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A monatomic ideal gas expands at constant pressure. (a) What percentage of the heat being supplied to the gas is used to increase the internal energy of the gas? (b) What percentage is used for doing the work of expansion?

Short Answer

Expert verified
(a) 60% of the heat increases internal energy; (b) 40% is used for work.

Step by step solution

01

Understand the process

We are dealing with a monatomic ideal gas expanding at constant pressure. During this process, heat is supplied to the gas, which can increase its internal energy or do work by expansion.
02

Recall the First Law of Thermodynamics

According to the First Law of Thermodynamics, \( \Delta Q = \Delta U + \Delta W \), where \( \Delta Q \) is the heat added to the system, \( \Delta U \) is the change in internal energy, and \( \Delta W \) is the work done by the system.
03

Define equations for internal energy and work

For a monatomic ideal gas, the change in internal energy is given by \( \Delta U = \frac{3}{2}nR\Delta T \), and the work done is \( \Delta W = P\Delta V \) where \( P \) is pressure and \( \Delta V \) is the change in volume. Remember, \( P\Delta V = nR\Delta T \) under constant pressure.
04

Calculate the percentages

We find that \( \Delta U = \frac{3}{2}nR\Delta T \) and \( \Delta W = nR\Delta T \). Thus, \( \Delta Q = \Delta U + \Delta W = \frac{3}{2}nR\Delta T + nR\Delta T = \frac{5}{2}nR\Delta T \). Therefore, the percentage of heat used to increase internal energy is:\( \frac{\Delta U}{\Delta Q} \times 100 = \frac{\frac{3}{2}nR\Delta T}{\frac{5}{2}nR\Delta T} \times 100 = 60\% \). And the percentage used for doing work is: \( \frac{\Delta W}{\Delta Q} \times 100 = \frac{nR\Delta T}{\frac{5}{2}nR\Delta T} \times 100 = 40\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Law of Thermodynamics
When studying thermodynamics, one of the first principles you'll encounter is the First Law of Thermodynamics, a pivotal concept. This law is a version of the Law of Conservation of Energy, tailored for thermodynamic processes. It essentially states that energy can neither be created nor destroyed. In thermodynamic terms, the law is expressed as:\[ \Delta Q = \Delta U + \Delta W \]where:- \( \Delta Q \) is the heat added to the system- \( \Delta U \) is the change in internal energy- \( \Delta W \) is the work done by the systemThis equation means that the heat supplied to a system does two things: it changes the internal energy of the system, and it performs work. Understanding this balance is crucial for grasping how energy moves and changes form in physical systems.
Internal Energy
Internal energy is the energy contained within a system. It's the sum of all microscopic kinetic and potential energies of the particles within the system. In the context of an ideal gas, internal energy primarily arises from the kinetic energy of gas molecules moving randomly. For a monatomic ideal gas, the change in internal energy \( \Delta U \) is given by the formula:\[ \Delta U = \frac{3}{2}nR\Delta T \]Here:- \( n \) is the number of moles of gas- \( R \) is the universal gas constant- \( \Delta T \) is the change in temperatureThis formula shows that internal energy changes are proportional to temperature changes. This relationship is fundamental for calculations involving heat and work in thermodynamic processes involving ideal gases.
Ideal Gas Law
The Ideal Gas Law links pressure, volume, and temperature of an ideal gas through the equation:\[ PV = nRT \]where:- \( P \) is pressure- \( V \) is volume- \( n \) is the amount of gas in moles- \( R \) is the universal gas constant- \( T \) is temperature in KelvinIn cases where an ideal gas undergoes a process at constant pressure, the Ideal Gas Law helps relate changes in temperature and volume. When a gas expands at constant pressure, as in the exercise, it performs work given by:\[ \Delta W = P\Delta V \]This work done during expansion is specifically related to the volume change of the gas, illustrating how the gas uses some of the heat energy supplied to it.
Heat Transfer
Heat transfer is the movement of thermal energy from one place to another due to temperature difference. In thermodynamic processes, heat transfer is a key factor that causes changes in the system's energy.For an ideal gas, the heat added \( \Delta Q \) impacts both internal energy and mechanical work. As described by the First Law of Thermodynamics, the total heat added is the sum of changes in internal energy and the work done by the gas:\[ \Delta Q = \Delta U + \Delta W \]This distinction is crucial because it tells us exactly how energy supplied as heat is used. Some portion increases the internal kinetic energy of molecules, while another part makes the gas do work, such as expanding against a piston. For a monatomic ideal gas expanding at constant pressure, calculations show that 60% of heat increases internal energy, while 40% is used for doing work. Understanding these proportions provides deeper insight into energy allocation in thermodynamic processes.

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Most popular questions from this chapter

A Carnot air conditioner maintains the temperature in a house at \(297 \mathrm{K}\) on a day when the temperature outside is \(311 \mathrm{K}\). What is the coefficient of performance of the air conditioner?

A power plant taps steam superheated by geothermal energy to \(505 \mathrm{K}\) (the temperature of the hot reservoir) and uses the steam to do work in turning the turbine of an electric generator. The steam is then converted back into water in a condenser at \(323 \mathrm{K}\) (the temperature of the cold reservoir), after which the water is pumped back down into the earth where it is heated again. The output power (work per unit time) of the plant is 84000 kilowatts. Determine (a) the maximum efficiency at which this plant can operate and (b) the minimum amount of rejected heat that must be removed from the condenser every twenty-four hours.

Heat is added isothermally to \(2.5 \mathrm{mol}\) of a monatomic ideal gas. The temperature of the gas is \(430 \mathrm{K}\). How much heat must be added to make the volume of the gas double?

The wattage of a commercial ice maker is \(225 \mathrm{W}\) and is the rate at which it does work. The ice maker operates just like a refrigerator or an air conditioner and has a coefficient of performance of \(3.60 .\) The water going into the unit has a temperature of \(15.0^{\circ} \mathrm{C}\), and the ice maker produces ice cubes at \(0.0^{\circ} \mathrm{C} .\) Ignoring the work needed to keep stored ice from melting, find the maximum amount (in \(\mathrm{kg}\) ) of ice that the unit can produce in one day of continuous operation.

The inside of a Carnot refrigerator is maintained at a temperature of \(277 \mathrm{K},\) while the temperature in the kitchen is \(299 \mathrm{K} .\) Using \(2500 \mathrm{J}\) of work, how much heat can this refrigerator remove from its inside compartment?

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