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A hollow cubical box is \(0.30\) \(\mathrm{m}\) on an edge. This box is floating in a lake with one-third of its height beneath the surface. The walls of the box have a negligible thickness. Water from a hose is poured into the open top of the box. What is the depth of the water in the box just at the instant that water from the lake begins to pour into the box from the lake?

Short Answer

Expert verified
The depth of the water in the box is 0.10 meters.

Step by step solution

01

Understand the Problem

The problem states that a hollow cubical box is floating in water with one-third of its height submerged. When water is poured into the box until the water level inside matches the outside, water from the lake will start flowing in. Our task is to find the depth of water in the box at that moment.
02

Determine Submerged Height

The box is a cube with an edge of 0.30 meters. Since one-third of its height is submerged, the submerged height, \( h_{submerged} \), is \((1/3) \times 0.30 \mathrm{m} = 0.10 \mathrm{m}\).
03

Relate Submerged Volume to Displacement

The volume of water displaced (which is equal to the submerged volume of the box) is responsible for buoyancy. This displaced volume is \( 0.10 \times 0.30 \times 0.30 = 0.009 \mathrm{m}^3 \).
04

Calculate the New Submerged Height

When water is poured in until it starts to pour into the box from the lake, the submerged volume equals the internal water volume. This additional volume equals \( 0.30 \times 0.30 \times d = 0.009 \mathrm{m}^3 \), where \( d \) is the new submerged depth.
05

Solve for Depth Inside the Box

Setting the internal water volume equal to the displaced volume, we solve: \( 0.09 = 0.09d \), thus \( d = 0.10 \mathrm{m} \). Therefore, just as water from the lake starts entering the box, the depth of water inside is \(0.10 \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Mechanics
Fluid mechanics is the branch of physics that studies the behavior of fluids (liquids and gases) and the forces acting upon them. Understanding fluid mechanics is essential to solve problems involving floating objects, like our hollow cubical box. When the box is floating in the lake, it interacts with the water around it. The water exerts an upward force on the box called the buoyant force. At the same time, gravity pulls the box downward. These two forces need to balance each other for the box to float stably without sinking or rising. Fluid mechanics helps us analyze and predict how fluids move and the forces they exert. It guides us to calculate whether an object will float or sink under specific conditions, like when water is added to the box in our scenario.
Archimedes' Principle
Archimedes' Principle is a fundamental principle in fluid mechanics. It states that any object fully or partially submerged in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. In simple terms, the principle explains why things float. For our cubical box, one-third of its height is beneath the water surface. According to Archimedes' Principle, the box displaces an amount of water with a weight equal to the weight of the box. This balance of forces allows the box to float. When water is poured into the box, the total displaced volume must rise to match the weight of the box plus the additional water. This is why when the internal water depth reaches a certain level, it leads to a new equilibrium between displaced volume and gravitational force.
Displacement Volume
Displacement volume has a crucial role in floating objects and is directly tied to buoyancy. It refers to the volume of the fluid that is moved out of its original place when an object is submerged.For our cube, the initially displaced volume is \[0.10 imes 0.30 imes 0.30 = 0.009 \, \text{m}^3\] This is the volume of water equal to one-third of the cube's submerged height, explaining why it floats partially. As more water is added inside, the interior water increases displacement.When enough water is added to match the outside water level, the internal and external displaced volumes equate. This means the water depth in the box becomes equal to the submerged depth of the box, reaching 0.10 m. When displacement volume inside equals that of the outside, forces balance and water starts to flow in from the lake.

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