/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 98 Mercury is poured into a tall gl... [FREE SOLUTION] | 91Ó°ÊÓ

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Mercury is poured into a tall glass. Ethyl alcohol (which does not mix with mercury) is then poured on top of the mercury until the height of the ethyl alcohol itself is \(110\) \(\mathrm{cm} .\) The air pressure at the top of the ethyl alcohol is one atmosphere. What is the absolute pressure at a point that is \(7.10\) \(\mathrm{cm}\) below the ethyl alcohol-mercury interface?

Short Answer

Expert verified
The absolute pressure is 1,193,545.4 dynes/cm².

Step by step solution

01

Understand the Problem

We have two types of liquid in a glass: mercury at the bottom and ethyl alcohol on top. We need to find the absolute pressure 7.10 cm below the interface between ethyl alcohol and mercury, with air pressure at 1 atmosphere at the top.
02

Define the Variables

The pressure at a depth in a fluid depends on the density, gravitational acceleration, and depth of the liquid. Let's denote: \( \rho_{a} = 0.789 \text{ g/cm}^3 \) (density of ethyl alcohol), \( h_{a} = 110 \text{ cm} \) (height of ethyl alcohol), \( \rho_{m} = 13.6 \text{ g/cm}^3 \) (density of mercury), \( d = 7.10 \text{ cm} \) (depth below ethyl alcohol), and \( P_{atm} = 1 \text{ atm} \).
03

Calculate Pressure from Ethyl Alcohol

The pressure contribution from the ethyl alcohol layer is given by \( P_{a} = \rho_{a} \cdot g \cdot h_{a} \), where \( g = 980 \text{ cm/s}^2 \). Substituting the values: \( P_{a} = 0.789 \times 980 \times 110 \).
04

Calculate Pressure from Mercury

The additional pressure from mercury because you are a total of 7.10 cm below the interface is due to this depth, \( d = 7.10 \text{ cm} \). The pressure contribution is \( P_{m} = \rho_{m} \cdot g \cdot d \), substituting gives \( P_{m} = 13.6 \times 980 \times 7.10 \).
05

Compute Total Absolute Pressure

The total absolute pressure is the sum of atmospheric pressure, pressure due to ethyl alcohol, and pressure due to mercury: \( P_{total} = P_{atm} + P_{a} + P_{m} \). Convert 1 atm to dynes/cm^2, which is \( 1.013 \times 10^{6} \text{ dynes/cm}^2 \). Add all components to find \( P_{total} \).
06

