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In 10.0 s, 200 bullets strike and embed themselves in a wall. The bullets strike the wall perpendicularly. Each bullet has a mass of \(5.0 \times 10^{-3} \mathrm{kg}\) and a speed of \(1200 \mathrm{m} / \mathrm{s}\). (a) What is the average change in momentum per second for the bullets? (b) Determine the average force exerted on the wall. (c) Assuming the bullets are spread out over an area of \(3.0 \times 10^{-4} \mathrm{m}^{2},\) obtain the average pressure they exert on this region of the wall.

Short Answer

Expert verified
(a) 120 kg路m/s虏; (b) 120 N; (c) 4.0 脳 10鈦 N/m虏.

Step by step solution

01

Calculate Individual Bullet's Momentum

Momentum is given by the equation \( p = mv \), where \( m \) is mass and \( v \) is velocity. For one bullet, \( m = 5.0 \times 10^{-3} \text{ kg} \) and \( v = 1200 \text{ m/s} \). Thus, the momentum is \( p = 5.0 \times 10^{-3} \times 1200 = 6 \text{ kg}\cdot\text{m/s} \).
02

Find Total Change in Momentum for All Bullets

Since 200 bullets hit the wall, the total change in momentum is \( 200 \times 6 = 1200 \text{ kg}\cdot\text{m/s} \).
03

Average Change in Momentum Per Second

The bullets strike the wall over a span of 10 seconds. Thus, the average change in momentum per second is \( \frac{1200}{10} = 120 \text{ kg}\cdot\text{m/s}^2 \).
04

Calculate Average Force Exerted on the Wall

Force is the rate of change of momentum, so the average force \( F \) on the wall per second is equal to the average change in momentum per second: \( F = 120 \text{ N} \).
05

Determine the Pressure Exerted on the Wall

Pressure is given by the equation \( P = \frac{F}{A} \), where \( F \) is force and \( A \) is area. Using \( F = 120 \text{ N} \) and \( A = 3.0 \times 10^{-4} \text{ m}^2 \), the pressure is \( P = \frac{120}{3.0 \times 10^{-4}} = 4.0 \times 10^5 \text{ N/m}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Force
Force is a push or pull that can change the motion of an object. It is directly related to momentum and impulse. The equation for force, derived from Newton's second law, is \( F = ma \), where \( F \) stands for force, \( m \) for mass, and \( a \) for acceleration. In the context of the exercise, force affects the bullet when it strikes the wall.
Force can also be expressed using momentum. In this scenario, force is calculated as the change in momentum over time, \( F = \frac{\Delta p}{\Delta t} \). Here, \( \Delta p \) is the change in momentum and \( \Delta t \) the time period over which this change occurs. When the 200 bullets hit the wall in 10 seconds, they exert an average force of 120 N on the wall. This is due to the mass and velocity of the bullets, as they combine to form the momentum which changes as the bullets stop at the wall.
Key points to remember:
  • Force is a vector quantity that can cause an object to accelerate.
  • It is calculated using mass and acceleration or change in momentum over time.
  • In this exercise, the force is the result of bullets hitting and stopping at the wall perpendicularly.
Exploring Pressure
Pressure is the force applied on a specific area. It shows how concentrated or spread out a force is over an area. Mathematically, it is calculated using the formula \( P = \frac{F}{A} \), where \( P \) represents pressure, \( F \) force, and \( A \) is the area over which the force is spread.
In this exercise, bullets exert pressure on a region of the wall. Given that the average force exerted by the bullets is 120 N and they impact an area of \( 3.0 \times 10^{-4} \) m虏, the pressure can be calculated as \( 4.0 \times 10^5 \) N/m虏. This illustrates how pressure increases when a force is spread over a smaller area.
These points are crucial to understanding pressure:
  • Pressure helps determine how much force is distributed over a surface.
  • It indicates stress levels on the surface area, useful in structural mechanics.
  • High pressure can cause damage; understanding it helps in designing stronger materials and structures.
  • In this problem, the concentrated impact of bullets on a small area results in high pressure.
Kinematics and Motion
Kinematics is the study of motion without considering the forces causing it. In our exercise, it deals with how the bullets move towards the wall. The kinematic equations help describe the motion in terms of speed and mass.
For the bullets, the initial speed is 1200 m/s before impact, and the effective motion stops once they embed in the wall. Understanding kinematics helps in measuring different aspects of moving objects like velocity, acceleration, and displacement, even though the underlying forces aren't part of the equations directly.
Kinematics provides insight into:
  • How objects move in terms of speed and trajectory.
  • Understanding stopping distances for safety in environments with moving hazards.
  • The ability to predict future positions of moving objects given certain initial parameters.
  • Key in determining the initial conditions before calculating resultant pressures and forces as seen in bullet impacts.
Impulse and Momentum
Impulse is closely linked to momentum. It is the effect of a force applied over time, changing an object's momentum. The impulse-momentum theorem states that impulse \( J \) equals the change in momentum \( \Delta p \), expressed as \( J = \Delta p = F \cdot \Delta t \).
In this exercise, as bullets hit the wall, their momentum changes from \( 6 \) kg路m/s to \( 0 \) upon stopping. Since 200 bullets strike the wall, the cumulative impulse experienced by the wall is considerable. Each impact adds up, resulting in a total change in momentum of 1200 kg路m/s over 10 seconds. The sustained force and total impulse delivered to the wall characterize how effectively the bullets can penetrate or stop upon impact.
Impulse and momentum concepts clarify:
  • The relationship between force, time, and changes in momentum.
  • Why certain impacts cause greater damage despite similar force magnitudes.
  • How effective applying force over more or less time changes an object's speed.
  • Critical in designing safety mechanisms to absorb force over time, reducing injuries or damages.

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Most popular questions from this chapter

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