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Water flows straight down from an open faucet. The cross-sectional area of the faucet is \(1.8 \times 10^{-4} \mathrm{m}^{2},\) and the speed of the water is \(0.85 \mathrm{m} / \mathrm{s}\) as it leaves the faucet. Ignoring air resistance, find the cross-sectional area of the water stream at a point \(0.10 \mathrm{m}\) below the faucet.

Short Answer

Expert verified
The cross-sectional area of the water stream at 0.10 m below the faucet is approximately \(1.6 \times 10^{-4} \ \mathrm{m^2} \).

Step by step solution

01

Identify Known Values

The cross-sectional area of the faucet, \( A_1 = 1.8 \times 10^{-4} \ \mathrm{m^2} \), and the speed of the water at the faucet, \( v_1 = 0.85 \, \mathrm{m/s} \). The distance below the faucet is \( 0.10 \, \mathrm{m} \).
02

Apply Torricelli's Law for Velocity

As the water falls, it accelerates due to gravity. Use Torricelli's law to find the speed, \( v_2 \), of the water at \( 0.10 \, \mathrm{m} \) below: \( v_2 = \sqrt{v_1^2 + 2gh} \), where \( g = 9.81 \, \mathrm{m/s^2} \) and \( h = 0.10 \, \mathrm{m} \).
03

Calculate the New Speed

Substitute the values into Torricelli's law: \[ v_2 = \sqrt{(0.85)^2 + 2 \times 9.81 \times 0.10} \]Simplify the expressions to solve for \( v_2 \).
04

Use Continuity Equation

The continuity equation states that the product of the cross-sectional area and velocity of a fluid flow is constant, i.e., \( A_1 v_1 = A_2 v_2 \). Use this equation to solve for the unknown cross-sectional area \( A_2 \).
05

Solve for New Area

Rearrange the continuity equation to find \( A_2 \): \[ A_2 = \frac{A_1 v_1}{v_2} \]Substitute the known values of \( A_1, v_1 \), and the calculated \( v_2 \) to find \( A_2 \).
06

Perform Final Calculations

Complete the calculation with the actual numerical values to find the value of \( A_2 \). Verify your unit conversions and ensure your numerical answers remain consistent with the given physical dimensions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torricelli's Law
Torricelli's Law helps us calculate the speed of a fluid in motion due to gravity—a fundamental principle in fluid dynamics. When water flows from a faucet, it accelerates downward, akin to a falling object under gravitational influence. This acceleration increases its speed the further it falls. Torricelli's Law is expressed as:\[ v_2 = \sqrt{v_1^2 + 2gh} \]Where:
  • \( v_2 \) is the speed at a certain depth
  • \( v_1 \) is the initial speed
  • \( g \) is the acceleration due to gravity (\( 9.81 \, \mathrm{m/s^2} \))
  • \( h \) is the height from which the water falls
This law helps us find out how fast the water will be moving at a point below the starting point. By plugging in the values, we find the speed at this new point, which is necessary information for understanding changes in fluid behavior over distance.
Continuity Equation
The Continuity Equation is a key concept in fluid dynamics that ensures mass conservation in fluid flow. It states that the product of the cross-sectional area (\( A \)) and velocity (\( v \)) is constant along a streamline. Mathematically, it can be expressed as:\[ A_1 v_1 = A_2 v_2 \]This means that if the area narrows, the fluid must flow faster to maintain the same rate, and vice versa. It's like ensuring that what's coming out matches what went in.For the exercise, this equation allows us to find the new cross-sectional area at a certain point below the faucet. By using the initial known area and speed at the faucet along with the newly calculated speed from Torricelli's Law, we can solve for the unknown cross-sectional area (\( A_2 \)) downstream. This consistency is important in many engineering and scientific calculations, ensuring that fluid behaves predictably in various systems.
Cross-sectional Area
The cross-sectional area of a fluid stream is crucial in determining how fluids behave as they move. Think of it as the size of the slice of the stream that perpendicular cuts through the flow. As the water falls from the faucet, its speed increases, and thus the cross-sectional area changes to conserve volume flow rate as explained by the Continuity Equation. At the beginning, the area is larger because the speed is slower. As the stream falls and accelerates, the area becomes smaller. The practical implication of this is noticeable when you turn on a water faucet. At the mouth of the faucet, where the speed is slow, the stream appears wide. As it falls and speeds up, the stream narrows. Calculating the new cross-sectional area involves using the known area and speeds from above, allowing you to find where else the water might go or how fast it has to flow to maintain balance in the system. This concept ensures proper engineering design and helps in problem-solving when dealing with fluid flows.

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Most popular questions from this chapter

Neutron stars consist only of neutrons and have unbelievably high densities. A typical mass and radius for a neutron star might be \(2.7 \times 10^{28}\) \(\mathrm{kg}\) and \(1.2 \times 10^{3}\) \(\mathrm{m} .\) (a) Find the density of such a star. (b) If a dime \(\left(V=2.0 \times 10^{-7} \mathrm{m}^{3}\right)\) were made from this material, how much would it weigh (in pounds)?

A hydrometer is a device used to measure the density of a liquid. It is a cylindrical tube weighted at one end, so that it floats with the heavier end downward. The tube is contained inside a large "medicine dropper," into which the liquid is drawn using the squeeze bulb (see the drawing). For use with your car, marks are put on the tube so that the level at which it floats indicates whether the liquid is battery acid (more dense) or antifreeze (less dense). The hydrometer has a weight of \(W=5.88 \times 10^{-2} \mathrm{N}\) and a crosssectional area of \(A=7.85 \times 10^{-5} \mathrm{m}^{2} .\) How far from the bottom of the tube should the mark be put that denotes (a) battery acid \(\left(\rho=1280 \mathrm{kg} / \mathrm{m}^{3}\right)\) and \((\mathrm{b})\) antifreeze \(\left(\rho=1073 \mathrm{kg} / \mathrm{m}^{3}\right) ?\)

In the human body, blood vessels can dilate, or increase their radii, in response to various stimuli, so that the volume flow rate of the blood increases. Assume that the pressure at either end of a blood vessel, the length of the vessel, and the viscosity of the blood remain the same, and determine the factor \(R_{\text {dilated }} / R_{\text {normal }}\) by which the radius of a vessel must change in order to double the volume flow rate of the blood through the vessel.

The drawing shows a hydraulic system used with disc brakes. The force \(\overrightarrow{\mathbf{F}}\) is applied perpendicularly to the brake pedal. The pedal rotates about the axis shown in the drawing and causes a force to be applied perpendicularly to the input piston (radius \(\left.=9.50 \times 10^{-3} \mathrm{m}\right)\) in the master cylinder. The resulting pressure is transmitted by the brake fluid to the output plungers (radii \(\left.=1.90 \times 10^{-2} \mathrm{m}\right)\), which are covered with the brake linings. The linings are pressed against both sides of a disc attached to the rotating wheel. Suppose that the magnitude of \(\overrightarrow{\mathbf{F}}\) is \(9.00\) \(\mathrm{N}\). Assume that the input piston and the output plungers are at the same vertical level, and find the force applied to each side of the rotating disc.

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