Perform the Addition

Substitute all calculated values: \( P_{a} = 85,158.6 \text{ dynes/cm}^2 \), \( P_{m} = 95,386.8 \text{ dynes/cm}^2 \), \( P_{atm} = 1.013 \times 10^6 \text{ dynes/cm}^2 \). Thus, \( P_{total} = 1.013 \times 10^6 + 85,158.6 + 95,386.8 = 1,193,545.4 \text{ dynes/cm}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mercury
Mercury is a dense, shiny liquid metal commonly used in scientific instruments like barometers and thermometers. In this exercise, mercury forms the bottom layer of a two-layered liquid system in a tall glass. Since mercury is significantly denser than many other liquids, such as ethyl alcohol, it settles at the bottom when combined with them.
If you are looking to understand why mercury behaves this way, consider its density compared to other liquids. It is approximately 13.6 times denser than water at room temperature. This high density also makes mercury useful for measuring pressure differences, as seen in this problem. It provides a clearer difference in pressure for small changes in depth compared to lighter liquids.
Ethyl Alcohol
Ethyl alcohol, also known as ethanol, is a common organic compound used in beverages and as a solvent. In the context of this exercise, it acts as the top layer above mercury in the glass. Ethyl alcohol is less dense than mercury, allowing it to float and create a separate, distinct layer.
To understand the role of ethyl alcohol in our problem, we need to look at its density, which is about 0.789 g/cm³. This density difference is why ethyl alcohol does not mix with mercury and instead positions itself above it. Its presence adds an additional layer of fluid pressure which must be calculated to determine the absolute pressure at a point beneath both fluids.
Absolute Pressure
Absolute pressure is the total pressure measured from zero, including all atmospheric and fluid pressures applied at a specific point. In this exercise, we are interested in the absolute pressure 7.10 cm below the interface of mercury and ethyl alcohol.
To find absolute pressure, you sum up three components:
  • Atmospheric pressure, which is about 1 atmosphere at the top of the liquid column.
  • Pressure from the column of ethyl alcohol above the measuring point, dependent on the height and density of the ethyl alcohol.
  • Pressure from the mercury column below the measuring point, dependent on the depth and density of mercury.
This combination gives you a complete picture of the forces exerting pressure at the measurement point.
Density
Density is a key concept in fluid dynamics and is defined as mass per unit volume. A liquid's density affects how it stacks up against other liquids, which determines its position in a multi-liquid system and significantly influences fluid pressure calculations.
For example, mercury is very dense with a value of 13.6 g/cm³. That's why it stays at the bottom, supporting heavier pressure at greater depths. On the other hand, ethyl alcohol, with a density of just 0.789 g/cm³, occupies the top layer in our exercise. The different densities of these liquids drive how the pressures are distributed and added together in this scenario.
Gravitational Acceleration
Gravitational acceleration is a crucial factor in calculating the pressure within a fluid. It represents the acceleration due to the force of gravity on Earth and is typically about 980 cm/s².
When calculating pressure in a fluid column, the formula involves multiplying the fluid's density, height, and gravitational acceleration. In our exercise, gravitational acceleration helps us determine how much pressure is exerted by both the ethyl alcohol column and the mercury below the specific measurement point.
This constant multiplier reinforces how pressure for any given depth depends not only on the fluid's material (or density) but also on how deeply it extends into a gravitational field.

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Most popular questions from this chapter

A patient recovering from surgery is being given fluid intravenously. The fluid has a density of \(1030 \mathrm{kg} / \mathrm{m}^{3},\) and \(9.5 \times 10^{-4} \mathrm{m}^{3}\) of it flows into the patient every six hours. Find the mass flow rate in \(\mathrm{kg} / \mathrm{s}\).

In the human body, blood vessels can dilate, or increase their radii, in response to various stimuli, so that the volume flow rate of the blood increases. Assume that the pressure at either end of a blood vessel, the length of the vessel, and the viscosity of the blood remain the same, and determine the factor \(R_{\text {dilated }} / R_{\text {normal }}\) by which the radius of a vessel must change in order to double the volume flow rate of the blood through the vessel.

A ship is floating on a lake. Its hold is the interior space beneath its deck; the hold is empty and is open to the atmosphere. The hull has a hole in it, which is below the water line, so water leaks into the hold. The effective area of the hole is \(8.0 \times 10^{-3} \mathrm{m}^{2}\) and is located \(2.0\) \(\mathrm{m}\) beneath the surface of the lake. What volume of water per second leaks into the ship?

An aneurysm is an abnormal enlargement of a blood vessel such as the aorta. Because of the aneurysm, the normal cross-sectional area \(A_{1}\) of the aorta increases to a value of \(A_{2}=1.7 A_{1} .\) The speed of the blood \(\left(\rho=1060 \mathrm{kg} / \mathrm{m}^{3}\right)\) through a normal portion of the aorta is \(v_{1}=0.40 \mathrm{m} / \mathrm{s}\) Assuming that the aorta is horizontal (the person is lying down), determine the amount by which the pressure \(P_{2}\) in the enlarged region exceeds the pressure \(P_{1}\) in the normal region.

The aorta carries blood away from the heart at a speed of about \(40 \mathrm{cm} / \mathrm{s}\) and has a radius of approximately \(1.1\) \(\mathrm{cm} .\) The aorta branches eventually into a large number of tiny capillaries that distribute the blood to the various body organs. In a capillary, the blood speed is approximately \(0.07 \mathrm{cm} / \mathrm{s},\) and the radius is about \(6 \times 10^{-4} \mathrm{cm} .\) Treat the blood as an incompressible fluid, and use these data to determine the approximate number of capillaries in the human body.

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