/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 A Goodyear blimp typically conta... [FREE SOLUTION] | 91Ó°ÊÓ

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A Goodyear blimp typically contains \(5400 \mathrm{m}^{3}\) of helium (He) at an absolute pressure of \(1.1 \times 10^{5}\) Pa. The temperature of the helium is 280 K. What is the mass (in kg) of the helium in the blimp?

Short Answer

Expert verified
Approximately 1016.45 kg.

Step by step solution

01

Identify Known Values

List the given values:- Volume (V): 5400 \( \text{m}^3 \)- Pressure (P): \(1.1 \times 10^{5}\) Pa- Temperature (T): 280 K- Molar mass of helium (M): 4 g/mol (or 0.004 kg/mol).
02

Use the Ideal Gas Law

The ideal gas law is given by \( PV = nRT \).Rearrange to solve for the number of moles ( n):\[ n = \frac{PV}{RT} \]
03

Calculate the Number of Moles

Substitute the known values into the equation:\[ n = \frac{(1.1 \times 10^{5}\, \text{Pa}) \times (5400\, \text{m}^3)}{(8.314\, \text{J}\, \text{mol}^{-1}\, \text{K}^{-1}) \times (280\, \text{K})} \]Calculate:\( n \approx 254112.99 \) moles.
04

Calculate the Mass of Helium

Use the formula \( m = n \times M \) to find the mass.With \( M = 0.004 \text{ kg/mol} \), calculate:\[ m = 254112.99 \times 0.004 \approx 1016.45 \text{ kg} \]
05

Finalize the Answer

Thus, the mass of helium in the blimp is approximately \(1016.45\) kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moles Calculation
To find out how many moles of a gas are present in a certain volume and conditions, we use the Ideal Gas Law, which is a fundamental equation in chemistry and physics. This equation is expressed as:\[ PV = nRT \]Here, \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant (8.314 J/mol K), and \( T \) is the temperature in Kelvin.
If you need to calculate the number of moles \( n \), you rearrange the formula as:\[ n = \frac{PV}{RT} \]This equation tells you that the number of moles is directly proportional to the pressure and volume, and inversely proportional to the temperature, meaning that if the pressure or volume increases, the number of moles will also increase, while an increase in temperature will decrease the number of moles needed to create the same pressure and volume under ideal conditions.
When working with real-world problems, like in our exercise, make sure you have all values in proper units: Pressure in Pascals (Pa), Volume in cubic meters (m³), and Temperature in Kelvin (K). This ensures the equation works correctly.
Helium Properties
Helium is quite unique and has special properties that make it very different from other gasses. Understanding these properties is important when it comes to calculations involving helium, especially in applications such as airships.
  • Helium is a lighter-than-air gas, which explains its use in balloons and airships like blimps to provide lift.
  • It is non-reactive, meaning it doesn't combust or react with other substances easily.
  • Helium has a relatively low molecular weight of 4 g/mol (or 0.004 kg/mol), which contributes to its buoyant properties.

These characteristics make helium stable, safe, and effective for lifting, as it won't ignite or react dangerously even in open air. Its low molecular weight, when compared to other gases, is a crucial factor in determining how many moles to expect in a given volume and ultimately helps us convert moles into mass for practical computations.
Gas Mass Calculation
Once you have determined the number of moles present in a gas, converting this to mass is straightforward with the help of the molar mass.The molar mass of a substance is the mass of one mole of that substance, which means it is usually expressed in grams per mole (g/mol). In our exercise, we found that helium has a molar mass of 4 g/mol, equivalent to 0.004 kg/mol when converted to kilograms.
The formula you use for calculating the mass \( m \) of a gas is simply:\[ m = n \times M \]Where \( n \) is the number of moles (which we've calculated with the ideal gas law), and \( M \) is the molar mass. Calculating the mass helps in determining how much of the gas is present in terms of weight rather than moles. For instance, in our blimp scenario, multiplying the number of moles by the molar mass of helium gives us a mass of approximately 1016.45 kg.
This conversion from moles to mass is key in practical applications where physical quantities like weight are more useful than moles, such as measuring how much material is needed for lift or how much to transport.

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Most popular questions from this chapter

A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon contains \(0.034 \mathrm{m}^{3}\) of helium at an absolute pressure of \(1.2 \times 10^{5} \mathrm{Pa} .\) The cylinder contains helium at an absolute pressure of \(1.6 \times 10^{7} \mathrm{Pa}\) and has a volume of \(0.0031 \mathrm{m}^{3} .\) The temperature of the helium in the tank and in the balloons is the same and remains constant. What is the maximum number of balloons that can be filled?

Two gas cylinders are identical. One contains the monatomic gas argon (Ar), and the other contains an equal mass of the monatomic gas krypton (Kr). The pressures in the cylinders are the same, but the temperatures are different. Determine the ratio \(\frac{\overline{\mathrm{KE}}_{\mathrm{Krypton}}}{\overline{\mathrm{KE}}_{\mathrm{Argon}}}\) of the average kinetic energy of a krypton atom to the average kinetic energy of an argon atom.

A tank contains 0.85 mol of molecular nitrogen ( \(\mathrm{N}_{2}\) ). Determine the mass (in grams) of nitrogen that must be removed from the tank in order to lower the pressure from 38 to 25 atm. Assume that the volume and temperature of the nitrogen in the tank do not change.

Initially, the translational rms speed of a molecule of an ideal gas is \(463 \mathrm{m} / \mathrm{s}\). The pressure and volume of this gas are kept constant, while the number of molecules is doubled. What is the final translational rms speed of the molecules?

Air is primarily a mixture of nitrogen \(\mathrm{N}_{2}\) (molecular mass \(=\) \(28.0 \mathrm{u}\) ) and oxygen \(\mathrm{O}_{2}\) (molecular mass \(=32.0 \mathrm{u}\) ). Assume that each behaves like an ideal gas and determine the rms speed of the nitrogen and oxygen molecules when the air temperature is \(293 \mathrm{K}\).

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