/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A monatomic ideal gas in a rigid... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A monatomic ideal gas in a rigid container is heated from \(217 \mathrm{K}\) to \(279 \mathrm{K}\) by adding \(8500 \mathrm{J}\) of heat. How many moles of gas are there in the container?

Short Answer

Expert verified
The container holds approximately 10.9 moles of gas.

Step by step solution

01

State the Known Values and Formula

The initial temperature \(T_1 = 217\, \mathrm{K}\) and the final temperature \(T_2 = 279 \, \mathrm{K}\). The heat added \(Q = 8500 \, \mathrm{J}\). A rigid container suggests constant volume, so we use the formula for heat at constant volume: \(Q = nC_v\Delta T\), where \(\Delta T = T_2 - T_1\), \(n\) is the number of moles, and \(C_v\) is the molar heat capacity at constant volume for a monatomic ideal gas, which is \(\frac{3}{2}R\).
02

Calculate the Temperature Change

Calculate the change in temperature \(\Delta T\) using the initial and final temperatures: \(\Delta T = T_2 - T_1 = 279\, \mathrm{K} - 217\, \mathrm{K} = 62\, \mathrm{K}\).
03

Identify the Molar Heat Capacity

For a monatomic ideal gas, the molar heat capacity at constant volume \(C_v = \frac{3}{2} R\), where \(R = 8.314 \, \mathrm{J/(mol \, K)}\). So, \(C_v = \frac{3}{2} \times 8.314 = 12.471 \, \mathrm{J/(mol \, K)}\).
04

Calculate the Number of Moles of Gas

Rearrange the formula \(Q = nC_v\Delta T\) to solve for \(n\): \(n = \frac{Q}{C_v\Delta T}\). Substitute the values \(Q = 8500\, \mathrm{J}\), \(C_v = 12.471 \, \mathrm{J/(mol \, K)}\), and \(\Delta T = 62 \, \mathrm{K}\) to find \(n\): \(n = \frac{8500}{12.471 \times 62}\approx 10.9\).
05

Conclusion

The number of moles of the gas in the container is approximately \(10.9\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Heat Capacity
Molar heat capacity is an important concept when studying gases and thermodynamics. It refers to the amount of heat needed to raise the temperature of one mole of a substance by one Kelvin. For different states of matter or types of substances, the molar heat capacity can vary. In the case of a monatomic ideal gas, which consists of single atoms like helium or neon, the molar heat capacity at constant volume ( \(C_v\) ) is particularly simple to determine.

### Why is it \( \frac{3}{2}R\) for a Monatomic Ideal Gas?When a monatomic ideal gas is at constant volume, its internal energy change directly correlates to changes in temperature, without the gas performing work. From kinetic molecular theory, we understand that the degrees of freedom for a monatomic gas relate to its three translational motions: moving in the x, y, and z directions. This is why we use the formula \( C_v = \frac{3}{2}R \) , where \( R \) is the ideal gas constant (\( 8.314 \, \text{J/(mol K)} \)).
  • It's essential because it allows you to determine how much energy is absorbed or released as the gas changes temperature.
  • The value for \( C_v \) remains constant for any monatomic ideal gas in the absence of phase change or any additional work done.
Temperature Change
Understanding the concept of temperature change is crucial in thermodynamics, especially when dealing with ideal gases. Temperature provides a measure of the average kinetic energy of the particles in a substance. When heat is added to a monatomic ideal gas, it results in a temperature change, provided the volume is constant.

### Calculating Temperature ChangeTo find the change in temperature, you subtract the initial temperature from the final one: \( \Delta T = T_2 - T_1 \). In this specific example, the gas is heated from \(217 \, \text{K} \) to \(279 \, \text{K} \) , leading to a temperature change of \(62 \, \text{K} \).
  • Temperature change is a direct indicator of how energy is absorbed or released by the gas.
  • It is an absolute value and doesn't depend on the substance's path between two states.
In real-world applications, knowing the temperature change helps to calculate other essential parameters like the heat absorbed, especially when combined with the ideal gas law.
Monatomic Ideal Gas
A monatomic ideal gas is one of the simplest models in physics, used to illustrate basic thermodynamic principles. Monatomic means the gas is composed of single atoms, as opposed to more complex molecules. Examples include noble gases such as helium and neon. The term 'ideal gas' refers to a theoretical gas that perfectly fits all the assumptions of the kinetic molecular theory, including no intermolecular attractions and infinite, elastic collisions.

### Properties of Monatomic Ideal Gases
  • They have three degrees of freedom corresponding to movement in the three spatial dimensions.
  • Their behavior can often be predicted using the ideal gas law: \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is moles, \( R \) is the gas constant, and \( T \) is temperature.
  • Understanding these gases provides a baseline for more complex gas behaviors and is foundational in thermodynamics calculations.
Due to their simplicity, monatomic ideal gases have specific molar heat capacities that are consistent across different types of these gases, simplifying the calculations needed to analyze changes in their systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Beginning with a pressure of \(2.20 \times 10^{5}\) Pa and a volume of \(6.34 \times 10^{-3} \mathrm{m}^{3},\) an ideal monatomic gas \(\left(\gamma=\frac{5}{3}\right)\) undergoes an adiabatic expansion such that its final pressure is \(8.15 \times 10^{4} \mathrm{Pa}\). An alternative process leading to the same final state begins with an isochoric cooling to the final pressure, followed by an isobaric expansion to the final volume. How much more work does the gas do in the adiabatic process than in the alternative process?

A Carnot engine has an efficiency of \(0.55 .\) If this engine were run backward as a heat pump, what would be the coefficient of performance?

Heat is added to two identical samples of a monatomic ideal gas. In the first sample the heat is added while the volume of the gas is kept constant, and the heat causes the temperature to rise by \(75 \mathrm{K}\). In the second sample, an identical amount of heat is added while the pressure (but not the volume) of the gas is kept constant. By how much does the temperature of this sample increase?

Carnot engine A has an efficiency of 0.60, and Carnot engine B has an ethciency of \(0.80 .\) Both engines utilize the same hot reservoir, which has a temperature of \(650 \mathrm{K}\) and delivers \(1200 \mathrm{J}\) of heat to each engine. Find the magnitude of the work produced by each engine and the temperatures of the cold reservoirs that they use.

A Carnot heat pump operates between an outdoor temperature of 265 \(\mathrm{K}\) and an indoor temperature of \(298 \mathrm{K}\). Find its coefficient of performance.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.