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Point \(A\) is located \(0.25 \mathrm{m}\) away from a charge of \(-2.1 \times 10^{-9} \mathrm{C}\). Point \(B\) is located \(0.50 \mathrm{m}\) away from the charge. What is the electric potential difference \(V_{B}-V_{A}\) between these two points?

Short Answer

Expert verified
The potential difference \(V_B - V_A = 37.76 \, \mathrm{V}\).

Step by step solution

01

Understanding Electric Potential

The electric potential due to a point charge is given by the formula \( V = \frac{k \cdot q}{r} \), where \( V \) is the potential, \( k \) is Coulomb's constant \( 8.99 \times 10^9 \ \, \mathrm{N m^2/C^2} \), \( q \) is the charge, and \( r \) is the distance from the charge.
02

Calculate Potential at Point A

Using the formula: \( V_A = \frac{k \cdot (-2.1 \times 10^{-9})}{0.25} \). Calculate \( V_A \) and remember that the potential is negative because the charge is negative.
03

Calculate Potential at Point B

Using the formula: \( V_B = \frac{k \cdot (-2.1 \times 10^{-9})}{0.50} \). Calculate \( V_B \) in the same way as for Point A.
04

Determine Potential Difference \(V_B - V_A\)

The potential difference \( V_B - V_A \) is calculated by subtracting the potential at point A from the potential at point B: \( V_B - V_A = V_B - V_A \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is the foundation for understanding electric forces between point charges. It states that the electric force (\( F \)) between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance separating them. This law also introduces the concept of the electromagnetic force as
  • Attractive: If charges have opposite signs.
  • Repulsive: If charges have the same sign.
The formula for Coulomb's Law is:\[F = k \cdot \frac{|q_1 \cdot q_2|}{r^2}\]where \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between the charges. This law is crucial in calculating forces in a variety of physics problems and aids in the understanding of electric potential.
Potential Difference
Potential difference, often referred to as voltage, is a measure of the work needed to move a test charge from one point to another within an electric field. It is represented as the difference in electric potential (\( V \)) between two points. In simpler terms, potential difference tells us how much energy is required to move a charge from point \( A \) to point \( B \).Potential Difference can be calculated using:
  • The potentials at two points in space: \( V_B - V_A = V_B - V_A \)
Potential difference is measured in volts (V) and is an essential concept in creating circuits, electronics, and generally understanding electric fields. In our exercise, it represents the energy change for a charge moving between point A and point B.
Point Charge
A point charge refers to a charged object that is treated as if all its charge is concentrated at a single point in space. This simplification is particularly useful in theoretical problems and calculations where the actual size of the charge doesn't significantly affect the results. Point charges make it straightforward to apply principles such as Coulomb's Law or the calculations of electric potential. Unlike charges spread over an area or volume, a point charge allows us to focus on:
  • The effect at a given distance, as seen in potential or force calculations.
  • Simplifying complex charge distributions into simpler, calculable forms.
The concept of point charge underpins many important calculations in electrostatics, such as those dealing with electric fields and forces.
Coulomb's Constant
Coulomb's constant (\( k \)) is a fundamental value used in electrostatics, specifically in Coulomb's Law and the formula for electric potential. It represents the magnitude of the electric force that two charges of 1 Coulomb each would exert on one another if they were 1 meter apart. The constant is a measure of the strong coupling of electric charges and is given by:\[k = 8.99 \times 10^9 \ \, \mathrm{N \cdot m^2/C^2}\]This constant is crucial for calculations in physics, allowing us to determine the forces and potentials between charges accurately. Coulomb's constant enables you to:
  • Calculate forces between point charges using Coulomb's Law.
  • Determine electric potentials at various points in space when discussing point charges.
It's essential for handling problems in electrostatics, making it a cornerstone of physics education.

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Most popular questions from this chapter

Two equipotential surfaces surround a \(+1.50 \times 10^{-8} \mathrm{C}\) point charge. How far is the \(190-\mathrm{V}\) surface from the \(75.0-\mathrm{V}\) surface?

If the electric field inside a capacitor exceeds the dielectric strength of the dielectric between its plates, the dielectric will break down, discharging and ruining the capacitor. Thus, the dielectric strength is the maximum magnitude that the electric field can have without breakdown occurring. The dielectric strength of air is \(3.0 \times 10^{6} \mathrm{V} / \mathrm{m},\) and that of neoprene rubber is \(1.2 \times 10^{7} \mathrm{V} / \mathrm{m} .\) A certain air-gap, parallel plate capacitor can store no more than 0.075 J of electrical energy before breaking down. How much energy can this capacitor store without breaking down after the gap between its plates is filled with neoprene rubber?

Two identical point charges \(\left(+2.4 \times 10^{-9} \mathrm{C}\right)\) are fixed in place, separated by \(0.50 \mathrm{m}\) (see the figure). Concepts: (i) The electric field is a vector and has a direction. At the midpoint, what are the directions of the individual electric-field contributions from \(q_{A}\) and \(q_{\mathrm{B}} ?\) (ii) Is the magnitude of the net electric field at the midpoint greater than, less than, or equal to zero? (iii) Is the total electric potential at the midpoint positive, negative, or zero? (iv) Does the electric potential have a direction associated with it? Explain. Calculations: Find the electric field and the electric potential at the midpoint of the line between the charges \(q_{A}\) and \(q_{\mathrm{B} .}\)

The capacitance of an empty capacitor is \(1.2 \mu \mathrm{F}\). The capacitor is connected to a \(12-\mathrm{V}\) battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, \(2.6 \times 10^{-5} \mathrm{C}\) of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?

A particle is uncharged and is thrown vertically upward from ground level with a speed of \(25.0 \mathrm{m} / \mathrm{s}\). As a result, it attains a maximum height \(h\). The particle is then given a positive charge \(+q\) and reaches the same maximum height \(h\) when thrown vertically upward with a speed of \(30.0 \mathrm{m} / \mathrm{s}\). The electric potential at the height \(h\) exceeds the electric potential at ground level. Finally, the particle is given a negative charge \(-q .\) Ignoring air resistance, determine the speed with which the negatively charged particle must be thrown vertically upward, so that it attains exactly the maximum height h. In all three situations, be sure to include the effect of gravity.

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