/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 Two blocks are connected by a wi... [FREE SOLUTION] | 91Ó°ÊÓ

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Two blocks are connected by a wire that has a mass per unit length of \(8.50 \times 10^{-4} \mathrm{kg} / \mathrm{m} .\) One block has a mass of \(19.0 \mathrm{kg},\) and the other has a mass of \(42.0 \mathrm{kg} .\) These blocks are being pulled across a horizontal frictionless floor by a horizontal force \(\overrightarrow{\mathbf{P}}\) that is applied to the less massive block. A transverse wave travels on the wire between the blocks with a speed of \(352 \mathrm{m} / \mathrm{s}\) (relative to the wire). The mass of the wire is negligible compared to the mass of the blocks. Find the magnitude of \(\overrightarrow{\mathbf{P}}\)

Short Answer

Expert verified
The magnitude of \( \overrightarrow{\mathbf{P}} \) is 105.32 N.

Step by step solution

01

Understand the Problem

We have two blocks connected by a wire. A force \( \overrightarrow{\mathbf{P}} \) pulls the lighter block, creating tension that allows a transverse wave to travel on the wire at 352 m/s. The goal is to find the magnitude of this force \( \overrightarrow{\mathbf{P}} \).
02

Determine the Tension in the Wire

The tension \( T \) in the wire can be found using the formula for wave speed on a string: \[ v = \sqrt{\frac{T}{\mu}} \]where \( v = 352 \mathrm{m/s} \) is the speed of the wave and \( \mu = 8.50 \times 10^{-4} \mathrm{kg/m} \) is the mass per unit length of the wire. Solve for \( T \) by squaring both sides and rearranging the formula:\[ T = v^{2} \cdot \mu \]
03

Calculate the Tension

Substitute the known values into the tension formula:\[ T = (352)^2 \times 8.50 \times 10^{-4} \]\[ T = 123904 \times 8.50 \times 10^{-4} \]\[ T = 105.3184 \, \mathrm{N} \]
04

Analyze the Forces on the Blocks

Since the mass of the wire is negligible, the tension calculated is the same everywhere in the wire. The horizontal force \( \overrightarrow{\mathbf{P}} \) provides enough energy to maintain this tension while moving both blocks.
05

Calculate Force \( \overrightarrow{\mathbf{P}} \)

To maintain the tension, the force \( \overrightarrow{\mathbf{P}} \) equals the tension since there is no friction and the blocks are on a horizontal plane. Hence, \( \overrightarrow{\mathbf{P}} = T = 105.3184 \mathrm{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in String
When two objects are connected by a string and a force is applied, tension is created along the string. This tension plays a crucial role in the way forces are transmitted between objects. In this context, tension is the result of a pulling force acting along the string, keeping the objects connected tightly.
The tension in the string is affected by
  • the applied force,
  • the mass of the objects,
  • and, in some cases, by friction, which in this problem is absent since the surface is frictionless.
For problems involving waves, like transverse waves traveling on a string, tension determines the wave speed. As depicted in the exercise, the wave speed depends on both the tension in the string and the mass per unit length (often referred to as linear density). These relationships are captured in the wave speed formula: \[ v = \sqrt{\frac{T}{\mu}} \]In essence, greater tension results in faster wave propagation. When the tension is increased, the wave has more energy to travel quickly.
Transverse Waves
Transverse waves are a type of wave where the oscillation or disturbance occurs perpendicular to the direction of wave travel. These are common on strings and wires, where the wave motion is up and down while the wave travels horizontally.
In this scenario, a transverse wave travels along the wire connecting the two blocks. The characteristics of transverse waves include:
  • Amplitude: the height of the wave from its average position,
  • Wavelength: the distance between successive wave crests,
  • Frequency: how often the waves pass a given point per second, and
  • Speed: how fast the wave moves down the wire.
The speed (\( v \)) of a transverse wave is particularly influenced by the tension in the string and the linear density (\( \mu \)), as given by the equation:\[ v = \sqrt{\frac{T}{\mu}} \]Here, we use this relationship to relate the observed wave speed to the tension set by the moving force. This provides a way to calculate the force needed to achieve such wave behaviors.
Force Calculation
Understanding force calculation in this scenario is key to solving for the actual applied force (\( \overrightarrow{\mathbf{P}} \)) that allows the blocks to move and the wave to travel along the string. The first step in the process is calculating the tension, which has already been discussed.
Once the tension is known, it becomes straightforward to calculate the applied force under the given conditions. Since the problem states that the motion happens on a frictionless plane, the tension calculated equals the applied force:\[ \overrightarrow{\mathbf{P}} = T \]The absence of friction simplifies this relationship. It means no other horizontal forces are acting on the blocks besides the applied force. Therefore, the tension required to maintain the wave speed directly translates to the magnitude of the force \( \overrightarrow{\mathbf{P}} \). Thus, ensuring that the total calculated tension represents the complete effect of the pulling force applied to the less massive block.

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Most popular questions from this chapter

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