/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 A monkey is chained to a stake i... [FREE SOLUTION] | 91Ó°ÊÓ

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A monkey is chained to a stake in the ground. The stake is \(3.00 \mathrm{m}\) from a vertical pole, and the chain is \(3.40 \mathrm{m}\) long. How high can the monkey climb up the pole?

Short Answer

Expert verified
The monkey can climb 1.6 meters up the pole.

Step by step solution

01

Understand the Problem

The monkey is tied to a chain that is anchored to a stake, which is a certain distance from a pole that the monkey wants to climb. The goal is to determine how high up the pole the monkey can climb, considering the chain's length.
02

Visualize the Scenario

Envision the problem as a right triangle. The length from the stake to the pole is one leg of the triangle, the height the monkey can climb is the other leg, and the chain forms the hypotenuse of the triangle.
03

Set Up the Right Triangle Equation

According to the Pythagorean theorem, for a right triangle with legs of lengths \(a\) and \(b\), and hypotenuse \(c\), we have the equation: \[ a^2 + b^2 = c^2 \] In this context, \(a = 3.00\) meters (distance from stake to pole), \(b\) is the height the monkey can climb, and \(c = 3.40\) meters (length of the chain).
04

Substitute Values into the Equation

Substituting the known values into the Pythagorean theorem: \[ 3.00^2 + h^2 = 3.40^2 \]
05

Solve for the Height

Calculate the squares of the lengths:\[ 9.00 + h^2 = 11.56 \]Subtract 9 from both sides:\[ h^2 = 11.56 - 9.00 = 2.56 \]Take the square root of both sides to solve for \(h\):\[ h = \sqrt{2.56} = 1.6 \] meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Right Triangle
In this exercise, we're considering a monkey, a chain, and a vertical pole forming a right triangle. A right triangle is a special type of triangle with one angle measuring exactly 90 degrees. This allows us to apply the Pythagorean theorem, a key mathematical principle for calculating distances.

A right triangle consists of three sides:
  • The hypotenuse, which is the longest side and opposite the right angle.
  • Two shorter sides, or legs, which meet at the right angle.
In our scenario, the chain is the hypotenuse, the pole is vertical forming one leg, and the distance on the ground from the stake to the pole forms the other leg. Understanding this setup is crucial for applying the theorem to find out how high the monkey can climb.
Exploring Chain Length
The concept of chain length is essential in solving this problem. The chain represents the hypotenuse of the triangle and is given as 3.40 meters.

This length is pivotal because, in the triangle, it dictates how far the monkey can reach. The chain is fixed at one end to the stake, and the other end is free for the monkey. Thus, determining the permissible height, known as the other leg, becomes a matter of figuring out which combination of height and distance meets the entire chain's length. This entire calculation revolves around understanding how to balance these sides within the constraints that are given. This setup refers to the classic geometric rule where the combined squares of the two legs equal the square of the hypotenuse.
Accurate Distance Calculation
Distance calculation in this problem involves using the Pythagorean theorem. The core formula for this theorem is:
  • \[ a^2 + b^2 = c^2 \]
Where:
  • \(a\) is one leg, the fixed distance from the stake to the pole, which is 3.00 meters.
  • \(b\) is the unknown leg, the vertical height on the pole that the monkey can climb.
  • \(c\) is the length of the chain, which is 3.40 meters.
By substituting these numbers into the equation, we calculate the potential height \(h\) (equivalent to \(b\)) the monkey can climb.

This involves solving for \(h\) through basic algebra steps:
  • Substituting known values into the equation results in \(3.00^2 + h^2 = 3.40^2\).
  • Solving for \(h\) involves finding the difference between the square of the hypotenuse and the square of the known leg.
  • Lastly, taking the square root provides the vertical height: \(h = \sqrt{2.56} = 1.6\) meters.
This calculation shows the importance of accurate measurements to decide the monkey's climbing range.
Calculating Height Determination
Height determination is the ultimate goal here. It involves applying the previous concepts of right triangle geometry and chain length. The aim is to conclude how high the monkey can ascend the pole. Beginning with the formula:
  • \[ h^2 = c^2 - a^2 \]
We previously computed:
  • \(c^2 = 3.40^2 = 11.56\)
  • \(a^2 = 3.00^2 = 9.00\)
  • Therefore, \(h^2 = 11.56 - 9.00 = 2.56\)
Taking the square root yields the height \(h = \sqrt{2.56} = 1.6\) meters.

Through this straightforward calculation, based on the Pythagorean theorem, we show that understanding and applying mathematical principles can lead to practical solutions, like determining reachable heights in real-life situations.

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Most popular questions from this chapter

Bicyclists in the Tour de France reach speeds of 34.0 miles per hour \((\mathrm{mi} / \mathrm{h})\) on flat sections of the road. What is this speed in (a) kilometers per hour \((\mathrm{km} / \mathrm{h})\) and \((\mathrm{b})\) meters per second \((\mathrm{m} / \mathrm{s}) ?\)

Vector \(\overrightarrow{\mathbf{A}}\) has a magnitude of 6.00 units and points due east. Vector \(\overrightarrow{\mathbf{B}}\) points due north. (a) What is the magnitude of \(\overrightarrow{\mathbf{B}},\) if the vector \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) points \(60.0^{\circ}\) north of east? (b) Find the magnitude of \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\).

Mmh Vector A has a magnitude of 145 units and points 35.0 " north of west. Vector \(\overrightarrow{\mathbf{B}}\) points \(65.0^{\circ}\) east of north. Vector \(\overrightarrow{\mathbf{C}}\) points \(15.0^{\circ}\) west of south. These three vectors add to give a resultant vector that is zero. Using components, find the magnitudes of (a) vector \(\overrightarrow{\mathbf{B}}\) and (b) vector \(\overrightarrow{\mathbf{C}}\).

Consult Multiple-Concept Example 9 in preparation for this problem. A golfer, putting on a green, requires three strokes to "hole the ball." During the first putt, the ball rolls \(5.0 \mathrm{m}\) due east. For the second putt, the ball travels \(2.1 \mathrm{m}\) at an angle of \(20.0^{\circ}\) north of east. The third putt is \(0.50 \mathrm{m}\) due north. What displacement (magnitude and direction relative to due east) would have been needed to "hole the ball" on the very first putt?

The corners of a square lie on a circle of diameter D = 0.35 m. Each side of the square has a length L. Find L.

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