/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 The amount of heat per second co... [FREE SOLUTION] | 91Ó°ÊÓ

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The amount of heat per second conducted from the blood capillaries beneath the skin to the surface is \(240 \mathrm{J} / \mathrm{s} .\) The energy is transferred a distance of \(2.0 \times 10^{-3} \mathrm{m}\) through a body whose surface area is \(1.6 \mathrm{m}^{2} .\) Assuming that the thermal conductivity is that of body fat, determine the temperature difference between the capillaries and the surface of the skin.

Short Answer

Expert verified
The temperature difference is 1.5°C.

Step by step solution

01

Identify the Knowns

We are given the heat transfer rate, \( Q = 240 \, \text{J/s} \), the distance \( d = 2.0 \times 10^{-3} \, \text{m} \), and the surface area \( A = 1.6 \, \text{m}^2 \). The thermal conductivity of body fat \( k = 0.2 \, \text{W/m} \cdot \text{°C} \).
02

Apply the Heat Conduction Formula

The heat conduction can be described using Fourier’s law: \[ Q = \frac{k \, A \, \Delta T}{d} \]. We need to solve for the temperature difference \( \Delta T \) between the capillaries and the surface of the skin.
03

Rearrange the Formula

Rearrange the formula to solve for \( \Delta T \): \[ \Delta T = \frac{Q \cdot d}{k \cdot A} \].
04

Substitute the Known Values

Plug in the known values into the equation: \[ \Delta T = \frac{240 \, \text{J/s} \times 2.0 \times 10^{-3} \, \text{m}}{0.2 \, \text{W/m} \cdot \text{°C} \times 1.6 \, \text{m}^2} \].
05

Calculate the Temperature Difference

Perform the calculation: \[ \Delta T = \frac{240 \times 2.0 \times 10^{-3}}{0.2 \times 1.6} = 1.5 \text{°C} \]. This is the temperature difference between the capillaries and the skin surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Conductivity
Thermal conductivity is a measure of a material's ability to conduct heat. It is denoted by the symbol \( k \) and is usually expressed in the units of watts per meter-kelvin (W/m·K) or watts per meter-degree Celsius (W/m·°C).

In simple terms, thermal conductivity determines how quickly heat can pass through a material. A higher \( k \) value indicates that the material is more effective at heat transfer. For instance, metals typically have high thermal conductivity, which is why they're often used in cooking utensils and heat exchangers. On the other hand, materials like wood or plastic have low thermal conductivity and are used as insulators.

In the given exercise, the thermal conductivity of body fat is important. This property helps us understand how heat moves from the blood capillaries under the skin to the skin's surface. Since body fat has a low thermal conductivity, it's not an excellent conductor of heat, which helps in maintaining the body's internal temperature by slowing down heat transfer.
Fourier's Law
Fourier's law of heat conduction provides a fundamental understanding of how heat, or thermal energy, is transferred through a material. The law states that the rate of heat transfer through a material is proportional to the negative gradient of temperatures and the area through which the heat flows. Mathematically, it is expressed as: \[ Q = \frac{k \cdot A \cdot \Delta T}{d} \]where:
  • \( Q \) is the heat transfer rate (in joules per second or watts)
  • \( k \) is the material's thermal conductivity
  • \( A \) is the cross-sectional area through which heat is being transferred
  • \( \Delta T \) is the temperature difference across the material
  • \( d \) is the thickness or distance the heat travels


This law helps engineers and scientists predict how much heat will flow through materials under certain conditions. In our problem, Fourier's law allows us to calculate the temperature difference between two points separated by a layer of body fat.
Temperature Difference
The temperature difference, denoted as \( \Delta T \), is a crucial factor in understanding heat transfer. It represents the change in temperature between two points. In thermal conduction problems, this difference drives the flow of heat.

The larger the temperature difference, the more heat flows from the warmer region to the cooler region per unit time, assuming other factors remain constant. For instance, in our exercise, the heat flows from the warm blood capillaries underneath the skin to the cooler surface of the skin.

In the application of Fourier's law, \( \Delta T \) is calculated by rearranging the formula: \[ \Delta T = \frac{Q \cdot d}{k \cdot A} \]By substituting the known values, we find that the temperature difference in our scenario is 1.5°C. Understanding this concept is essential in engineering and everyday applications, like designing buildings and clothing that effectively regulate temperature.

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Most popular questions from this chapter

A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processes are generating, its temperature will drop. If the drop is severe, it can be life-threatening. Suppose that a person is unclothed and energy is being lost via radiation from a body surface area of \(1.40 \mathrm{m}^{2},\) which has a temperature of \(34^{\circ} \mathrm{C}\) and an emissivity of \(0.700 .\) Also suppose that metabolic processes are producing energy at a rate of \(115 \mathrm{J} / \mathrm{s} .\) What is the temperature of the coldest room in which this person could stand and not experience a drop in body temperature?

A pot of water is boiling under one atmosphere of pressure. Assume that heat enters the pot only through its bottom, which is copper and rests on a heating element. In two minutes, the mass of water boiled away is \(m=0.45 \mathrm{kg} .\) The radius of the pot bottom is \(R=6.5 \mathrm{cm},\) and the thickness is \(L=2.0 \mathrm{mm} .\) What is the temperature \(T_{\mathrm{E}}\) of the heating element in contact with the pot?

Sirius \(\mathrm{B}\) is a white star that has a surface temperature (in kelvins) that is four times that of our sun. Sirius \(\mathrm{B}\) radiates only 0.040 times the power radiated by the sun. Our sun has a radius of \(6.96 \times 10^{8} \mathrm{m} .\) Assuming that Sirius B has the same emissivity as the sun, find the radius of Sirius B.

A baking dish is removed from a hot oven and placed on a cooling rack. As the dish cools down to \(35^{\circ} \mathrm{C}\) from \(175^{\circ} \mathrm{C},\) its net radiant power decreases to \(12.0 \mathrm{W}\). What was the net radiant power of the baking dish when it was first removed from the oven? Assume that the temperature in the kitchen remains at \(22^{\circ} \mathrm{C}\) as the dish cools down.

Two pots are identical except that the flat bottom of one is aluminum, whereas that of the other is copper. Water in these pots is boiling away at \(100.0^{\circ} \mathrm{C}\) at the same rate. The temperature of the heating element on which the aluminum bottom is sitting is \(155.0^{\circ} \mathrm{C} .\) Assume that heat enters the water only through the bottoms of the pots and find the temperature of the heating element on which the copper bottom rests.

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