/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 A cylindrical glass beaker of he... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A cylindrical glass beaker of height \(1.520 \mathrm{m}\) rests on a table. The bottom half of the beaker is filled with a gas, and the top half is filled with liquid mercury that is exposed to the atmosphere. The gas and mercury do not mix because they are separated by a frictionless movable piston of negligible mass and thickness. The initial temperature is \(273 \mathrm{K}\). The temperature is increased until a value is reached when one-half of the mercury has spilled out. Ignore the thermal expansion of the glass and the mercury, and find this temperature.

Short Answer

Expert verified
The final temperature is 409.5 K.

Step by step solution

01

Identify Initial Volumes

The initial volume of the gas is half the beaker's volume, while the other half is filled with mercury. Since the total height of the beaker is 1.520 m, each half has a height of 0.760 m.
02

State Charles's Law

Charles's Law states that the volume of a gas is directly proportional to its temperature when pressure is constant. The formula is given by \( V_1 / T_1 = V_2 / T_2 \), where \( V_1 \) and \( T_1 \) are the initial volume and temperature, and \( V_2 \) and \( T_2 \) are the final volume and temperature of the gas.
03

Determine Final Volume of Gas

After half of the mercury spills out, the gas fills three-quarters of the beaker's volume. This corresponds to a height of 1.140 m (0.760 m of the initial gas plus half of the mercury, which was 0.760 m, resulting in 0.760 m + 0.380 m).
04

Apply Charles's Law

Knowing that \( T_1 = 273 \mathrm{K} \) and \( V_1 = 0.760 \mathrm{m} \), calculate \( T_2 \) when \( V_2 = 1.140 \mathrm{m} \). Using the formula, rearrange to find the temperature: \( T_2 = T_1 \times \frac{V_2}{V_1} = 273 \times \frac{1.140}{0.760} \).
05

Calculate Final Temperature

Substitute and calculate \( T_2 \): \( T_2 = 273 \times 1.5 = 409.5 \mathrm{K} \). Therefore, the final temperature when half of the mercury has spilled out is 409.5 K.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Expansion
Thermal expansion is a fundamental concept in physics where materials change their volume, area, or length in response to temperature changes. While solids like glass and mercury typically experience only small changes, gases display much more noticeable expansion.
For this exercise, thermal expansion refers to how gases behave when heated. As the temperature increases, the gas molecules move more vigorously, causing them to take up more space. This results in the volume expansion of the gas. However, in our original problem, we deliberately ignored the thermal expansion of the glass beaker and mercury, focusing only on the gas since its expansion significantly affects the outcome of the problem. Understanding how thermal expansion impacts different states of matter helps us predict and manage changes in conditions, particularly when temperature and volume interact directly.
Ideal Gas Law
The ideal gas law is a critical equation in understanding the behavior of gases. It combines several simple gas laws, connecting pressure (P), volume (V), and temperature (T) using the equation: \( PV = nRT \), where \( n \) is the number of moles of gas and \( R \) is the ideal gas constant.
While our exercise focuses on Charles's Law, which is a component of the ideal gas law, it's essential to grasp how these individual relationships come together to describe gas behavior under various conditions. In simple terms, the ideal gas law indicates that if volume increases while the number of moles and pressure stay constant, the temperature must also rise for the equation to hold true.
This comprehensive view provided by the ideal gas law can predict the effects of temperature changes on gas volume, making it a fundamental concept in both theoretical and practical applications involving gases.
Temperature and Volume Relationship
The relationship between temperature and volume is captured by Charles's Law, a special case of the ideal gas law. According to Charles's Law, when a gas is kept at constant pressure, its volume is directly proportional to its temperature, measured in Kelvin. This relationship can be shown as \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \).
In our exercise, this law is pivotal for calculating the temperature at which half the mercury spills out of the beaker. By understanding that as the temperature rises, so does the volume, and vice versa, we can predict and calculate the changes needed to achieve specific conditions.
This straightforward relationship simplifies complex processes and is useful in everyday applications, such as inflating balloons or designing systems that utilize gases. It's a clear example of how basic physical laws hold true across different scenarios, making them crucial tools in scientific exploration and engineering.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(0.030-\mathrm{m}^{3}\) container is initially evacuated. Then, \(4.0 \mathrm{g}\) of water is placed in the container, and, after some time, all the water evaporates. If the temperature of the water vapor is \(388 \mathrm{K},\) what is its pressure?

When you push down on the handle of a bicycle pump, a piston in the pump cylinder compresses the air inside the cylinder. When the pressure in the cylinder is greater than the pressure inside the inner tube to which the pump is attached, air begins to flow from the pump to the inner tube. As a biker slowly begins to push down the handle of a bicycle pump, the pressure inside the cylinder is \(1.0 \times 10^{5} \mathrm{Pa}\), and the piston in the pump is \(0.55 \mathrm{m}\) above the bottom of the cylinder. The pressure inside the inner tube is \(2.4 \times 10^{5} \mathrm{Pa}\). How far down must the biker push the handle before air begins to flow from the pump to the inner tube? Ignore the air in the hose connecting the pump to the inner tube, and assume that the temperature of the air in the pump cylinder does not change.

Manufacturers of headache remedies routinely claim that their own brands are more potent pain relievers than the competing brands. Their way of making the comparison is to compare the number of molecules in the standard dosage. Tylenol uses \(325 \mathrm{mg}\) of acetaminophen \(\left(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}_{2}\right)\) as the standard dose, whereas Advil uses \(2.00 \times 10^{2} \mathrm{mg}\) of ibuprofen \(\left(\mathrm{C}_{13} \mathrm{H}_{18} \mathrm{O}_{2}\right) .\) Find the number of molecules of pain reliever in the standard doses of (a) Tylenol and (b) Advil.

Insects do not have lungs as we do, nor do they breathe through their mouths. Instead, they have a system of tiny tubes, called tracheae, through which oxygen diffuses into their bodies. The tracheae begin at the surface of an insect's body and penetrate into the interior. Suppose that a trachea is \(1.9 \mathrm{mm}\) long with a cross-sectional area of \(2.1 \times 10^{-9} \mathrm{m}^{2}\) The concentration of oxygen in the air outside the insect is \(0.28 \mathrm{kg} / \mathrm{m}^{3}\), and the diffusion constant is \(1.1 \times 10^{-5} \mathrm{m}^{2} / \mathrm{s} .\) If the mass per second of oxygen diffusing through a trachea is \(1.7 \times 10^{-12} \mathrm{kg} / \mathrm{s},\) find the oxygen concentration at the interior end of the tube.

The chlorophyll-a molecule \(\left(\mathrm{C}_{55} \mathrm{H}_{72} \mathrm{MgN}_{4} \mathrm{O}_{5}\right)\) is important in photosynthesis. (a) Determine its molecular mass (in atomic mass units). (b) What is the mass (in grams) of 3.00 moles of chlorophyll-a molecules?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.