/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 A cart is driven by a large prop... [FREE SOLUTION] | 91Ó°ÊÓ

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A cart is driven by a large propeller or fan, which can accelerate or decelerate the cart. The cart starts out at the position \(x=0 \mathrm{m}\), with an initial velocity of \(+5.0 \mathrm{m} / \mathrm{s}\) and a constant acceleration due to the fan. The direction to the right is positive. The cart reaches a maximum position of \(x=+12.5 \mathrm{m},\) where it begins to travel in the negative direction. Find the acceleration of the cart.

Short Answer

Expert verified
The acceleration of the cart is \(-1 \; m/s^2\).

Step by step solution

01

Identify the Known Variables

We start by identifying the variables we know from the problem statement. The initial position of the cart is \( x_0 = 0 \; m \) and the initial velocity is \( v_0 = +5.0 \; m/s \). It reaches a maximum position of \( x = +12.5 \; m \) before changing direction.
02

Understand the Turning Point

At the maximum position, the cart changes direction. This implies that the velocity at \( x = +12.5 \; m \) is \( v = 0 \; m/s \). This is the turning point where the acceleration acts opposite to the direction of the initial velocity.
03

Apply the Kinematic Equation

We will use the kinematic equation: \( v^2 = v_0^2 + 2a(x - x_0) \). At the turning point where the cart stops, \( v = 0 \), \( v_0 = 5.0 \; m/s \), \( x_0 = 0 \; m \), and \( x = 12.5 \; m \). Plug these into the equation.
04

Insert Known Values into Equation

Replacing the known values into the equation: \[0 = (5.0)^2 + 2a(12.5 - 0)\]Which simplifies to:\[0 = 25 + 25a\]
05

Solve for Acceleration

Rearrange the equation to solve for \( a \):\[25a = -25\]Divide both sides by 25:\[a = -1 \; m/s^2\]
06

Conclusion

The acceleration of the cart is \( -1 \; m/s^2 \). The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, slowing the cart down until it stops and reverses direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations are powerful tools in physics that relate different aspects of motion. These equations can tell us about things like velocity, acceleration, and displacement. They are perfect for solving motion problems when an object moves at a constant acceleration.
In this problem, the cart is subject to constant acceleration due to the fan, and we use the kinematic equation:
  • \( v^2 = v_0^2 + 2a(x - x_0) \)
This particular equation is useful because it links the initial velocity \( v_0 \), final velocity \( v \), acceleration \( a \), and the displacement \((x - x_0)\). It's particularly convenient when you're trying to find the acceleration, as long as you have the other values. By plugging in what we know, we can find the unknown acceleration.
Knowing how to use kinematic equations is crucial for solving physics problems that involve motion, especially when forces, accelerations, and speed changes are involved.
Acceleration
Acceleration tells us how quickly an object's velocity changes over time. It can be caused by speeding up, slowing down, or changing direction.
In our exercise, the cart's acceleration is due to the propeller-driven fan. Since we know the cart starts with an initial velocity and then slows down to a stop before reversing direction, we find that the acceleration is in the opposite direction to its initial movement.
  • The calculated acceleration \( a = -1 \, m/s^2 \) shows this deceleration effectively.
The negative sign of the acceleration clearly indicates it's acting opposite to the initial direction of the cart's motion. This means the force applied by the fan is strong enough to not only stop the cart but also reverse its direction of travel.
Understanding acceleration is crucial as it influences how an object moves and interacts with its surroundings under different forces. Recognizing its direction and magnitude is a key skill in physics problem-solving.
Initial Velocity
Initial velocity is the speed at which an object starts its motion. It's one of the essential variables that describe an object's initial state before any forces have been applied or changes in motion have occurred.
In this problem, the cart has an initial velocity of \( +5.0 \, m/s \), indicating it's initially moving towards the right, in the positive direction.
  • This initial value is critical for understanding how the cart will move before the force from the propeller influences its speed and direction.
When addressing kinematics problems, knowing the initial velocity helps us determine how other factors like acceleration and displacement will affect the motion.
For students working on similar problems, it's important to clearly identify the positive and negative directions, which helps when working with initial velocities and subsequent calculations in physics.
Turning Point
A turning point in dynamics is where an object comes to a stop and reverses its direction due to a change in motion. This point is critical as it indicates zero velocity for an instant as the motion transitions.
In our example, the cart reaches its turning point at \( x = +12.5 \, m \), where the velocity becomes \( v = 0 \, m/s \).
  • At this moment, the direction of the force (and corresponding acceleration) is evident as it counteracts the initial motion, bringing the object to rest.
The concept of a turning point helps us solve for acceleration in this problem, as knowing the exact location and conditions under which turning happens can make the calculations straightforward.
Turning points are important in understanding motion as they help reveal how forces act over time to change an object's direction and state of movement.

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Most popular questions from this chapter

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