Step by step solution

01

Understanding Average Velocity

The average velocity is defined as the change in position (displacement) divided by the time interval during which the change occurred. Mathematically, it is expressed as: \( \text{Average Velocity} = \frac{\Delta x}{\Delta t} \), where \( \Delta x = x - x_0 \) is the change in position and \( \Delta t \) is the time interval.
02

Calculate Average Velocity for Pair (a)

For pair (a), the initial position \( x_0 \) is \( +2.0 \mathrm{m} \) and the final position \( x \) is \( +6.0 \mathrm{m} \). The time interval \( \Delta t \) is 0.50 s. Calculate the displacement: \( \Delta x = x - x_0 = 6.0 \mathrm{m} - 2.0 \mathrm{m} = 4.0 \mathrm{m} \). Then, compute the average velocity: \( \text{Average Velocity} = \frac{4.0 \mathrm{m}}{0.50 \mathrm{s}} = 8.0 \mathrm{m/s} \). The positive sign indicates the direction is positive.
03

Calculate Average Velocity for Pair (b)

For pair (b), the initial position \( x_0 \) is \( +6.0 \mathrm{m} \) and the final position \( x \) is \( +2.0 \mathrm{m} \). Calculate the displacement: \( \Delta x = x - x_0 = 2.0 \mathrm{m} - 6.0 \mathrm{m} = -4.0 \mathrm{m} \). The average velocity is: \( \text{Average Velocity} = \frac{-4.0 \mathrm{m}}{0.50 \mathrm{s}} = -8.0 \mathrm{m/s} \). The negative sign indicates the direction is negative.
04

Calculate Average Velocity for Pair (c)

For pair (c), the initial position \( x_0 \) is \( -3.0 \mathrm{m} \) and the final position \( x \) is \( +7.0 \mathrm{m} \). Calculate the displacement: \( \Delta x = x - x_0 = 7.0 \mathrm{m} - (-3.0 \mathrm{m}) = 10.0 \mathrm{m} \). The average velocity is: \( \text{Average Velocity} = \frac{10.0 \mathrm{m}}{0.50 \mathrm{s}} = 20.0 \mathrm{m/s} \). The positive sign indicates the direction is positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement
Displacement is a key concept in understanding motion. It refers to the change in position of an object from its starting point to its end point. Unlike distance, which considers all paths taken, displacement considers only the straight line between these two points.
This difference is important because displacement has both direction and magnitude, making it a vector quantity. For example, if a car moves from +2.0 m to +6.0 m, its displacement is 4.0 m in the positive direction. Conversely, if the car goes from +6.0 m to +2.0 m, its displacement is -4.0 m, indicating a move to the negative direction. In terms of motion, considering the sign (positive or negative) of displacement helps understand which way an object is moving.
To calculate displacement, the formula is simple:
  • Find the difference between the final position and the initial position: ewline ewline ( Delta x = x - x_0)
In scenarios where the position crosses a point, such as moving from -3.0 m to +7.0 m, displacement shows the object's overall movement relative to a starting point, calculating a 10.0 m journey in the positive direction.
Time Interval
The time interval is a crucial part of calculating average velocity. It represents the amount of time over which the movement occurs. Understanding and identifying the time interval is essential because it directly affects how we perceive the speed of an object's movement.
Consider the set time interval as 0.50 seconds in this case. This constant time frame means that the average velocity tells us how fast displacement occurs within each 0.5 second period.
The time interval helps in equations for determining how quickly a change in position happens:
  • Use the formula to find average velocity: ewline(text{Average Velocity} = \frac{\Delta x}{\Delta t})
  • The \(\Delta t\) represents the duration of 0.50 seconds in these examples.
This consistency assists in comparing how fast different displacements occur over the same period.
Direction of Motion
Direction of motion adds context to displacement and velocity. Much like using a compass to navigate, understanding directions in physics helps in accurately describing how an object moves.
In our examples, the direction of motion is indicated by the sign of displacement and average velocity. A positive sign shows movement towards a positive direction, suggesting forward or upward motion, while a negative sign indicates movement towards a negative direction, signifying backward or downward travel.
Using direction, you can:
  • Identify positive or negative motion through the results of displacement, which is confirmed with velocity calculations.
  • Combine magnitude and direction to fully understand an object's journey.
In practice, if a car moves from +6.0 m to +2.0 m, the negative velocity emphasizes the car is moving in a reverse course. On the contrary, transitioning from -3.0 m to +7.0 m indicates a positive, forward movement.

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Most popular questions from this chapter

The left ventricle of the heart accelerates blood from rest to a velocity of \(+26 \mathrm{cm} / \mathrm{s}\). (a) If the displacement of the blood during the acceleration is \(+2.0 \mathrm{cm},\) determine its acceleration (in \(\left.\mathrm{cm} / \mathrm{s}^{2}\right)\) (b) How much time does blood take to reach its final velocity?

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of \(6.0 \mathrm{m} / \mathrm{s}\) in \(1.5 \mathrm{s}\). Assuming that the player accelerates uniformly, determine the distance he runs.

A car is traveling at \(20.0 \mathrm{m} / \mathrm{s},\) and the driver sees a traffic light turn red. After \(0.530 \mathrm{s}\) (the reaction time), the driver applies the brakes, and the car decelerates at \(7.00 \mathrm{m} / \mathrm{s}^{2} .\) What is the stopping distance of the car, as measured from the point where the driver first sees the red light?

(a) Suppose that a NASCAR race car is moving to the right with a constant velocity of \(+82 \mathrm{m} / \mathrm{s}\). What is the average acceleration of the car? (b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed. What is the average acceleration of the car?

Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is \(6.00 \mathrm{m}\). The stones are thrown with the same speed of \(9.00 \mathrm{m} / \mathrm{s}\). Find the location (above the base of the cliff) of the point where the stones cross paths.

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